Displaying 20 results from an estimated 80 matches similar to: "Error message in nmkb()"
2012 Nov 04
1
Struggeling with nlminb...
Hallo together,
I am trying to estimate parameters by means of QMLE using the nlminb
optimizer for a tree-structured GARCH model. I face two problems.
First, the optimizer returns error[8] false convergence if I estimate the
functions below. I have estimated the model at first with nlm without any
problems, but then I needed to add some constraints so i choose nlminb.
2011 Nov 10
3
optim seems to be finding a local minimum
Hello!
I am trying to create an R optimization routine for a task that's
currently being done using Excel (lots of tables, formulas, and
Solver).
However, otpim seems to be finding a local minimum.
Example data, functions, and comparison with the solution found in
Excel are below.
I am not experienced in optimizations so thanks a lot for your advice!
Dimitri
### 2 Inputs:
2016 Oct 08
4
optim(…, method=‘L-BFGS-B’) stops with an error message while violating the lower bound
Hello:
The development version of Ecdat on R-Forge contains a vignette
in which optim(?, method=?L-BFGS-B?) stops with an error message while
violating the lower bound.
To see all the details, try the following:
install.packages("Ecdat", repos="http://R-Forge.R-project.org")
Then do "help(pac=Ecdat)" -> "User guides, package
2020 Oct 28
2
R optim() function
Hi R-Help,
I am using R to do functional outlier detection (using PCA to reduce to 2 dimensions - the functional boxplot methodology used in the Rainbow package), and using Hscv.diag function to calculate the bandwidth matrix where this line of code is run:
result <- optim(diag(Hstart), scv.mat.temp, method = "Nelder-Mead", control = list(trace = as.numeric(verbose)))
Within the
2017 Aug 06
1
Help with optim function in R, please?
Hi all,
Many thank in advance for helping me.? I tried to fit Expectation Maximization algorithm for mixture data. I must used one of numerical method to maximize my function.
I built my code but I do not know how to make the optim function run over a different value of the parameters.? That is,
For E-step I need to get the value of mixture weights based on the current (initial) values of
2011 Dec 18
2
Dealing with NAs
Hi
I am trying to estimate parameter values with mlogit. I attach a part of my data.
My code is
x=mlogit.data(y,choice="voittaja",shape="long",id.var="id",alt.var="numero")
summary(mlogit(voittaja ~ Ie-1 , data=x, na.action=na.pass))
But i get
Error in if (abs(x - oldx) < ftol) { :
missing value where TRUE/FALSE needed
Because there is Na
2012 Oct 18
3
Upper limit in nlsLM not working as expected
Dear all,
I am using the nlsLM function to fit a Lorentzian function to my experimental data.
The LM algorithm should allow to specify limits, but the upper limit appears not to work as expected in my code.
The parameter 'w', which is peak width at half maximuim always hits the upper limit if the limit is specified. I would expect the value to be in-between the upper and lower limit with
2011 Dec 19
1
Mlogit missing value problem
Hi
After good advices i post this problem here again. Now the attached sambledata is in csv form and it is a part of my real data. I have tried different na.action operations but the result stays the same...
My code
> library(mlogit)
> library(foreign)
> z<-odbcConnectExcel("D:\\SAMBLEDATA.csv")
> y<-sqlFetch(z,"Taul1")
>
2013 Mar 19
0
mlogit: block design CE model
Hi,
I am trying to use mlogit in R to analyse a block design choice experiment
dataset. The 12 choice sets/cards have been randomly assigned to 3
different blocks and each respondent answers all sets from one block (i.e.
each respondent chooses from 4 choice sets). In total I have 2336 rows of
data from 292 respondents. The data looks like this (2 of the three
blocks):
ID Sex Age Block Card
2006 Sep 22
2
inequality with NA
Dear everybody!
take a<-c(5,3,NA,6).
if(a[1]!=NA){b<-7}
if(a[3]!=5){b<-7}
if(a[3]!=NA){b<-7}
if(a[3]==NA){b<-7}
will alltogeather return
Fehler in if (a[1] != NA) { : Fehlender Wert, wo TRUE/FALSE n?tig ist
(or simularly). Somehow this is logical. But how else should I get out,
whether a certain vector-component has an existing value?
Thank you in advance!
Yours,
Mag. Ferri
2012 Oct 20
2
can't find the error in if function... maybe i'm blind?
Hi everybody,
the following alway gives me the error
"Fehler in if (File$X.Frame.Number[a] + 1 == File$X.Frame.Number[a + 1])
(File$FishNr[a] <- File$FishNr[a - : Fehlender Wert, wo TRUE/FALSE n?tig
ist". Maybe its stupid, but i'm not getting why... Maybe someone can help
me. Thanks a lot!
for (i in unique(BigFile$TrackAll))
{ File <-
2008 Aug 13
2
Tiny help for tiny function
I just started to write tiny functions and therefore I appologise in advance
if I am asking stupid question.
I wrote a tiny function to give me back from the original matrix, a matrix
showing only the values smaller -0.8 and bigger 0.8.
y<-c(0.1,0.2,0.3,-0.8,-0.4,0.9)
x<-c(0.5,0.3,0.9,-0.9,-0.7,0.3)
XY<-rbind(x,y)
extract.values<-function (x)
{
if(x>=0.8|x<=-0.8)x
2006 May 16
1
survival package - pspline
help
Hello,
I?m a statistic student in Austria and I have to do a survival analysis in R
by using psplines as regressor. My problem is that I sometimes (I think it
depends on the choose of the parameters) get a error message, but I do not
know what it means. After that I tried the procedure with an example dataset
R is providing. Although using the cancer dataset I also get this message.
Input:
2010 Oct 03
1
Modifying a data.frame
Hello list members
I have a problem with modifying a data.frame.
As an example given is a data.frame called ex :
ex<-data.frame(id=c(1,2,3,4,5,6),obs=c(14,9,20,36,55,47),eff=c("A","A","B","C","C","C"))
After that I would like to modify the object ex with the following short script:
for (i in ex) {
if(ex[i,3]=="A"||
2010 Feb 01
3
playwith error message
Hi,
I'am using the playwith library to write my own small GUI application.
But I get the following error under Windows and Linux (Ubuntu):
Error in if ((modeOK %in% c("Identify", "Brush")) && (actions$ident == :
Fehlender Wert, wo TRUE/FALSE n?tig ist
Under linux my R program simply continues, but under Windows it stops.
Since it is not in my code, has anyone
2012 Aug 24
1
Fwd: Re: Package cwhmisc and problems
-------- Original-Nachricht --------
Betreff: Re: Package cwhmisc and problems
Datum: Fri, 24 Aug 2012 07:34:14 +0100
Von: Prof Brian Ripley <ripley@stats.ox.ac.uk>
An: Christian Hoffmann <c-w.hoffmann@sunrise.ch>
Kopie (CC): CRAN@r-project.org
This is the address for CRAN submissions. Please ask for help on R-help
or R-devel.
On 23/08/2012 20:16, Christian Hoffmann wrote:
2008 Mar 22
2
intraday OHLC plot
I want to create a open/high/low/last plot of intraday data.
I try to use the function plotOHLC from the tsteries package. I create
my own multiple time series and then try to plot it.
raw Data Format (file eurusd2.csv):
"Date (GMT)" "Open" "High" "Low" "Last"
17-03-2008 00:00:00 1,5764 1,5766 1,5747 1,5750
17-03-2008 00:05:00 1,5749 1,5750 1,5741
2009 Jan 07
1
troubles performing Moran.I test
dear R users,
I have troubles performing Moran.I test as suggested on
http://www.ats.ucla.edu/stat/r/faq/morans_i.htm
my spatial data are longitude and lattitide of communities. The
calculation of the inverse distance matrix according to the homepage
(using my data)
datAL <- read.csv2("C:\\Konvergenz AL.csv", header=T)
ALdist <- as.matrix(dist(cbind(datAL$L?nge,
2013 Mar 30
1
normal mixture EM not working?
Hi,
I am currently working on fitting a mixture density to financial data.
I have the following data:
http://s000.tinyupload.com/?file_id=00083355432555420222
I want to fit a mixture density of two normal distributions.
I have the formula:
f(l)=πϕ(l;μ1,σ21)+(1−π)ϕ(l;μ2,σ22)
my R code is:
normalmix<-normalmixEM(dat,k=2,fast=TRUE)
pi<-normalmix$lambda[1]
mu1<-normalmix$mu[1]
2012 Sep 16
1
trying to obtain same nls parameters as in example
Dear R-users;
I'm working with a a dataset that was previously used to fit a
nonlinear model of the form:
Y ~ a * (1 + b * log(1 - c * X^d))
The parameters published elsewhere are:
a = 1.758863, b = .217217, c = .99031, and d = .054589
However, there is no way I can replicate this result. I've tried
several options (including SAS) w/o success.
The data is:
X <-