Displaying 10 results from an estimated 10 matches similar to: "lapply with different size lists?"
2005 Dec 29
2
loop
Dear All,
I have to use loop over an array so I am using following procedure
count<-1
repeat{
count<-count + 1
c(g[count],1:i[count]) ->qw
if(count>5)break
}
as a result qw is
[1] 0.9643836 1.0000000 2.0000000 3.0000000 4.0000000 5.0000000
[7] 6.0000000 7.0000000 8.0000000 9.0000000 10.0000000 11.0000000
[13] 12.0000000 13.0000000 14.0000000 15.0000000 16.0000000
2013 Mar 14
1
ggplot2 problem
Hello all!
I have a problem with ggplot2 library. I want to do an heat map and the y
variables are the year months. If I use the following code, he y values are
in alphabetical order, but I want it in month order.
The code is:
library(reshape)
library(ggplot2)
library(scales)
p <- ggplot(data.m, aes(variable, Month)) + geom_tile(aes(fill = value),
2006 Feb 06
2
novice questions about programming in "R"
folks,
I have been struggling with the "R" documentation for too long now and
I need a simple answer on two questions. The documentation does not
have adequate examples. Please help.
given two equal vector lists:
A <- c(0,1,2,3)
B <- c(5,6,7,8)
[Question #1]
how do I dump them to a text file with the following format:
2007 Jan 30
2
Rbind for appending zoo objects
Hi R,
y1 <- zoo(matrix(1:10, ncol = 2), 1:5)
colnames(y1)=c("a","b")
y2 <- zoo(matrix(rnorm(10), ncol = 2), 6:10)
colnames(y2)=c("b","a")
> y1
a b
1 1 6
2 2 7
3 3 8
4 4 9
5 5 10
> y2
b a
6 0.9070204 0.3527630
7 1.2405943 0.8275001
8 -0.1690653 -0.1724976
9 -0.6905223 -1.1127670
10
1998 Sep 25
1
format(numericmatrix, ...) : proposal for a change
Since format, i.e., format.default(.), is a pretty basic function I
thought I'd ask before just changing it...
aa <- cbind(1:7, rnorm(7))
format(aa)
or
format(aa, digits=7)
looks like
[,1] [,2]
[1,] " 1.0000000" " 0.2406669"
[2,] " 2.0000000" "-0.4973221"
[3,] " 3.0000000" " 0.4672260"
[4,] "
2017 Nov 16
3
Manera eficiente de añadir el valor anterior por grupo
Buenas
Tengo un Data table de la siguiente manera:
datos<-data.table(grupo=rep(c("a","b"),5),x=c(1:10),y=rnorm(10,2,1))
Lo que quiero es añadir una fila por cada grupo y en esa nueva fila, al valor de la x ponerle el valor anterior de la y
Lo que hago es añadir una nueva fila por grupo, con:
datos[,.SD[1:(.N+1)],by=grupo]
Y para añadir el valor anterior uso la función
2005 Jun 07
1
Help with possible bug (assigning NA value to data.frame) ?
There's something peculiar that I do not understand here. However, did you
realize that the thing you are assigning into parts of `a' is NULL? Check
you're my.test.boot.ci.1: It's NULL.
Be that as it may, I get:
> a <- data.frame(matrix(1:4, nrow=2), X3=NA, X4=NA)
> a
X1 X2 X3 X4
1 1 3 NA NA
2 2 4 NA NA
> a[a$X1 == 1,]$X3 <- NULL
> a
X1 X2 X3 X4
1 1
2014 Jun 24
4
asignacion de un valor a un elemento de una lista
Buen dia!
Queria saber si siendo l3 una lista,
no se puede asignar un valor a un elemento de una lista?!!!
l3[[1]][1,5]<-5
eso no vale?
--
"Abraza la incertidumbre, es un intento de tener una filosofía de vida para
agarrarme de algo e ir naufragando en la vida de alguna manera. Encarar a
ciegas, y generar incertidumbres en el proyectar."
J.I.S.
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2005 Jun 07
0
Help with possible bug (assigning NA value to data.frame)?
This 'strange behaviour' manifest itself within some quite complex
code. When I created a *very* simple example the behaviour dissapeared.
Here is the simplest version I have found which still causes the strange
behaviour (it could be quite unrelated to the boot library, however).
library(boot)
## boot statistic function
my.mean.s <- function(data,subset){
mean(data[subset])
}
2013 May 04
2
Lasso Regression error
Hi all,
I have a data set containing variables LOSS, GDP, HPI and UE.
(I have attached it in case it is required).
Having renamed the variables as l,g,h and u, I wish to run a Lasso
Regression with l as the dependent variable and all the other 3 as the
independent variables.
data=read.table("data.txt", header=T)
l=data$LOSS
h=data$HPI
u=data$UE
g=data$GDP
matrix=data.frame(l,g,h,u)