Displaying 20 results from an estimated 1000 matches similar to: "How to replicate SAS by group processing in R"
2012 Oct 19
4
Creating a new by variable in a dataframe
Hello,
I have a dataframe w/ 3 variables of interest: transaction,date(tdate) &
time(event_tim).
How could I create a 4th variable (last_trans) that would flag the last
transaction of the day for each day?
In SAS I use:
proc sort data=all6;
by tdate event_tim;
run;
/*Create last transaction flag per day*/
data all6;
set all6;
by tdate event_tim;
last_trans=last.tdate;
Thanks
2012 Aug 31
2
Conditional merging in R & if then statement
1)I am wandering how the following SQL statement can be written in R language
w/o using sqldf:
create table detail2 as
select a.*
from detail a,
pdetail b
where a.TDATE=b.TDATE
and (a.STIM >= b.STIM and a.STIM <=b.MAXTIM)
2) when try if then in R it only applies to the 1st row & not to whole
dataset like in SAS. How do you get round that?
in SAS:
data summary;
set all1;
2012 Nov 13
1
Using lubridate to increment date by business days only
Hello,
I know how to increment a date by calendar date:
ticker$ldate <- ticker$tdate + days(5)
How do I increment it by business days only so that week-ends are not
counted?
So for example friday november 2 + 5days becomes friday november 9 & not
wednesday nov 7.
Thanks for your help.
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2013 Apr 03
5
Can package plyr also calculate the mode?
I am trying to replicate the SAS proc univariate in R. I got most of the
stats I needed for a by grouping in a data frame using:
all1 <- ddply(all,"ACT_NAME", summarise, mean=mean(COUNTS), sd=sd(COUNTS),
q25=quantile(COUNTS,.25),median=quantile(COUNTS,.50),
q75=quantile(COUNTS,.75),
q90=quantile(COUNTS,.90), q95=quantile(COUNTS,.95),
q99=quantile(COUNTS,.99) )
2013 May 23
3
Removing rows w/ smaller value from data frame
Hello,
I have a column called max_date in my data frame and I only want to keep the
bigger values for the same activity. How can I do that?
data frame:
activity max_dt
A 2013-03-05
B 2013-03-28
A 2013-03-28
C 2013-03-28
B 2013-03-01
Thank you for your help
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2013 Apr 05
2
How to perform a grouped shapiro wilk test on dataframe
Hello,
I was wandering if it is possible to perform on a dataframe called 'all' a
shapiro wilk normality test for COUNTS by variable Group
ACTIVITY? Could it be done using plyer? I saw an eg that applies to an
array but not to a dataframe:
lapply(split(dataset1$Height,dataset1$Group),shapiro.test)
Any thoughts would be much appreciated.
My dataframe is in shape:
dat ACTIVIT
2012 Nov 30
5
subset data frame by variable with missing value
Hello,
I have a variable in a data frame that contains NA values. I just want to
subset so that I get the obs where that variable is missing.
In SAS I would do:
data missing;
set test;
if myvalue=' ';
run;
How can I perform this simple task in R?
Thanks in advance for your help.
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2012 Sep 18
4
Conditional operations in R
Hello,
I am a newbie to R coming from SAS background. I am trying to program the
following:
I have a monthly data frame with 2 variables:
client pct_total
A 15%
B 10%
C 10%
D 9%
E 8%
F 6%
G 4%
I need to come up w/ a monthly list of clients that make 50% or just above
it every month so I can pass them to the rest of the program.
2012 Aug 29
2
Deduping in R by multiple variables
I have a dataset w/ 184K obs & 16 variables. In SAS I proc sort nodupkey it
in seconds by 11 variables.
I tried to do the same thing in R using both the unique & then the
!duplicated functions but it just hangs there & I get no output. Does
anyone know how to solve this?
This is how I tried to do it in R:
detail3 <-
2012 Sep 13
3
Cannot install package xlsx
I get following error message:
trying URL
'http://cran.stat.ucla.edu/bin/windows/contrib/2.15/xlsx_0.4.2.zip'
Content type 'application/zip' length 365611 bytes (357 Kb)
opened URL
downloaded 357 Kb
Error in read.dcf(file.path(pkgname, "DESCRIPTION"), c("Package", "Type")) :
cannot open the connection
In addition: Warning messages:
1: In
2012 Aug 24
1
if then in R versus SAS
I am new to R and I have the following SAS statements:
if otype='M' and ocond='1' and entry='a.Prop' then MOC=1;
else MOC=0;
How would I translate that into R code?
Thanks in advance
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2012 Sep 13
1
Paasing values to sqlQuery like SAS macro
Hello,
We lost our SAS licence & I am busy transfering my old SAS programs to R
environment. I am very new to R. In 1 program I was creating SAS macro
vars & passing them into a SQL query to run against the server. There are 3
variables firm, begindt, enddt. # of values for each varies month to month.
Is there anyway I could do the same thing in R & pass the afore mentioned
values
2013 Apr 12
2
Stat question: How to deal w/ negative outliers?
Hello all,
I have a question: I am using the interquantile method to spot outliers &
it gives me values of say 234 & -120 or for the higher & lower benchmarks.
I don't have any issues w/ the higher end. However I don't have any
negative values. My lowest possible value is 0. Should I consider 0 as an
outlier?
Thanks ahead for your thoughts
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2018 Mar 29
1
Problem with my function using as.POSIXct
Hello all:
I wrote a function:
my.bastimeToSynoptic <- function(x) {
f<-unlist(strsplit(as.character(x), " "))
hr<-unlist(strsplit(f[2], ":"))
if(as.numeric(hr[1])<6) {
synoptic<-"00"
}
else {
synoptic<-as.integer(as.numeric(hr[1])/6)*6
}
tdate<-paste(c(f[1],"
2018 Apr 15
4
Adding a new conditional column to a list of dataframes
Hi all ..,
I have a list of 7000 dataframes with similar column headers and I wanted to add a new column to each dataframe based on a certain condition which is the same for all dataframes.
When I extract one dataframe and apply my code it works very well as follows :-
First suppose this is my first dataframe in the list
> OneDF <- Mylist[[1]]
> OneDF
ID Pdate
2015 Nov 06
2
(sin asunto)
Hola a tod en s,
sigo intentando representar una variable en función de meses. En la columna
Mesos tengo los meses de la siguiente manera:
01/08/1996, 01/09/1996 etc.
He probado con el siguiente comando:
plot(Mesos, Serie01)
obteniendo
y tendría que obtener:
[image: Imágenes integradas 2]
Pero donde pone Observation Index, me gustaria tener los meses (para esta
grafica he usado
2018 Apr 15
0
Adding a new conditional column to a list of dataframes
> On Apr 15, 2018, at 4:08 AM, Allaisone 1 <Allaisone1 at hotmail.com> wrote:
>
>
> Hi all ..,
>
>
> I have a list of 7000 dataframes with similar column headers and I wanted to add a new column to each dataframe based on a certain condition which is the same for all dataframes.
>
>
> When I extract one dataframe and apply my code it works very well as
2008 Jun 17
2
constrOptim with method = "L-BFGS-B"
Hi,
i need to minimize a quadratic function with boundary condidtions and one
equality condition.
In order to do that i converted the equality constraint into 2 inequality
constaints and passed everything cia constrOptim, as the manual said:
everything included in the ... will be passed to Optim that will pass it
back to fn in case it does not need it.
My code is the following:
mat <-
2010 Sep 17
7
removing specific rows from array
I'm attempting to create an array of treatment comparisons for modelling data generation. This involves comparison of one treatment (c2) with another (c3), relative to a common comparator (c1).
Attached code gives me the correct array but need to remove duplicates. Duplicates relate only to c2 and c3
such that I need to remove
r3 because c2 and c3 are same as r1 with c2 and c3 swapped
r5
2010 Jun 13
1
using latticeExtra plotting confidence intervals
I am wanting to plot a 95% confidence band using segplot, yet I am wanting
to have groups. For example if I have males and females, and then I have
them in different races, I want the racial groups in different panels. I
have this minor code, completely made up but gets at what I am wanting, 4
random samples and 4 samples of confidence, I know how to get A & B into one
panel and C&D in to