similar to: erasing a polygon

I have a case where the easiest way to draw a particular symbol would be to draw something a little bigger, and then use polygon(... , col=0) to erase the extra stuff. Just how to do this best when par('bg') = 'transparent' is, however, eluding me. I've looked through the archives and the book R Graphics without quite seeing the light. Help or pointers to help would be

# polygon ignores requests to have its border transparent, look at par(bg="transparent") plot(c(0, 3), 0:1) polygon(c(0, 1, 1, 0), c(0, 0, 1, 1), border=NA, col = 0) polygon(c(1, 2, 2, 1), c(0, 0, 1, 1), border="transparent", col = 0) polygon(c(2, 3, 3, 2), c(0, 0, 1, 1), border=0, col = 0) # a quick fix for erase.screen() is the following erase.screen <- function (n =

Dear R users, I still feel new to R so please apologize if I am doing something stupid here. My use of the polygon() function produces a result that I cannot comprehend: In a plot, I would like to shade the area below a normal distribution. However, I do not want the entire area to be shaded, but just the area on the right side of a vertical line that I draw through the distribution (in

Objective: Determine if a set of x and y-latitude points are inside of a polygon using R. Lets say I have 9 polygons. Where I have labeled the polygons to be checked from 1-9. The problem I?m running into is running the point.in.polygon to check if those points are in one of several polygons, as my code overwrites the result. To accomplish this I am using the R-built in function called

I am a new user of the R spatstat package and am having problems creating a polygonal observation window with owin(). Code follows: library("maps") library ("sp")` library("spatstat") mass.map <- map("state", "massachusetts:main", fill=T) # This returns a data frame includding x and y components that form a polygon of massachusetts mainland`

Hello Friends!!! I would want draw a circular histogram, and I would like draw a polygon with a circular side. This is easy if I use the functions polygon and arc, but I want that the polygon with a circular side have background colour. The polygon created with function polygon can have background colour, but the surface created with function arc can?t have background colour. How I could create a

Dear useRs: I try to plot an rpart object but cannot get a nice tree structure plot. I am using plot.rpart and text.rpart (please see below) but the branches that connect the nodes overlap the text in the ellipses and rectangles. Is there a way to get a clean nice tree plot (as in the Rpart Mayo report)? I work under Windows and use R2.11.1 with rpart version 3.1-46. Thank you. Tudor ...

Dear list: I encountered some problems using the function point.in.polygon() of the sp package, when trying to determine whether some points lye inside, outside, on the border or on a vertice of a polygon. I have a list of point I know should lye right on the border of a polygon, but some of them are not classified as such by point.in.polygon() (see the example code below). To make a long story

I was reading a presentation of Professor Peng's and typed the presentation code into R but I changed it to make plot.polygon a separate function instread of defining the function in SetMethod itself as he did. Is that the problem with the code below because plot(p) just gives me zero. Thanks. setClass("polygon", representation(x = "numeric", y =

Tena koe Simon plot(1:10, 1:10, type='n') polygon(c(2,3,6,8), c(2,5,5,3), density=20, angle=90) polygon(c(2,3,6,8), 5+c(2,5,5,3), density=20, angle=0) I don't understand your problem. Perhaps if you "provide[d] commented, minimal, self-contained, reproducible code" it would help. HTH .... Peter Alspach -----Original Message----- From: R-help [mailto:r-help-bounces at

The angle is not based on the polygon edges, but it can seem that way if you do not use the asp=1 argument in your plot. Try this example, > plot(1:10, 1:10, type='n') > x <- c(1, 3, 5, 3) > y <- c(3, 5, 3, 1) > polygon(x, y, angle=0, density=10) > polygon(x, y + 4.5, angle=45, density=10) > polygon(x + 4.5, y + 4.5, angle=90, density=10) > polygon(x + 4.5, y,

Thanks for the question. Here is a sample of the code for my plot: Top = c(34, 39, 42, 45, 46, 41, 41, 40, 43, 38, 33, 33) Bottom = c(24, 29, 32, 36, 32, 34, 32,41, 40, 39, 29, 24) plot(1,1, col = "white", xlim = c(1.3,11.7), ylim = c(0,80), axis = FALSE, xaxt = "n") axis(1, at = c(1:12)) polygon(c(c(1:12),c(12:1)), c(top, bottom), col =

I have a complex 2D polygon with thousands of vertices, and I'd like to be able to identify points from a large set contained within the polygon, and was wondering if there might be an efficient way of doing this? Any advice would be useful! Here is a small example of what I mean: # make polygon v1<-c(0,1,1,2,1,3,6,7) v2<-c(1,3,3,5,6,7,8,9) plot(v1, v2, type = "n" )

Dear R users; Is there any way to intersect a filled contour image and a polygon? My problem is that I want to create a kriging map and the boundaries of my map are given by the coordinates of the polygon. So far I can superompose the polygon in the filled.contour image but I don't know how to get rid of the contour image outside of the polygon boundaries. Any hint will be appreciated PM

Hi, I'm trying to use grid.polygon() to plot several polygons at once, with a view to putting coloured polygons beneath a curve. I'm struggling just to get the grid.polygon to plot anything # PLOT SOME POINTS x <- 1:100 y <- 1:100*0.5 + 3 plot(x, y, pch = ".") # PLOT 2 POLYGONS library(grid) grid.polygon(x = c(20, 20, 40, 40, 40, 40, 60, 60), y =

Dear forum, I would like to use the kernel2d or spkernel2d in the Splancs-package, but it does not recognize my polygon data. "Error in kernel2d(as.points(ptsbin), polygonprov, h0 = 2, nx = 100, : " is the error message. Invalid poly argument The data are defined as follows: polgonprov<-list(x=polyprov$X, y=polyprov$Y) with X and Y coordinates in the Lambert1972

HI, Sorry Carl, I received your message in my spam folder. Sarah proposed me a good example of code. Thank you Momadou  ________________________________ De : Carl Witthoft [via R] <ml-node+s789695n4188375h96@n4.nabble.com> Envoyé le : Mardi 13 Décembre 2011 3h34 Objet : Re: Polygon Please read the posting guide and provide a (small) reproducible example of your data. The statement

Filling polygons with lines is a throwback to the time when the height of quality graphics was the mechanical pen plotter (a device that used a pen in a mechanical arm to draw the plot on a piece of paper). Computing and printing technology has advanced quite a bit from that day, so you may want to reconsider why you want polygons filled with lines instead of just a solid color (and I consider

Hi all, I would like to color the area between two time-series. I tried it by using the polygon() function but I keeps drawing lines between beginning and end points. Is there another more appropriate function or how could I close the polygon at the end en the beginning of the time series (e.g., drawing a straight line)? The following doesn't plot a polygon between the two

Preamble: Sorry for being dense. Now that that's done, here are my questions. I want to put a polygon on a plot of a time series. I'm going to add lines from a smooth.spline interpolation and other annotation to it. But here's the general idea: # Start code n <- 121 dat <- rnorm(n) plot(dat, type="n") polygon(c(1:n,n:1), c(dat,c(rep(0,n))), col =