similar to: transforming a .csv file column names as per a particular column rows using R code

Hello--I'm doing a simple crosstab using dcast: rawfreq <- dcast(nh11brfs, race3~CHCCOPD, length) with the results race3 Yes No NA 1 White non-Hispanic 446 5473 21 2 Other non-Hispanic 29 211 0 3 Hispanic 6 81 1 4 <NA> 10 83 1 How would I modify this call to exclude all missing values; that is, to obtain race3

Hi Experts, This might be silly question that I am asking, but no way as I am new to R. I want to list the files in a directory using regular expression like A_B*_C*.csv etc. How to make this possible in R ? I tried like this list.files(dir=".", pattern="A_B*_C*.csv") but this gives no output, whereas list.files(.... pattern="*.csv") giving all the .csv files in

Hello All, I use Cygwin ( unix on windows) heavily for all my text data processing. Also use Cygwin inbuilt *R* to do numerical processing. *My aim is to integrate R and unix commands to avoid heavy memory usage that R takes normally.* I can run many unix commands using system("some unix command or sh script.sh or even R file itself ") inside R. But, When I tried to run the command

Hi All, I have a data frame where nearly 10K columns of data, where most of them have standard deviation( of all rows) as zero. I want to exclude all the columns from the data frame and proceed to further processing. I tried like blow. *data <- read.csv("data.CSV", header=T) for(i in 2:ncol(data)) if(sd(data[,i])==0){ df[,i] <-NULL } * where I have the data columns from

Hi Rusers, I found sometimes that the same values cannot be judged to be the same in R. Anybody knows the probelm? I think i ignored some minor detail. Thanks. Here is the example. ############ data1<-matrix(data=c(1,1.2,1.3,"3/23/2004",1,1.5,2.3,"3/22/2004",2,0.2,3.3,"4/23/2004",3,1.5,1.3,"5/22/2004"),nrow=4,ncol=4,byrow=TRUE)