similar to: Isomorphic matrices

Dear R users, i have this problem with matrices i want to check between two matrices if they are isomorphic i will give an example for what excactly i want   1 -1  1                                 -1  1   1 -1   1  -1                                1  -1  -1   1  1   -1                                1   1  -1 this two matrices are isomorphic beacause if i change the first 2 columns the matrices

Dear R users, I want a help to write an algorithm for swapping rows and columns in a matrix thanks in advance [[alternative HTML version deleted]]

I have 3003 16x5 submatrices from a hadamard matrice of 16x15. I want to write an algorithm that check all of these 3003 matrices if they are isomorphic and i want to find and keep the non-isomorphic ones. Any help will be welcome.  [[alternative HTML version deleted]]

Dear R users, I have an array that has matrices that i want BB[16,5,2:27] i want to put each of the 26 matrices into a List  thanks in advance [[alternative HTML version deleted]]

i have this problem with matrices i want to check between two matrices if they are isomorphic i will give an example for what excactly i want   1 -1  1                                 -1  1   1 -1   1  -1                                1  -1  -1   1  1   -1                                1   1  -1 this two matrices are isomorphic beacause if i change the first 2 columns the matrices are identical

Dear R users, I want to check matrices when i change the order of the rows or/and the order of the columns or/and the combination of them i will give an example what i want  1  -1  1  1      1  1   1  1 -1  -1 -1 -1    -1 -1  -1  -1   1  1    1  1     1 -1    1   1 these 2 matrices are identical because i change the first row and make it third   1  -1  1  1      -1  1   1  1 -1  -1 -1

Dear R users, I have this program aa<-array(rep(0,27),dim=c(3,3,3)) a<-matrix(rep(1,9),ncol=3) n<-0 for (i in 1:3) {            a[i,]<-a[i,]*(-1)       n<-n+1       aa[,,n]<-a[i,] } but i real want to multiply each row  with -1 according to for loop and after that to put it in the array.  I will give an example for what excaclty want -1 -1 -1  1  1  1  1  1  1 -1 -1 -1 -1

Dear R users, I have a Hadamard matrix 16x15 and i want to put 16x5 submatrices in an array put i have an error. > A1<-matrix(c(0,0,0,0,0,0,0,0,0,0,0,0,0,0,0, + 1,0,1,0,1,0,1,0,1,0,1,0,1,0,1, + 0,1,1,0,0,1,1,0,0,1,1,0,0,1,1, + 1,1,0,0,1,1,0,0,1,1,0,0,1,1,0, + 0,0,0,1,1,1,1,0,0,0,0,1,1,1,1, + 1,0,1,1,0,1,0,0,1,0,1,1,0,1,0, + 0,1,1,1,1,0,0,0,0,1,1,1,1,0,0, + 1,1,0,1,0,0,1,0,1,1,0,1,0,0,1, +

Dear R users, I have this problem with memory i guess  AA<-array(rep(0,96096000),dim=c(16,5,3003,400)) Error: cannot allocate vector of size 733.2 Mb can anyone help me,  Thanks in advance... [[alternative HTML version deleted]]

Hi I have some data with these dimensions: 5 3 100 which correspond to the x, y, and time dimensions, for a variable, p. I need the data in this format: 100 rows (1 row per time unit), and 15 values in each row. I have attempted to reshape my data >dim(data) 5 3 100 >attr(data,'dim')<-c(dim(data)[3],dim(data)[1]*dimdata[2]) So I get data with 100 rows, 15 columns. I need

Dear All, Sorry for the typoes earlier, let me repost the question. Suppose I want to generate sequences of length 3 from two symbols {1,2}, we get the following 8 sequences 1 1 1 1 1 2 1 2 1 1 2 2 2 1 1 2 1 2 2 2 1 2 2 2 However, I do not want all these 8 sequences. I call two sequencs to be isomorphic if one sequence could be obtained from the other by relabelling the symbols. For example,

Dear ExpRts, I would like to perform a function with two arguments over the rows of two matrices. There are a couple of *applys (including mApply in Hmisc) but I haven't found out how to do it straightforward. Applying to row indices works, but looks like a poor hack to me: sens <- function(test, gold) { if (any(gold==1)) { sum(test[which(gold==1)]/sum(which(gold==1))) } else NA }

Hi, I need to compare two matrices with each other. If you can get one of them out of the other one by resorting the rows and/or the columns, then both of them are equal, otherwise they're not. A matrix could look like this: [,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [1,] 0 1 1 1 0 1 1 0 [2,] 1 1 0 0 0 1 0 1 [3,] 1 0 1 0 0

This message contains a description of what looks like a bug, examples of the suspect behavior, a proposed change to the C code to change this behavior, example of behavior with the fix, and suggestions for 3 places to update the documentation to reflect the proposed behavior. It is submitted for consideration for inclusion in R. Comments are requested. Currently, the code for subscripting

I've put this in (with some different wording). Although S blithely accepts mis-dimensioned index matrices I agree this is wrong and have made it an error. On Fri, 29 Apr 2005 tplate@acm.org wrote: > This message contains a description of what looks like a bug, examples > of the suspect behavior, a proposed change to the C code to change this > behavior, example of behavior with

[Apologies to Gabor, who I sent a personal copy of the reply erroneously instead of posting to List directly] [...] > Perhaps what you really intend is to > take the average over those elements in each row of the first matrix which correspond to 1's in the second in the corresponding > row of the second. In that case its just: > > rowSums(newtest * goldstandard) /

I'm having trouble setting up the function call to handle two lists of matrices. Each list has 6 matrices - Each matrix is 20x10. I need to do some basic math on corresponding matrices in each list. Here are some outputs of these lists, etc... # first list > length(qc.pm) [1] 6 > dim(qc.pm[[1]]) [1] 20 10 > qc.pm[[1]][1:4,1:4] 441-JP071707.CEL 442-JP071707.CEL

Estimated people, I have two matrices: ar1 <- array(data=c(1:16),dim=c(4,4)) ar2 <- array(data=c(1,2,3,3,5:16),dim=c(4,4)) They only differ in the fourth row. I would like to compare them in order to know which columns are equal. The following works, but I would like to have a better solution, and not to use what someone called "prehistorical loops": for(i in

I've got a list of 5 matrices that are each 5 x 6. I'd like to end up with a 5 x 6 matrix that contains the mean value of the 5 original matrices. I can do this by brute force, but there must be a better way than making each matrix into a vector and then remaking a matrix thanks very much for any help david freedman ll=list(structure(c(9.7, 17.6, 20.8, 24.1, 33.8, 14.5, 25.7, 29.8,

i'm somehow embarrassed to even ask this, but is there any built-in method for doing this: my_list <- list() my_list[[1]] <- matrix(1:20, ncol = 5) my_list[[2]] <- matrix(20:1, ncol = 5) now, knowing that these matrices are identical in dimension, i'd like to unfold the list to a 2x4x5 (or some other permutation of the dim sizes) array. i know i can initialize the array, then