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Hi all I am writing to you with a question regarding the pvclust package. And yes, before the usual people produce their usual contact-the-package-maintainers line, ye, I tried that but the emails one can find on the web either bounce or are not responded to. Also, yes, this error has already been reported as a bug but been shot down as not reproducible

Dear all I use R for Windows 2.3.1 on a fully updated Windows XP Home SP2 machine and I have two related regular expression problems. platform i386-pc-mingw32 arch i386 os mingw32 system i386, mingw32 status major 2 minor

Hi, I wish to develop a web crawler in R. I have been using the functionalities available under the RCurl package. I am able to extract the html content of the site but i don't know how to go about analyzing the html formatted document. I wish to know the frequency of a word in the document. I am only acquainted with analyzing data sets. So how should i go about analyzing data that is not

I am running R 1.2.3 with ESS5.1.18 with Windows 98. I am trying to use lsoda in the odesolve apckage and am having problems. Question: The return value of the function of the system of ode's has to be a list that includes first, the ode's and second, "a vector (possibly with a `names' attribute) of global values that are required at each point in `times'." I

Full_Name: Stefan Th. Gries Version: 2.2.1 OS: Windows XP (Home and Professional) Submission from: (NULL) (68.6.34.104) The problem is this: I have a vector of two character strings. > text<-c("This is a first example sentence.", "And this is a second example sentence.") If I now look for word boundaries with regexpr, this is what I get: >

Consider the following scrap of code: > x<- ts(1:50,start=c(1,11),freq=12) > y <- aggregate(x,nfreq=4) > c(y) [1] 6 15 24 33 42 51 60 69 78 87 96 105 114 123 132 141 > y Error in rep.int("", start.pad) : invalid number of copies in rep.int() > tsp(y) [1] 1.833333 5.583333 4.000000 So we can aggregate into quarters, but we cannot print it using

Consider the following scrap of code: > x<- ts(1:50,start=c(1,11),freq=12) > y <- aggregate(x,nfreq=4) > c(y) [1] 6 15 24 33 42 51 60 69 78 87 96 105 114 123 132 141 > y Error in rep.int("", start.pad) : invalid number of copies in rep.int() > tsp(y) [1] 1.833333 5.583333 4.000000 So we can aggregate into quarters, but we cannot print it using

dear all, I have some very long strings and would like to break up each long string into multiple strings with a fixed length, e.g. to break up abcdefghijkl into abc, def, ghi, jkl I tried a couple of commands but was not successful. Any help will be appreciated. Best, Jimmy -- View this message in context:

Hi all I have run into a case where I don't understand why predict.lrm and predict.glm don't yield the same results. My data look like this: set.seed(1) library(Design); ilogit <- function(x) { 1/(1+exp(-x)) } ORDER <- factor(sample(c("mc-sc", "sc-mc"), 403, TRUE)) CONJ <- factor(sample(c("als", "bevor", "nachdem",

I have problem with integer overflow that I cannot understand. I have a character vector curr.lemmas with the following properties: length(curr.lemmas) # 61224 length(unique(curr.lemmas)) # 2652 That vector is the input to the following function: yules.k1 <- function(input) { m1 <- length(input); temp <- table(table(input)) m2 <- sum("*"(temp,

Hello R-philes: I have the following function that gets the output of mget() and converts it to a data frame to return. What I am finding is that the dimensions are wrong. Basically, I get: bridesmaid wed u see m gt lt like love X.0 dress pagetrack one go X3 get 1 56 35 27 30 24 20 20 23 28 17 25 16 16 28 15 26 Instead, I want something like: [1] bridesmaid

Full_Name: Stefan Th. Gries Version: R version 2.6.1 (2007-11-26) OS: Windows XP Home SP2 Submission from: (NULL) (68.6.47.105) Hi A simple computation results in integer overflow: These are the relevant vectors: > sum(cur.obs) [1] 110231 > colfreq other past perfect present progressive 14845 1222 4776 101347 2863 >

My tuneR sawtooth wave function generator is broken. When I use the sine function, I get exactly what I expect: a sine wave whose frequency is defined by the freq parameter. In particular, higher frequencies have shorter wavelengths (more cycles per second means shorter waves). When I create a sawtooth wave, the opposite seems to occur: higher frequencies result in longer waves. But that?s not

Hi, I have two histograms created separately using the following code. It creates two separate figures. dat <- read.table(file="GDS1096.modelout", head = FALSE ) __BEGIN__ dat <- read.table(file="GDS1096.modelout", head = FALSE ) hist(dat$V2, main="AIC Freq", xlab = "\# Component", breaks = 36, xlim = c(0,max(dat$V2)), col = "dark red",

Ccing the maintainer if the tuneR package. Looks to me like sawtooth (and square) don't behave as expected when using xunit="samples". Workaround is to use xunit="time" instead: sawtooth(110,duration=1/100,samp.rate=sample_rate,xunit="time") I looked at the code but found it to be opaque. -- Sent from my phone. Please excuse my brevity. On November 12, 2017

Dear R-users, I have sent another mail some hour ago about a matlab Code I was trying to translate in R. Actually I have found a simpler code originally written in S-PLUS for the same function. Author's page -> http://math.bu.edu/people/murad/methods/locwhitt/ ============================================================= rfunc_function(h, len, im, peri) # h -- Starting H value for

There were some questions about hist() a couple of days ago which triggered this post. My question/suggestion is about the y-axis in hist. There are reasons to prefer making the y-axis density=relative frequency/bin width. One reason is that the height of the plot does not depend on the bin width; another is that if your histogram is in density then you can easily superimpose a smooth theoretical

Hi all I have problems installing rJava on my system. ######## My system: > R.version # at R prompt platform x86_64-pc-linux-gnu arch x86_64 os linux-gnu system x86_64, linux-gnu status major 2 minor 8.1 year 2008 month 12 day 22 svn rev 47281 language R version.string R version 2.8.1

a) Numeric values may be either integers (signed 32 bit) or double precision (53 bit mantissa). b) Double precision constants are numeric with no decoration (e.g. 61224). Integer constants have an L (e.g. 61224L). c) 61224*61224 > 2^31-1 so that answer cannot fit into an integer. d) Exponentiation is a floating point operation so the result of 61224L^2L is a floating point answer that CAN

Hi friends, I have following data and would like to plot this with barchart() availble with lattice package. RsID Freqs Genotype AAA 63.636 1/1 AAA 32.727 1/2 AAA 3.636 2/2 BBB 85.965 2/2 BBB 14.035 2/1 CCC 63.158 1/1 CCC 21.053 1/2 CCC 15.789 2/2 DDD 26.786 2/2 DDD 46.429 2/1 DDD 26.786 1/1 EEE 32.759 2/2 EEE 43.103 2/1