similar to: Formula in a data-frame

Hello All, I have a data frame (dput information below) with food item weight for fish species. I need to calculate the Mean proportion by weight of each food item for each specie, as show in solution data frame (dput information below). I use the ddply function (plyr package) in two steps. First calculate the proportion of weight for each individual: step1 = ddply (example, .(ID), transform,

Hi, Could you please explain the :limit to me? I thought I knew what it was but now it seems I''ve misunderstood something. >> Fooditem.find_by_contents("*quark*", {:limit => 10}, {:conditions => ["origin = ?", "fda"]}).length => 1 >> Fooditem.find_by_contents("*quark*", {:limit => 2000000}, {:conditions => ["origin

Hi I''m having a really hard time trying to get a specific form in RoR to work. I''m trying to build a really simple page which lets the user make a pizza by setting check boxes. The choose their toppings, click submit and the form does a callback and shows them how much it will cost to have a pizza with those toppings on. At the moment I have the following: View: <%=

Hello, I am attempting to replace an NT server with Samba (2.0.4) under Linux (2.2.9) here at Plattsburgh State, and have 2 questions about a couple of snags I've run into: 1) Is there any way to specify a password server that has a space in its name? I keep getting errors in the log saying "Cannot find server WINDOWS" and "Cannot find server SERVER" (our NT server has

Hey, Does anyone out there know an easy way to make a Samba share not allow programs to run from it? Is there a way, besides simply hiding .exe files? I know this can be enabled on NTFS partitions under NT (bleech), but it would be nice to stop people from running programs out of publicly writable directories. I'm aware of why the linux ext2 execute permissions don't handle this btw...

Hello all, I don't understand a strange behavior in data frame manipulation. data_frame1 = data.frame(Site = c("S1", "S2", "S3", "S4", "L1", "L2", "L3", "L4"), Number = c(1, 3, 5, 2, 1, 1, 2, 1)) data_frame2 = data_frame1 [data_frame1$Site != "S1", ] dput (data_frame2) structure(list(Site =

Hola, tengo una matriz de especies donde cada celda tiene datos con caracteres (son parentesis). Cómo la puedo reordenar considerando tanto filas como columnas? Ejemplo: ,Specie 1, Specie2, Specie3 Specie1, NA, 3(1-4), 8(6-9) Specie2, 5(2-6),NA, 5(4-6) Specie3, 2(1-3), 10(5-15), NA Quiero: ,Specie 2, Specie3, Specie1 Specie2, NA, 5(4-6) , 5(2-6) Specie3, 10(5-15) ,NA,

Hi, sorry by this off. I'm still try to understand nested design. I have the follow example (fiction): I have 12 plots in 4 sizes in 3 replicates (4*3 = 12) In each plot I put 2 species (A and B) to reproduce. After a period I make samples in each board and count the number of individuals total (tot) and individuals A and B (nsp). Others individuals excepts A and B are in total of

Hello R Help, I'm working in a project with a software that register date and time data in serial time format. This format is used by excel, for exemple. In this format, 40597.3911423958 is 2011/2/23 09:23:15. First part is number os days since 1900/1/1, and second part is a fraction of a day. I need to make this transformation in R, and use it to make some algebrian operations. I found that

Hello all, I'm having a problem with data handling. My input data is (dput in the after the signature): Date Time Fraction 06/19/13 22:15:39 0.3205 06/19/13 22:15:44 0.3205 06/19/13 22:15:49 0.3205 06/19/13 22:15:54 0.3205 06/19/13 22:15:59 0.3205 06/19/13 22:16:09 0.3205 Date in format month/day/year, Time in HH:MM:SS and fraction represents the fractions of

List, I want to reshape my data, but I'm not sure how to do it... it might be a simple task, but don't know which package does this. "occ.data" (see below) is how my original data are arranged, and I know that with melt() I can reshape it like "y" (see below). However, I just want to build a matrix like the "y" matrix, but with only 2 dimensions. Something

Hello all! I have a data frame with nine variables and 293 cases. (attached goes the csv file). I need to calculate a index using the sum of one variable (N) divided by the length of other variable (Fisherman), but for each day (Date). I tried to use that codes: by (cpue, cpue$Date, function (x) sum (cpue$N)/length(cpue$Fisherman)) tapply (cpue$Data, cpue$Data, function (x) {sum

Hello, I have a table that was constructed in a wrong way (dput data on bottom - wrong data-frame): Local Mês Dia Colonia X6h X7h X8h X9h X10h X11h X12h X13h X14h X15h X16h X17h 1 Conceição Junho 1 3 2.16137 2.20412 2.08991 1.72428 1.69897 1.62325 1.44716 1.51851 1.43136 1.47712 1.51851 1.04139 2 Conceição Junho 2 3 2.46538 2.13672

Dear R I recently performed a cluster analysis. It produced the dendogram no problem but unfortunately the font size of the row.names were all cluttered due to their large size So I tried to change the font size using plclust(cluster.results, labels=iris$specie, cex=0.8) and R came back to me saying Error in plclust(cluster.results, labels = iris$specie, cex = 0.8) : unused argument(s)

Hi there: I have a question about generating mean value of a data.frame. Take iris data for example, if I have a data.frame looking like the following: --------------------- Sepal.Length Sepal.Width Petal.Length Petal.Width Species 1 5.1 3.5 1.4 0.2 setosa 2 4.9 3.0 1.4 0.2

Hi, I'm designing a experiment in order to compare the growing of several clones of a tree specie. It will be a complete randomized block design. How can I decide what model of mean comparision to choose? LSD, HSD,TukeyHSD, Duncan,...? Thanks in advance

Dear all, We have developed our own Affymetrix chip (Custom Express Array, PM-only with two species). I want to analyse the data with the limma package, but for that I need to built my own CDF package, probe package and built the filters to analyse one specie or another. I'm using the makeProbePackage available in the AnnotationDbi (for a R-2.13.0) but I got the following error message:

Hi, I'm trying to find out what threshold of indicator value in labadsv should be used to accept a specie as an indicator one? So far I assumed that indval=0.5 is high enough to avoid any mistakes but it was based only in my intuition. I'd be greatful for any advise best regards Agnieszka

I have code like this: data <- read.csv("test1.csv", stringsAsFactors=FALSE, header=TRUE) # Graph myplot=ggplot(data, aes(fill=condition, y=value, x=condition)) + geom_bar(position="dodge", stat="identity", width=0.5) + scale_fill_manual(values=c("#7b3294", "#c2a5cf", "#a6dba0", "#008837"))+

Hola everyone, I'm doing an analisys about abundance of a planctonic specie in Robinson Crusoe Islan and I am having a hard time just adding the superscripts and the 100 (one hundred) in the measure of abundance. Perhaps this is so basic to you, but I need to put the real unit of measure. Individuals / 100 cubic meters. I have been looking in websites and R-list and there is not any