similar to: recursive function on a structured list of lists (dendrogram)

Dear r-list, I am trying to visually seperate the two main clusters of a dendrogram. The idea is to use: 'edgePar=list(lty=3)' for 'dend1[[1]]' and 'edgePar=list(lty=1)' for 'dend1[[2]]' I have not found a way to solve this. Any suggestions? Patrick hc <- hclust(dist(USArrests), "ave") (dend1 <- as.dendrogram(hc)) par(mfrow=c(2,2)) plot(dend1)

I am trying to learn how to format Ascii data files for scan or read into R. Precisely for a quickie project, I found some code (at end of this email) to do exactly what I need: To cluster and graph a dendrogram from package (stats). I am stuck on how to format a text file to run the script. I looked at the dataset USArrests (which would be replaced by my data and labels) using UltraEdit. That

Hello to all, I still have this doubt. I'd like to colour the different labels of my dendrogram each one with a different colour. How can I do? I guess I could do using *edgetext* and then *t.col* or* lab.col* but I don't know how to add edgetext to my dendrogram. Can you help me please? Example: require(graphics); require(utils) hc <- hclust(dist(USArrests), "ave") (dend1

Hi! In the example: hc <- hclust(dist(USArrests), "ave") dend1 <- as.dendrogram(hc) dend2 <- cut(dend1, h=70) Do the branches "Branch 1", "Branch 2", "Branch 2"...in dend2$upper str(dend2$upper) --[dendrogram w/ 2 branches and 4 members at h = 152] |--[dendrogram w/ 2 branches and 2 members at h = 77.6] | |--leaf "Branch 1" (h=

Hello to all, I'd like to colour the different labels of my dendrogram. How can I do? I guess I could to using *edgetext* and then* t.col* or *lab.col* but I don't know how to add edgetext to my dendrogram. Can you help me please? Example: require(graphics); require(utils) hc <- hclust(dist(USArrests), "ave") plot(dend1) labels (USArrests) [[1]] # to know how many cities

I would like to be able to exert certain types of control over the plotting of dendrograms (representing hierarchical clusterings) that I think is best achieved by modifying the dendrogram object prior to plotting. I am using the "dendrogram" class and associated methods. Define the cluster number of each cluster formed as the corresponding row of the merge object. So, if you are

Dear All, How can the height of a leaf be extracted from a dendrogram? Sure, I can print it, but I am not able to, say, store it in an object. I think I understand that the height is a property of the split, not the leaf itself, but the printing functions display a "height" or "h" (which changes with "hang") and that is what I want. Obviously, the info is there

Hello, It seems that the plot function for dendrograms does not draw labels when they are too long. > hc <- hclust(dist(USArrests), "ave") > dend1 <- as.dendrogram(hc) > dend2 <- cut(dend1, h=70) > dd <- dend2$lower[[1]] > plot(dd) # first label is drawn > attr(dd[[1]], "label") <- "aaaaaaaaaaaaaaaaaa" > plot(dd) # first label is

I am using hclust and plot to produce dendrograms. Using my input data I am able to complete an analysis and obtain a vertical plot. I want to be able to plot the dendrogram horizontally.I am using version 2.6 of R and have updated my packages recently. Using the sample script for dendrograms I can produce a horizontal plot using the instruction horiz = TRUE in plot(). When I use the same

I'd like to be able to cut dendrograms at a height I specify and then plot the resulting subtrees. I wanted to use the dendrogram object for this purpose because there doesn't seem to be a canned way to cut a hclust object and get a list of hclust objects, but there is a function (cut) that does that for dendrograms. The problem I'm having is that when I plot a dendrogram, I

Dear useRs, I am working on a project involving the clustering of a large dataset. I need to extract specific sub-clusters from the parent dendrogram for further analysis. The data is too large for the use of convenient tools such as identify.clust (it selects the specific group of interest on a graph), so alternatively I have saved the plot as a large image file so that it can be printed or

Hi I have a distance matrix which is computed by user defined method. I would like to plot the dendrogram. I would like to use different color and want the leaves laying down bottom. The script like this. I am not familiar with R. I followed the example shown in http://stat.ethz.ch/R-manual/R-devel/library/stats/html/dendrogram.html dist.obj <- as.dist(matrix.distance) hc.obj <-

Dear R-Help, I have a clustering problem with hclust that I hope someone can help me with. Consider the classic hclust example: hc <- hclust(dist(USArrests), "ave") plot(hc) I would like to cut the tree up in such a way so as to avoid small clusters, so that we get a minimum number of items in each cluster, and therefore avoid singletons. e.g. in this example, you can see

Dear I am using the 'as.dendrogram' function from the 'stats' library to convert from an hclust object to a dendrogram with a dataset of size ~30000 (an example code is below). I need the dendrogram structure to use the "dendrapply" and "attributes" functions and to access the child nodes, I do not need any of the plot properties. The problem is that it

I have done a cluster analysis doing: 1-clusNorth <-hclust(dist(Artorious)^2, method="ward") 2-clusNorth$labels <-Artorious$Name ## to show the case names and not numbers 3-dend1 <- as.dendrogram(clusNorth) 4-plot(dend1) My Dendrogram is now showing the names of my cases in the dataframe on the x axis 1 OMNICELL INC COM 2 GETTY IMAGES INC

I have tried to use rect.hclust() to draw a rectangle around a set of leaves, but am running into trouble. The rect.hclust() is drawing two rects instead of one, and of the wrong size: -------------------- scoreClusterObj <- hclust(scoreDistanceObj, method=clustMethod) order <- scoreClusterObj$order orderedLabels <- rep(0, length(order)) for (orderIndex in 1:length(order)) { # this

Hi all, I think I have some problems to use correctly the function dendrapply. Let suppose dend is a dendrogram object. I would likde to know the cardinal number of leaves depending of each node of the tree dend. It is right that the command attr(dend,"members") gives the total number of leaves, and attr(dend[[1]],"members") gives the number of leaves for the first left

Hello, I am a new R user and have a question regarding dendrogram coloring. I would like to color each leaf in the dendrogram (dhc) according to a specific criterion. For me this criterion is the gene name. For this, I created a data.frame with 2 variables: The gene name and the corresponding color. Using the following function, adapted from "dendrapply {stats}", I still have the same

Hi all, This is the first time I'm writing to R-devel, and this time I'm just asking for the purpose for a certain line of code in stats::as.hclust.dendrogram, which comes up as I'm trying to fix dendextend. The line in question is at line 128 of dendrogram.R in R-3.3.3, at stats::as.hclust.dendrogram: stopifnot(length(s) == 2L, all( vapply(s, is.integer, NA) )) Is there any

Hi! I just discovered that cutree() and cut.dendrogram() do not assign the same cluster numberings when called on the same tree. More specifically, cutree() assigns cluster numbers by order of appearance in the data, while cut.dendrogram() sorts clusters by height (see example below). I guess this is for historical reasons? I'm hit by this difference when I want to get a vector of cluster