similar to: Creating missingness in repeated measurement data

Dear useRs, Thanks for any advices # I do not know where are the examples how to mark groups # based on signal occurence in the additional variable: cf. variable c2, # How to calculate different calculations for groups defined by (split by occurence of c2 characteristic data) #First example of simple data #mexample 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17

Dear all, Could anyone help me figure out why bootstrap works for one of similar models but not for the other and how I can solve it? I am using R 2.11.1 in Windows and would like to get confidence intervals for my models A and B by bootstrapping. However, bootstrap gives expected output for the model A but not for B, which I found was puzzling because the structure of the models is

Hello All, My question is regarding the attached plot. I would like to have multiple transparent green bands running the length (yaxis) of the plot the width of which is determined by the green lines at y=0 in the plot. Can you suggest a way to do it? For those who can't or are unwilling to download the file the plot is at http://www.twitpic.com/ma8w0 Thanks!

Hello all, I have a .csv file like below. Tool,Step_Number,Data1,Data2... etc up to 100 columns. A,1,0,1 A,2,3,1 A,3,2,1 . . B,1,3,2 B,2,1,2 B,3,3,2 . . ...... so on upto 50 rows where the column "*Tool*" has distinct steps in second column "*Step_Number*",but both have same entries in Step_Number column. I want the output like below.

--- daemon/btrfs.c | 69 ++++++++++++++++++++++++++++++++++++++++++++++++++++ daemon/daemon.h | 1 + daemon/fs-min-size.c | 50 ++++++++++++++++++++++++++++++++++++- generator/actions.ml | 6 ++++- 4 files changed, 124 insertions(+), 2 deletions(-) diff --git a/daemon/btrfs.c b/daemon/btrfs.c index ddb029d..d2d85f3 100644 --- a/daemon/btrfs.c +++ b/daemon/btrfs.c @@ -2190,3 +2190,72

Hi Irucka, I tried it and was able to plot it without any errors.? Here, your code indicates you need two lines. temper[[i]][1] ?temper[[1]][1] # which is the column 1. ? Month 1???? 1 2???? 2 3???? 3 ?temper[[1]][2] #? Data1 #1?? 1.5 #2? 12.3 #3? 11.4 Suppose I use names(temper) instead of seq_along(temper) pdf("irucka.pdf") ?lapply(names(temper),function(i)

Hi, all What I want to do is to locate the range of a for-loop statement in a binary. For example, given a for-loop statement belows, for (stat1; stat2; stat3) { /* do something */ } Is it possible to get information about the range (binary address) of the above for-loop, say, 0x0100 - 0x0120. One idea comes up in my mind is adding passes to retrieve such information in LLVM, then use

Hi, I downloaded both gee and geepack, and I am trying to understand the differences between the two libraries. I used the same data and estimated the same model, with a correlation structure autoregressive of order 1. Surprisingly for me, I found very different results. Coefficients are slightly different in value but sometimes opposite in sign. Moreover, the estimate of rho (correlation

https://bugzilla.redhat.com/show_bug.cgi?id=755729 This bug reports that the error message printed by the resize2fs API calls (which comes directly from the resize2fs command) says: Please run 'e2fsck -f /dev/vda1' first. That command is not possible from guestfish (where it would be 'e2fsck-f' or 'e2fsck ... forceall:true'). Fixing that bug caused this bug:

Hello everyone... We were trying to implement the Newton-Raphson method in R, and estimate the parameters a and b, of a function, F, however we can't seem to implement this the right way. Hope you can show me the right way to do this. I think what we want R to do is to read the data from the website and then peform maxNR on the function, F. Btw the version of R being used is "RGui for

Dear list, I have a list of number sequences. Each number sequence has different numbers of elements. Is there a quick way (other than to iterate through the entire list) way to coerce list to matrix with NAs filling in the short sequences? An example of what I mean is this: A <- list(c(3,2,3),c(6,5)) I'd like to get A so that it is 3 2 3 6 5 NA Best, Ken

Hi, as a followup for the signature fix for mount_vfs [1], here it is a patch series to generate automatically all the OCaml interfaces of daemon actions. [1] https://www.redhat.com/archives/libguestfs/2018-April/msg00059.html Thanks, Pino Toscano (5): daemon: directly use Optgroups daemon: use the structs from the Structs module daemon: move Lvm.lv_canonical to new Lvm_utils module

Hi. This is likely a trivial problem but have not found a solution. Imagine the following dataframe: Lat Lon x1 x2 x3 01 10 NA NA .1 01 11 NA .2 .3 01 12 .4 .5 .6 I want to generate another column that consist of the first value in each row from columns x1 to x3. That is NewColumn .1 .2 .4 Any input greatly appreciated, Thanks, Camilo Camilo Mora, Ph.D.

In general, this is not possible. Consider, for example, the fact that various optimization passes may reorder the code, including such things as hoisting computations outside of the loop, and enclosing loops, scheduling those instructions before others that did not originate from source lines within the loop, etc. That's not to mention things like loop unrolling. That said, especially at low

Hi everyone- I have a dataset with multiple "pre" and "post" variables I want to compare. The variables are named "apple_pre" or "pre_banana" with the corresponding post variables named "apple_post" or "post_banana". The variables are in no particular order. apple_pre orange_pre orange_post pre_banana apple_post post_banana person_1

Hi >i have this data > X [1] 5.79 1579.52 2323.70 68.85 426.07 110.29 108.29 1067.60 17.05 22.66 [11] 21.02 175.88 139.07 144.12 20.46 43.40 194.90 47.30 7.74 0.40 [21] 82.85 9.88 89.29 215.10 1.75 0.79 15.93 3.91 0.27 0.69 [31] 100.58 27.80 13.95 53.24 0.96 4.15 0.19 0.78 8.01 31.75 [41] 7.35 6.50

In an effort to select the most appropriate number of clusters in a mixture analysis I am comparing the expected and actual membership of individuals in various clusters using the Fisher?s exact test. I aim for the model with the lowest possible p-value, but I frequently get p-values below 2.2e-16 and therefore does not get exact p-values with standard Fisher?s exact tests in R. Does anybody know

Hi List, I have one column of beginning dates and one column of ending dates, I want to find their difference. And I want to ignore the trailing zeros, basically everything after the first colon mark. Begin_date End_date 01JAN2000:00:00:00:000 02FEB2002:00:00:00:000 24MAR2012:00:00:00:000 18MAY2012:00:00:00:000 01OCT2003:00:00:00:000

[My previous message rejected, therefore I am sending same one with some modification] I have 3 vectors with object name : dat1, dat2, dat3 Now I want to create a loop, like : for (i in 1:3) { cat(sd(dati)) } How I can do this in R? Regards,

HI Elisa, You could use ?cut() vec1<-c(33,18,13,47,30,10,6,21,39,25,40,29,14,16,44,1,41,4,15,20,46,32,38,5,31,12,48,27,36,24,34,2,35,11,42,9,8,7,26,22,43,17,19,28,23,3,49,37,50,45) label1<-unlist(lapply(mapply(c,lapply(seq(0,45,5),function(x) x),lapply(seq(5,50,5),function(x) x),SIMPLIFY=FALSE),function(i) paste(i[1],"<x<=",i[2],sep="")))