similar to: serial subtraction within a vector

Hello, I wish to count how often zero (0) appears in the vector test. test [1] 1 1 1 1 1 1 2 1 1 1 0 2 0 1 1 0 0 0 1 1 1 0 1 2 1 1 1 1 1 1 I think of something like ... > sapply (test, function (x) if (x==0 ... ... but actually I dont know how to carry on. Could anybody give me a hint? Thanks Hermann [[alternative HTML version deleted]]

Hello, I would like to transform a character vector into a "binary" vector ("keine" and " " become 0 and the rest 1). > dput (scm) c("keine", " ", "keine", "Erstgradverw.", "Mutter", "Erstgradverw.", "Erstgradverw.", "keine", " ", "Vater",

To whom it may concern. As I would like to analyse some array data I was keen on downloading the lumi package that depends obviously on hdrcde that is not available for r 2.12.1. I did not find instructions to solve or circumvent this problem. Installing hdrcde by hand did not work either. It was not detected by > (.packages(all.available=TRUE)) if installed in the R library. Thanks Hermann

Hello, I have a list with gene names, fold changes (=expression level) and chromosomes. Names fold change chromosome hz 1.5 2 If I plot fold change versus chromosome (or vice versa): plot (ch, fc) I see only the chromosomes with numbers but not those with letter (x and y). What can I do? A second question: How can I add a single line in that plot at a certain

Dear list, I wish to plot chromatin precipitation data: I would like to have a rectangles (x:end-start, y:peak) but I do not have an idea how to define x (in terms of qplot syntax) and to choose the correct geom. mydata is a subset of a larger file. > mydata chrom start end peak 1 chr11 5291000 5291926 8 2 chr11 10988025 10988526 7 3 chr11 11767950 11768676 8 4

Hello, having a data frame like test with pairs of characters I would like to create chains. For instance from the pairs A/B and B/I you get the vector A B I. It is like jumping from one pair to the next related pair. So for my example test you should get: A B F G H I C F I K D L M N O P > test V1 V2 1 A B 2 A F 3 A G 4 A H 5 B F 6 B I 7 C F 8 C I 9 C K 10 D L

Hello, I have start and end coordinates from different experiments (DNase hypersensitivity data) and now I would like to combine overlapping intervals. For instance (see my test data below) (2) 30-52 and (3) 49-101 are combined to 30-101. But 49-101 and 70-103 would not be combined because they are on different chromosomes (chr a and chr b). Does anybody have an idea? Thanks Hermann > df

Hello, my data is sorted by start.ens (see below). And now I would like to extract all rows (so called* defined row*s) with type==Expression - subset (df, type==Expression) - and the aforegoing type==DNase HS (which is not necessarly row n-1 - assumung that the defined row is n). I dont know how to add this to my subset command. Is that possible? Thanks Hermann > df start.ens fc.trans

Hello, I did a pca with over 200000 snps for 340 observations (ids). If I plot the eigenvectors (called rotation in prcomp) 2,3 and 4 (e.g. plot (rotation[,2]) I see a strange "column" in my data (see attachment). I suggest it is an artefact (but of what?). Suggestion: I used prcomp this way: prcomp (mat), where mat is a matrix with the column means already substracted followed by a

Dear list, I have a problem with defining a function (see below) to read my testfile (see testfile). My function only returns mydata I wish to work with attr(mydata, 'fc') as well (for labelling a plot). Principally it works if I do not insist on this function but it would be much easer if it is possible to return mydata AND attr(mydata, 'fc') by using a function. 1) testfile:

Hello, I open some files in a directory and get a list. open.list <- sapply (namen, function (x) {file <- list.files (ddir, pattern=x, full.names=TRUE) # namen is vector and each element detects a special file to open file <- read.table (file) } ) This list has no names. I would like to get a list with key/value

Sorry, it seems I have only replied to Lakhdar, not to the newsgroup. Below is my reply to Lakhdar, and I would like to make it more clear now, using some pseudo values for simplicity: I read bytes 1 to 124 from my encoded spx file. I decode themt and get the values: ---Frame 1---- -293 -8234 2134 17 ---Frame 2---- -9323 -732 189 2329 Both frames are just perfect as I need them. But now when I

I found out something: The more frames I decode before the frame that I actually want to decode, the better the quality becomes. For example when I basically want to decode frame #100, I read frame #80 to #100, and then frame 100 has the quality that I need. Why? Is there any information on this behaviour? Thank you. Hermann Am 23.12.2011 18:37, schrieb Hermann Weber: > It would be nice

Hi Everyone, I would like to do sequential subtractions within a group so that I know the time between separate observations for a group of individuals. My data: data <- structure(list(group = c("IND1", "IND1", "IND2", "IND2", "IND2", "IND3", "IND4", "IND5", "IND6", "IND6"), date_obs =

My file is 3 hours long, so decoding takes around 5 minutes on an average computer. That is a bit too long unfortunately... Am 23.12.2011 20:38, schrieb Steve Checkoway: > On Dec 23, 2011, at 10:54, Hermann Weber<hermie.weber at gmx.de> wrote: > >> And how many frames does Speex need to "recover"? >> Or is that not predictable? > No idea. My guess is not

And how many frames does Speex need to "recover"? Or is that not predictable? Greetings, Hermann Am 23.12.2011 19:17, schrieb Steve Checkoway: > > On Dec 23, 2011, at 10:03 , Hermann Weber wrote: > >> I found out something: >> >> The more frames I decode before the frame that I actually want to >> decode, the better the quality becomes. >> For

Dear Nikos, thanks! But you use Opus only for resampling, not for entirely replacing Speex, don't you? Greetings! Hermie Am 07.05.2013 22:53, schrieb Nikos Chantziaras: > The Opus resampler is actually a bugfixed version of the Speex one. Same > interface/API, but with the bugs removed. It's why I recommended it :-) > Otherwise I would have recommended something entirely

Hello, I have a samba 1.9.18p4 server running as a domain master browser on a subnet, with some clients distributed on other subnets. If there are only Win 95 clients on a subnet, browse sync works - but not if there are Win NT 4.0 SP3 machines on that subnet. Error from nmdb (at log level 3): sync_with_lmb: Initiating sync with local master browser MAILHEIDELBERG<0x20> at IP

I would like to calculate vector from existing value e.g v <- 1000 s <- 30 d1 <- v-s d1 <- 970 d2 <- d1 -s d2 <- 940 d 3 <- d2-s d3 <- 910 : : d15 <- ..... so how I should get vector of length 15 d < - 970,940 , 910 , ....... -- View this message in context:

Hello! I encoded a voice file (48kHz) with opusbin\opusenc.exe with the standard settings and decoded it. The output was amazing. I could not hear any loss at all. Then i encoded the same file with opus_demo.exe and standard settings and then decoded it. The output had a sizzling noise, even when I used full bandwidth. I think I have played around with any of the settings in opus_demo.exe,