similar to: Gini with bias correction

Hi all, Could anybody tell me how to test for stationarity in time series? Thanks a lot! [[alternative HTML version deleted]]

Hi every one, Thanks for every one who are all supporting to us. we want some clarification on output in R. I have generated summary statistics output for dataset (E.g. sales) in output window. Now i want to store that output in a html or pdf in a table format. if possible can any one provide code for this one. Thanks in advance. -- View this message in context:

Hi listers, Does it necessary to install any package in order to use the GINI or INEQ functions. If I use the following command the R tells me that didn't find the GINI function. x<-c(541, 1463, 2445, 3438, 4437, 5401, 6392, 8304, 11904, 22261) G<-gini(x) Thanks in advance, Marcio -- View this message in context:

Hello, I would like to build a Lorenz curve and calculate a Gini coefficient in order to find how much parasites does the top 20% most infected hosts support. Here is my data set: Number of parasites per host: parasites = c(0,1,2,3,4,5,6,7,8,9,10) Number of hosts associated with each number of parasites given above: hosts = c(18,20,28,19,16,10,3,1,0,0,0) To represent the Lorenz curve: I

Hi there, I am trying to compute Gini coefficients for vectors containing income classes. The data I possess look loke this: yit <- c(135, 164, 234, 369) piit <- c(367, 884, 341, 74 ) where yit is the vector of income classes, and fit is the vector of associated frequencies.(This data is from Rustichini, Ichino and Checci (Journal of Public Economics, 1999) ). In ineq pacakge, Gini( )

If I use the Ineq library and the Gini function in this way: >Gini(c(100,0,0,0)) I obtain the result 0.75 instead of 1 (that is the perfect inequality). I think Gini's formula in Ineq is based on a formula as reported here: http://mathworld.wolfram.com/GiniCoefficient.html but in the case of perfect inequality: x_1=.......=x_n-1 =0 x_n>0 these formula are equal to 1 - 1/n, not to

I have written the following function to calculate the weighted mean difference for univariate data (see http://www.xycoon.com/gini_mean_difference.htm for a related formula). Unsurprisingly, the function is slow (compared to sd or mad) for long vectors. I wonder if there's a way to make the function faster, short of creating an external C function. Thanks very much for your advice. gmd

dear Researchers, i am looking for a function to plot a barplot for each mean value and the related standard deviation, and i can close my week. This is an example of my data set. really Thanks in advance for any help or suggestions Gianni My.mean <- data.frame(Mean=c(0.4108926,0.3949009,0.4520346, 0.4091665,0.4664066,0.3048296,0.4297226,0.4056383,

Dear all, I am working with randomForest package and I am interested in examining the "Gini importance" measures that are used as a general indicator of feature relevance. Is there a possibility of getting the Gini measure that is being estimated in each tree by the output of the getTree() function? Thanks a lot, Chrysanthi [[alternative HTML version deleted]]

Dear List, I am unsure if this is specifically a R question or a stats question? I thought i would ask here and if i get no replies it will answer that! I am trying to calculate Gini coefficients in R, based on a slight modification of the typical equation that i have seen in a paper. -------------- next part -------------- A non-text attachment was scrubbed... Name: PastedGraphic-2.pdf Type:

Hi does anyone know how to do a logistic regression in R? any help appreciated Carl -- View this message in context: http://r.789695.n4.nabble.com/Logistic-regression-tp4512658p4512658.html Sent from the R help mailing list archive at Nabble.com.

Hola, paso el mini programita q estoy viendo, lo q me llama la atencion es una parte donde se definen las funciones. Probe primero meter adentro del boots la estadistica a estimar usando directamente gini(varible, pesos) pero no me dejo. Vi q en el ej del manual de boots, siempre define antes la funcion, entonces probe definir antes una funcion haciendo grini<-function(x) {gini(variable,

Hi. I have some data from a survey w/c include income data. Was not quite sure how to generate the gini index on these data. Jose Ramon Albert Statistical Research and Training Center www.srtc.gov.ph -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-help mailing list -- Read http://www.ci.tuwien.ac.at/~hornik/R/R-FAQ.html Send "info",

Dear R-users, I'm working with the Rpart package and trying to understand how the procedure select the best split in the case the method "class" and the splitting index "Gini" are used. In particular I'd like to have look to the source code that works out the best split for un unordered predictor. Does anyone can suggest me which functions in the sources I should

Dear All, I have developed a programme the anable the decomposition of the Gini index, it complets tha valuable work of Achim Zeileis, the author of the ineq package. I would like to make it to be part of all R package. How should I proceed. Must I sent it to the the Core developement team ? The proogramme is written in R. Many thanks for your advice, Best regards, Souleymane

Dear All, I wish to calculate the Gini index (ineq from same package) and some other indices for the diameter distribution of each plot (df dgtot). dgtot: IDPlot Diameter(cm) 1 4 34.0 2 4 23.0 3 4 38.0 ... 51 5 16.0 52 5 8.0 53 5 9.0 ... 5301 140 25.0 5302 140 12.0 5303 140 7.0 I use: >

Buen día a todos. Tengo un problema.Podría ayudarme diciendóme cómo se llama la paquetería para encontrar el comando "bs.data", lo he estado buscando para ver como escribir el comando en R y no me aparece una paquetería para ver la descripción. Saludos. [[alternative HTML version deleted]]

By any chance are there any alternatives to image(...) and filled.contour(...) I used Rseek to search for that very topic, but didn't turn over any leads... http://www.rseek.org/?cx=010923144343702598753%3Aboaz1reyxd4&newwindow=1&q=alternative+to+image+and+filled.contour&sa=Search&cof=FORID%3A11&siteurl=www.rseek.org%252F#1238 I'm sure there are some out there, but

I am looking for R packages that can make a Logistic Regression model with parameter estimation by Maximum Likelihood Estimation. Many thanks for helping out.

Hello dear R-help members, I would appreciate any help in understanding how the rpart function computes the "improve" (which is given in fit$split) when using the split='information' parameter. Thanks to Professor Atkinson help, I was able to find how this is done in the case that split='gini'. By following the explanation here: