similar to: Mean of matrices entries in list of lists

Hello, i only got a small problem. i try to create automatic new dataframes, or png?s. the main problem i got is: how can i create automatic a new name for a file (read out by simply "for") - i tried to use "(paste...) but theres an errormessage, about a wrong declination. R told it is as.character, but need as.Real. Should i use another method than "paste"? i tried as

From: Hervé Poussineau <hpoussin@reactos.org> Signed-off-by: Hervé Poussineau <hpoussin@reactos.org> Signed-off-by: Andreas Färber <afaerber@suse.de> --- hw/xen_platform.c | 21 ++++++++++----------- 1 Datei geändert, 10 Zeilen hinzugefügt(+), 11 Zeilen entfernt(-) diff --git a/hw/xen_platform.c b/hw/xen_platform.c index ca66047..8866468 100644 --- a/hw/xen_platform.c +++

I am looking for a way to get a warning message immediately after an evaluation within a function. To get error messages you can use geterrmessage(). But I found no function that allows me to check for warnings. Five years ago this questions has been posted but I haven't found any answer. Thanks for any help. Peter Wolf ------------ For illustration purpose a simple example follows: you

Dear all, I am new R user and I am sure that this question has been asked quite often and I have also googled it and read about it! I understood that in order to read excel sheet into R you need to open it and saved it as csv or text, is this true? or you can use read.delim2 and read.csv2 to do this without the following error > dat <- read.csv2(file="C:\\Dokumente und

I am working with some large text files (up to 16 GBytes). I am interested in extracting the words and counting each time each word appears in the text. I have written a very simple R program by following some suggestions and examples I found online. If my input file is 1 GByte, I see that R uses up to 11 GBytes of memory when executing the program on a 64-bit system running CentOS 6.3. Why is

hello could you help in solving the following problem I want to replace same consecutive words by a single word in a sentence.. for example --- my name name name is micky so I want the output like this--my name is micky I want this solution for a text file can you tell me the code for it?? thanking you in anticipation -- Shilpa Rai MSc.(2011-2013) Applied Statistics and Informatics Indian

Dear All,   I have the following code set up:   x <-2000 y <-8 z <-3   I would need to use these numbers to show up in my plot title "mixed" with text. The x,y,z numbers would need to change, the text would not. So my title should look like this   "x txt1 y txt2 z txt3"   so if: txt1=hours txt2=minutes txt3=seconds   then my title of the plot should read:   2000 hours

Buenas tardes, grupo. Estoy tratando de hacer la comparación de dos archivos de una misma organización para encontrar las diferencias entre su informe del tema edl año 2005 y el del año 2013: Todos los comandos van bien, a exepción del último "colnames", como se ve en la siguiente secuencia: > pdf1<-"./PLAN de INSPECCIONES/05_seguridad_ciudadana.pdf" >

hi, I have a file in a samba share with the following attributes: [dir1002] comment = webmin share write list = usr1,usr2 path = /misc/removable/dir1002 read only = no The files are created with the following ownership(the file system is vfat): -rwxr-xr-x 1 root root 0 Feb 14 07:23 New Text Document.txt -rwxr-xr-x 1 root root 4 Feb 14 07:28 txt1.txt

Dear R users, A co-worker and I are writing a function to facilitate graph plotting in R. The function makes use of a lot of lists in its defaults. However, we discovered that R does not necessarily preserve the defaults if we were to input them in the form of list() when initializing the function. For example, if you feed the function codes below into R: myfunction=function( list1=list

I'd like to do some plots of historical event data on a reverse log scale, started, say at the year 2000 and going backwards in time, with tick marks spaced according to log(2000-year). For example, see: http://euclid.psych.yorku.ca/SCS/Gallery/images/log-timeline.gif As an example, I'd like to create a density plot of such data with the horizontal axis reverse-logged, a

Hi R users: I got this code to generate a graphic for each member of a lists. list1<-list(A=data.frame(x=c(1,2),y=c(5,6)),B=data.frame(x=c(8,9),y=c(12,6))) names1<-names(list1) sapply(1:length(list1),function(i) with(list1[[i]],plot(x,y,type="l",main=paste("Graphic of",names1[i])))) Is there a more elegant solution for not to use two separate lists? I would like to

Hi all... I?m making a chart dealing with frequencies of isotopes of various elements. For instance, I'd like the following text to appear on a chart with the "35" and "37" as superscripts: Based upon: 35Cl: 75% 37Cl: 25% I am having problems properly parsing the superscript that preceeds the "Cl", since there is no character ahead of the superscript (I saw

Hi, I have 22 files (A1, A2, ..., A22) with different number of columns, totaling 10,000 columns: c1, c2, c3, ..., c10000 I have another file with a list of 100 columns that I need to extract. These 100 columns are distributed in 22 files. How to extract the 100 columns of the 22 files? I have done it "manually" with the following commands, for example: cromo1 = read.table ("~

Hi, I have 2 questions on list object:   1. Suppose I have a matrix like: dat <- matrix(1:9,3)   Now I want to replicate this entire matrix 3 times and put entire result in a list object. Means, if "res" is the resulting list then I should have:   res[[1]]=dat, res[[2]]=dat, res[[3]]=dat   How can I do that in the easilest manner?   2. Suppose I have 2 list objects: list1 <- list2

Hi, Algorithm question: I have two sets of "intervals", where an interval is an ordered pair [a,b] of two numbers. Is there an efficient way in R to generate the intersection of two lists of same? For concreteness: I'm representing a set of intervals with a data.frame: > list1 = as.data.frame(list(open=c(1,5), close=c(2,10))) > list1 open close 1 1 2 2 5

>From the Details section of ?capture.output: Messages sent to stderr() (including those from message, warning and stop) are captured by type = "message". Note that this can be "unsafe" and should only be used with care. Capturing messages works as expected: capture.output(message("!!!"), type = "message") ## [1] "!!!" Capturing warnings

Hi, This has bugged me for a bit. First question is how to keep classes with rbind, and second question is how to properly return vecotrs instead of lists after turning an rbind of lists into a data.frame list1=list(a=2, b=as.Date("20090102", format="%Y%m%d")) list2=list(a=2, b=as.Date("20090102", format="%Y%m%d")) rbind(list1, list2) #this loses the

Hello R-Helpers, I have a slight problem with the expresion data[data==""] <- NA which works well for a data.frame. But now i must use the same for a list of data.frames. My idea is data[[]][data==""] but it don´t work. Thanks!! Dominic [[alternative HTML version deleted]]

HI Eliza, You could do this: set.seed(15) mat1<-matrix(sample(1:800,124*12,replace=TRUE),nrow=12) # smaller dataset #Your codes ?list1<-list() ?for(i in 1:ncol(mat1)){ ? list1[[i]]<-t(apply(mat1,1,function(x) x[i]-x)) ? list1} ?x<-list1?? x<-matrix(unlist(x),nrow=12) x<-abs(x) ?y<-colSums(x, na.rm=FALSE) z<-matrix(y,ncol=10) ?z<-as.dist(z) ?z ?# ?? 1?? 2?? 3?? 4?? 5??