Displaying 20 results from an estimated 10000 matches similar to: "Parameter Matrix"
2013 Feb 27
2
matrix multiplication
Hi,
Try this:
#mat1 is the data
res<-do.call(cbind,lapply(seq_len(nrow(mat1)),function(i) {new1<-do.call(rbind,lapply(seq_len(nrow(mat1[-i,])),function(j) {x1<-rbind(mat1[i,],mat1[j,]); x2<-(abs(x1[1,1]-x1[2,1])*abs(x1[1,5]-x1[2,5]))+(abs(x1[1,2]-x1[2,2])*abs(x1[1,6]-x1[2,6]))+(abs(x1[1,3]-x1[2,3])*abs(x1[1,7]-x1[2,7]))+(abs(x1[1,4]-x1[2,4])*abs(x1[1,8]-x1[2,8]))}));new1}))
2018 Aug 08
2
limit sharing ability to certain users
http://repo.dovecot.org/ <http://repo.dovecot.org/>
Sami
> On 8 Aug 2018, at 10.27, Simeon Ott <simeon.ott at onnet.ch> wrote:
>
> Okay, this seems to be due to the fact that the option ?use_globals_only" is supported only in v2.2.31+
> We are on Debian jessie with dovecot v2.2.13 ? even an upgrade to current stable stretch won?t help (dovecot v2.2.27). So we will
2013 Apr 12
2
processing matrix equation derived from rows of two matrices
Hi,
May be this helps:
?tb[1,]%*%(((val-rep(meansb79[1,],5))^2)/6)
#??????? [,1]
#[1,] 1.47619
tryvarb<-c(1,2,3,4,4,4,4)
?var(tryvarb)
#[1] 1.47619
tb[2,]%*%(((val-rep(meansb79[2,],5))^2)/6)
#???????? [,1]
#[1,] 1.904762
sapply(seq_len(nrow(tb)),function(i) tb[i,]%*%(((val-rep(meansb79[i,],5))^2/6)))
# [1] 1.4761905 1.9047619 1.9047619 1.9047619 1.9047619 2.2857143 1.9047619
# [8] 1.9047619
2019 Sep 18
2
Sync UID/GUI between two DCs
Am 18.09.19 um 16:17 schrieb Rowland penny:
> On 18/09/2019 03:41, Simeon Peter via samba wrote:
>> I would remove any uidNumber & gidNumber attributes from the
>> following users (if set):
>>> administrator
>>> guest
>>> krbtgt
>> Administrator has a uidNumber since long time and owns some files.
>> Are there disadvantages if I leave his
2009 Aug 18
1
Plyr and memory allocation issue
Dear R users
I am trying to create some new variables for a 4401 x 30 dataframe using
ddply and transform. The "id" variable i am using is a factor with 1330
levles eg
bb <- function(df) {transform(df,
years = study.year - min(study.year) + 1,
periods = length(study.year)
)}
test <- ddply(x,.(id),bb)
I havent copied the data to avoid clogging the
2017 Nov 14
1
OrcJIT + CUDA Prototype for Cling
Hi Lang,
thank You very much. I've used Your code and the creating of the object
file works. I think the problem is after creating the object file. When
I link the object file with ld I get an executable, which is working right.
After changing the clang and llvm libraries from the package control
version (.deb) to a own compiled version with debug options, I get an
assert() fault.
In
void
2008 Jun 10
2
convert characters into integers in a matrix
Hello,
I will appreciate any suggestion for this simple problem. I have a matrix of
characters "A", "P", "M".
I want to convert those characters to integers 0,1, 1 respectively. I am
using the following R statements:
exprs.new<-gsub("P",1,exprs)
exprs.new1 <- gsub("A",0,exprs.new)
exprs.new2 <-
2007 Nov 12
1
update matrix with subset of it where only row names match
I guess this has a simple solution:
I have matrix 'mat1' which has row and column names, e.g.:
A B C
row1 0 0 0
row2 0 0 0
....
rown 0 0 0
I have a another matrix 'mat2', essentially a subset of 'mat1' where the
rownames are all in 'mat1' e.g.:
B
row3 5
row8 6
row54 7
I want to insert the values of matrix mat2 for column B (in reality it
could be some or
2019 Sep 18
2
Sync UID/GUI between two DCs
Thank you for your answers Rowland.
I could go ahead.
Am 17.09.19 um 18:52 schrieb Rowland penny:
> On 17/09/2019 09:30, Simeon Peter wrote:
>> Am 17.09.19 um 17:08 schrieb Rowland penny via samba:
>>> Do not give the standard Windows users and groups a uid/gidNumber,
>>> most are never used on Unix, the main exception would be Domain Users.
>> OK, now I did it
2010 Jan 29
7
Simple question on replace a matrix row
Hello, I have a matrix mat1 of dim [1,8] and mat2 of dim[30,8], I want to
replace the first row of mat2 with mat1, this is what I do:
mat2[1,]<-mat1 but it transforms mat2 in a list I don't understand, I want
it to stay a matrix...
-----
Anna Lippel
--
View this message in context: http://n4.nabble.com/Simple-question-on-replace-a-matrix-row-tp1427857p1427857.html
Sent from the R help
2007 Nov 21
2
matrix elementwise average with NA's
Hello fellow R users,
I have a matrix computation that I imagine should be relatively easy to do, however I cannot figure out a nice way to do it. I have two matrices, for example
mat1 <- matrix(c(1:5,rep(NA,5), 6:10), nrow=3, byrow=T)
mat2 <- matrix(c(2:6, 6:10, rep(NA,5)), nrow=3, byrow=T)
I'd like to compute the element-wise average for non-NA entries. Of course
(mat1+mat2)/2
2009 Jan 17
1
Downloading Excel file & reading a range
I am trying to figure out a way to download an Excel file and then read a
range into R - so that i can have a reasonably automated process. I have
been trying to use the RODBC package, but with little success. I suspect
that this isnt the right route
Here is some code. My aim is to read in the data starting in H69:H283 in
sheet 2.
2013 Sep 20
3
search species with all absence in a presence-absence matrix
Dear list
I have a matrix composed of islandID as rows and speciesID as columns.
IslandID: Island A, B, C….O (15 islands in total)
SpeciesID: D0001, D0002, D0003….D0100 (100 species in total)
The cell of the matrix describes presence (1) or absence (0) of the species
in an island.
Now I would like to search the species with absence (0)
in all the islands (Island A to Island O.)
2013 Sep 26
1
Grouping Matrix by Columns; OHLC Data
HI,
May be this helps:
set.seed(24)
?mat1<- matrix(sample(1:60,30*24,replace=TRUE),ncol=24)
colnames(mat1)<- rep(c("O","H","L","C"),6)
indx<-seq_along(colnames(mat1))
n<- length(unique(colnames(mat1)))
?res<- lapply(split(indx,(indx-1)%%n+1),function(i) mat1[,i])
lapply(res,head,2)
#$`1`
#????? O? O? O? O? O? O
#[1,] 18 56 51 24 24 52
#[2,]
2003 Mar 20
2
Matrix problems
Hi all.
I do not know if it is a bug in the windows version but i have this
problem.
Reading a file with 200000 rows, 2 columns and transforming into a
200000 x 2 matrix.
If I try to find an element by using the which command which gives
some correct indexes plus some others passing the 200000 row
boundaries.
If I try to reach those "outbound" indexs I get an "Error: subscript out
2012 Nov 16
4
Multiple Vector with matrix in R
Hi
Can someone show me an easy way to multiple a weighted vector with an
matrix?
example below
mat1<-matrix(sample(1:100,80,replace=TRUE),ncol=8)
w <- 1/1:10
I want the first element in w to be multiplied by the first row of mat1 and
2nd element in w to be multiplied with the 2nd row and so on.
I have huge matrix is there an easy way other than diag(w)%*%mat1
Thanks
--
View this
2013 Apr 15
3
Indices of lowest values in matrix
Dear R users,Sorry for such a basic question. I really need to know that how can i pick the indices of 5 lowest values from each row of a matrix with dimensions 12*12??Thank you very much in advance
Elisa
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2013 Jan 04
2
Working with Matrix
Hello again,
Let say I have 2 matrices which equal number of columns but different
number of rows like:
Mat1 <- matrix(1:20, 4, 5)
Mat2 <- matrix(1:25, 5, 5)
Now for each column 1-to-5 I need to fetch the corresponding columns
of these 2 matrices and add the corresponding elements (ignoring NA
values if any). Therefore for the 1st column I need to do:
(1+1), (2+2),...,(4+4), (NA+5)
and
2012 Oct 05
3
loop for column substraction of a matrix
Dear useRs,
I have a matrix with 38 columns and 365 rows. what i want to do is the following.....
1. subtracting from each column, first itself and then all the remaining columns. More precisely, from column number 1, i will first subtract itself(column 1) and then the remaining 37 columns. Afterwards i will take column number 2 and do the same. In this way i want to proceed till 38th column.
2010 Mar 29
2
Need help on matrix manipulation
Dear all,
Ket say I have 3 matrices :
mat1 <- matrix(rnorm(16), 4)
mat2 <- matrix(rnorm(16), 4)
mat3 <- matrix(rnorm(16), 4)
Now I want to merge those three matrices to a single one with dimension
4*3=12 and 4 wherein
on resulting matrix, row 1,4,7,10 will be row-1,2,3,4 of "mat1", row
2,5,8,11 will be row-1,2,3,4 of "mat2" and row 3,6,8,12 will be row-1,2,3,4
of