Displaying 20 results from an estimated 10000 matches similar to: "Autofilling a large matrix in R"
2011 Jun 23
3
trying to import xls or xlsx files
library(xlsReadWrite)
mydata<-read.xls("file path", header=TRUE)
however if I change xls to csv it works just fine. Any ideas what I'm doing
wrong? I have have also using the package gdata with the exact same error.
Below is the error that pops up.
Error in findPerl(verbose = verbose) :
perl executable not found. Use perl= argument to specify the correct path.
Error in
2011 Jun 21
2
qplot/ggplot2 Questions
I took some data from an online poll about which R GUI people used most and I
am messing around with it to learn how to use qplot. Specifically I am
making a horizontal bar graph and I have two questions.
1. The categories are ordered in rather strange way at least to me. It is
not alphabetical or ascending/descending order of votes cast so i had to
manually state the order I wanted which is
2012 Jul 20
6
Speeding up a loop
General problem: I have 20 projects that can be invested in and I need to
decide which combinations meet a certain set of standards. The total
possible combinations comes out to 2^20. However I know for a fact that the
number of projects must be greater than 5 and less than 13. So far the the
code below is the best I can come up with for iteratively creating a set to
check against my set of
2011 Jun 06
2
qplot fill and colour not working as expected
I am just learning to use qplot and can't get the fill/colour to work. Below
is the R code for a scatter plot and bar graph.
library(ggplot2)
x<-c(1,2,3,4,5,6,7)
y<-c(1,2,3,2,5,6,3)
qplot(x,y, main="Scatter Plot Test", xlab="X Label Test", ylab="Y Label
Test", colour="blue")z<-c("van", "van", "van",
2011 Jul 12
4
qplot and for loops
I have 4 columns and 56 rows of made up data that I want to plot as a series
of bar graphs. The idea is to create one bar graph for each of the 4 columns
using a for loop. I tried the following command in RStudio and when I type x
in the console I get just the 4th graph instead of all four graphs. I did
not define what x is before hand. I was not sure what it would be. Any
suggestions on how you
2012 Sep 07
4
Trying to learn how to write a function... can't define a variable??
I am just starting to experiment with writing a function and have run into
what seems like a limitation or more likely a lack of understanding on my
part.
Very Simple Example: I want to define a function that does 1+1=2.
z<-1
ADD<-function(x)
{
x<-x+1
}
ADD(z)
z
output for z is 1 not the expected 2.
Now if I were to do print(x+1) instead of x<-x+1 it does return 2, so the
2007 Nov 27
3
Disappearing decimals... please help!
Maybe it''s all in my head, but I''m having the strangest little issue
ever. My pricetags in my rails app are always whole numbers. Rails seems
to completely ignore my decimal input. So as a consequence, 10.41
becomes 10.00, always.
Here''s some worthwhile stuff:
within my 004_create_products.rb file:
:price, :decimal, :percision => 2, :default => 0
And calling
2012 Sep 26
3
Removing duplicates without a for loop
I have several thousand rows of shipment data imported into R as a data
frame, with two columns of particular interest, col 1 is the entry date, and
col 2 is the tracking number (colname is REQ.NR). Tracking numbers should be
unique but on occassion aren't because they get entered more than once. This
creates two or more rows of with the same tracking number but different
dates. I wrote a for
2012 Jul 23
2
Bug in my code (finding nonzero min)
Can someone verify for me if the for loop below is really calculating the
nonzero min for each row of a matrix? I have a bug somewhere in the is
section of code. My first guess is how I am find the the nonzero min of each
row of my matrix. The overall idea is to make sure I am investing all of my
money, i.e. new.set is a set of indicator variables for each stock for a
particular portfolio, i.e.
2006 Jan 17
9
Formatting a float with a set number of decimals
Another newbie question:
How do i convert a float to a string, rounded to a certain number of
decimals?
Thanks
--
Posted via http://www.ruby-forum.com/.
2006 Jul 22
4
Reading floating points into a field stored as Integers
Hi, I''m trying to follow the "AWDR" example of storing certain types of
numbers (in my case, percentages not money) as integers in the
database. I understand from the Depot application how to format the
output to have 2 places (or n places for that matter) decimal.
Now, I"m wondering about the input. It''s more natural for people to
enter numbers as
2008 Jul 25
2
Package Hmisc, functions summary.formula() and latex(), options pdig, pctdig, eps and prmsd
Un texte encapsul? et encod? dans un jeu de caract?res inconnu a ?t? nettoy?...
Nom : non disponible
URL : <https://stat.ethz.ch/pipermail/r-help/attachments/20080725/bcafe250/attachment.pl>
2011 May 04
1
Str info. Thanks for helping
It looks from str(SA) that Response IPS1 is a data.frame of class "anova", which probably cannot be coerced to vector.
Maybe you can use unlist() instead of as.vector()
Or something like
SA[["Response IPS1"]]["as.factor(WSD)",] ## to select the first row only, even maybe with unlist()
Without a better REPRODUCIBLE example, I cannot tell more (maybe some others
2011 Apr 27
2
Writing Macros for RExcel
I have columns of data in Excel 2007, A2:A196, B2:B196...ET2:ET196 that I
would like to place into arrays in R. I have been trying to write a macro
that would automatically create all of my arrays for me with a array names
coming from the cells A1, B1, etc.
I can manually create an array using RExcel<Put R Var< Array, but I don't
want to manually create all 150 arrays this way.
Thanks
2009 Feb 04
1
How to declare an array with columns storing different datatypes/precision
Dear R- Experts,
Seek your help.
I want to creata data as follows.
Ref_array with 4 columns.
1st column should store data of precision: 8.4 (i.e. 8 digits before decimal
point and 4 digits after decimal points)
2nd column: should store data of type date "yyyy-mm-dd hh:mm:ss"
3rd column: only integer value. No decimal points
4th column: percentage values
Please help.
Thank you in
2011 Aug 02
3
3D Bar Graphs in ggplot2?
Does anyone know how to create a 3D Bargraph using ggplot2/qplot. I don't
mean 3D as in x,y,z coordinates. Just a 2D bar graph with a 3D shaped bard.
See attached excel file for an example.
Before anyone asks I know that 3D looking bars don't add anything except
"prettiness".
http://r.789695.n4.nabble.com/file/n3713305/Example.xlsx Example.xlsx
--
View this message in
2012 Jul 20
0
[External] Re: Speeding up a loop
"Reith, William [USA]" <reith_william@bah.com> wrote on 07/20/2012
09:52:02 AM:
> Would this matrix eat up memory making the rest of my program
> slower? Each x needs to be multiplied by a matrix and the results
> checked against a set of thresholds. Doing them one at a time takes
> at least 24 hours right now.
>
> Optimizing a program is not my thing.
2008 Nov 10
1
cant boot after installation of centos 5
Hi all,
I'm having problems with the installation of CentOS 5 for i386 to my Dell
Percision T4500 Workstation.
The installation run just fine. The installation DVD had been tested before
installation. After installation, the installer ask me to reboot. after
reboot, when the msg for LVM saying detection of my LVMs, 1 or 2 lines after
that my monitor turned off, but i believed the cpu is still
2003 May 14
1
mcl models, percentages
I've put two packages for R on my home page at
http://www.xs4all.nl/~jhckx/R/. The "pcnt" package is for multiway
percentage tables. I've posted a first effort called "ctab" on this
group and a request for enhancing "ftable" with percentages on the
wishlist.
The "mcl" package is for estimating multinomial logistic models using
conditional logistic
2002 Oct 17
3
Non-central distributions
Hi Folks,
I note that, while the "chisq" functions
dchisq(x, df, ncp=0, log = FALSE)
pchisq(q, df, ncp=0, lower.tail = TRUE, log.p = FALSE)
qchisq(p, df, ncp=0, lower.tail = TRUE, log.p = FALSE)
rchisq(n, df, ncp=0)
all have a slot for the non-centrality parameter "ncp", of
the functions for the t and F distributions:
dt(x, df, log = FALSE)