similar to: ffdfindexget from package ff

Dear list, I have a vector of numbers, let's say: myvec <- c(2, 8, 24, 26, 51, 57, 58, 78, 219) My task is to reduce this vector to non-reducible numbers; small numbers can cross-out some of the larger ones, based on a function let's say called reduce() If I apply the function to the first element 2, my vector gets shorted to: > (myvec <- reduce(myvec[1])) [1] 2 24 51

Hi all, I’ve narrowed down a problem in my code to the following test case: - - - - typedef struct {float v[2];} vec2; typedef struct {float v[3];} vec3; vec2 getVec2(); vec3 getVec3() { vec2 myVec = getVec2(); vec3 res; res.v[0] = myVec.v[0]; res.v[1] = myVec.v[1]; res.v[2] = 1; return res; } - - - - Compiling this with any level of optimization for arm64 gives incorrect code,

Dear R-users, I have two outliers related questions. I. I have a vector consisting of 69 values. mean = 0.00086 SD = 0.02152 The shape of EDA graphics (boxplots, density plots) is heavily distorted due to outliers. How to define the interval for outliers exception? Is <2SD - mean + 2SD> interval a correct approach? Or should I define 95% (or 99%) limit of agreement for data interval,

Dear experts, I try not to trouble the list again after this question. I want to print this vector into a file > myvec [1] --Control --Control --Control --Control --Control HBA2 HBA1 [8] HBA1 --Control HBB --Control HBB HBA1 MBP [15] --Control HBA1 HBA2 HBB PTGDS GAPDH UBC [22] --Control GAPDH TPT1 HUWE1 PRM1 CKM

Dear list, This should be a simple one, I just cannot see it. I need to generate a sequence of the form: 4 5 6 13 14 15 22 23 24 That is: starting with 4, make a 3 numbers sequence, jump 6, then another 3 and so on. I can create a whole vector with: myvec <- rep(rep(c(F, T, F), rep(3, 3)), 3) Then see which are TRUE: which(myvec) [1] 4 5 6 13 14 15 22 23 24 I'd like to avoid

This is my reproducible example tv.ms<-structure(list(inq = structure(4:17, .Label = c("D4", "D5", "D6a", "D6b", "D6c", "D7", "D8", "F4", "F5a", "F5b", "F6a", "F6b", "F6c", "F6d", "F7a", "F7b", "F8"), class =

List, Consider the following data. gender mygroup id 1 F A 1 2 F B 2 3 F B 2 4 F B 2 5 F C 2 6 F C 2 7 F C 2 8 F D 2 9 F D 2 10 F D 2 11 F D 2 12 F D 2 13 F D 2 14 M A 3 15 M A 3 16 M A 3 17

Hi R-users, To automate the creation of scripts, I converted the code (example below) into a character string and wrote the object to a file: Repeat <- " myvec <- c(1:12) cat('vector= ', myvec, '\n') " write (Repeat, 'yourpath/test.R') the problem is that one line of the code is a "cat" command. In the output file (i.e. test.R), the newline

Thanks Bruce. > On 4 May 2015, at 13:18, Bruce Hoult <bruce at hoult.org> wrote: > > I can confirm that, with Apple LLVM version 6.0 (clang-600.0.56) (based on LLVM 3.5svn) > > Very strange! Yes, that’s what I thought. I’ve also checked the binary downloads for OS X from llvm.org <http://llvm.org/> and get the same broken code from both the 3.5.2 and 3.6.0 releases.

This is a real newbie question. What makes it worse is that I know I've seen the answer somewhere, but I can no longer find it. If I have a loop that is supposed to generate a vector piecemeal, adding an element each time through the loop, what do I do to stop it failing the first time around the loop, when the vector doesn't yet exist (so I can't use the append() function)?

Hi there, is there a possibility to count the number of appearances of an element in a vector ? i mean of any given element.. deliver all elements which are exactly xtimes in this vector ? thx in advance !!

I am trying to print a nice looking vector in Sweave. c <- 1:4 I want to see (1, 2, 3, 4) in TeX. . If I use paste(c, ",", sep="") I get "1," "2," "3," "4," If use cat(c, sep=",") I can't seem to assign it to an object, 1,2,3,4> myvec <- cat(c, sep=",") 1,2,3,4> myvec NULL and if I bypass the

I am pretty new to R. So this may be an easy question for most of you. ? I would like to calculate the squared distances of a large set (let's say 20000) of vectors (let's say dimension of 5) to a fixed vector. ? Say I have a data frame MY_VECTORS with 20000 rows and 5 columns, and one 5x1 vector y. I would like to efficiently calculate the squared distances?between each of the 20000

Dear R-users, I have a plot created with the code below. I tried to put some text to the right of the color key. I worked with grid.text and also viewport(), but couldn't achieve this. I know this should be simple, but I just couldn't figure out how to do it. How does this work? Cheers, Marius library(lattice) library(grid) myvec=1:10 data=data.frame(x=myvec,y=myvec)

Dear All, I want to sort a character type vector. the vector is [1] 4 5 6 8 9 11 Y 1 13 15 16 20 X 2 3 10 14 19 XY 7 12 18 17 22 [25] 21 and I want to sort 1-22 X Y XY or 1-22 X XY Y. How can I do that? Thanks,

# I understand that a good way to build a vector from a sequence of integers, # is to use syntax like this: myvec = c(1:99) # Here is the 'short' version of my question: # I want to understand a 'good' way to build a matrix from a sequence of integers. # If that question is not clear, here is a longer version: # Here is what I did for a 1D-matrix: # I pick the sequence 1:3 # I

Attached is a patch with suggestions for the R-lang manual at r64277. Below are a few comments (some are implemented in the patch): In the section "Objects", there is a table introduced by "The following table describes the possible values returned by typeof". One of the results is "any". Can "any" be returned by "typeof()" ? Regarding the

Dear list, I have a vector (array, table row, whatever is best) of frequency values for categories (or bins), and I need to find the median category. Trivial to do by hand, but I was wondering if there is a means to do it in R in an elegant way. The obvious medioan(vector) returns the median frequency for the binns, and that is not what I want. i.e,: freq cat1 1 cat2 10

Hi all, Is there a function to check if a particular value is contained in a vector? I've looked at grep in the hope that I could use a Perl-like syntax, but obviously it's different... I'd like to do something like: y <- c("a","b","c") if("a" in y) { # "a" is not in y } Also, is there a way to

Hi there, I have a vector and would like to create a data frame, which contains all unique combination of two elements, regardless of order. myVec <- c(1,2,3) what expand.grid does: 1,1 1,2 1,3 2,1 2,2 2,3 3,1 3,2 3,3 what I would like to have 1,1 1,2 1,3 2,2 2,3 3,3 Can anybody help?