similar to: Why the error is coming, can anyone help?

Hello, Say all the below five vectors should have same elements in any situation. How to find the non matching vectors among these five, if so how we can find the non matching elements of those vectors? Can anyone help? a=c(1,2,3) b=c(1,2,3,4) c=c(1,2,3) d=c(1,2,3) e=c(1,4,5) identical(a,b,c,d,e) Visit us at Booth No. 5 at 2012 ChemOutsourcing Conference, 10-13 Sept 2012, Ocean Place Resort -

Why the error is coming? even though the length of outcome.new$compkey and outcome.new$armkey were exactly same. Can anyone help? setwd("D:/AZ") library("RODBC") cdb_cnct <- odbcConnectExcel("AZIF_DC_GVK_NSCLC_MSALL_287papers_02072012_141450_v1_4.xls") outcomes <- sqlFetch(cdb_cnct, "Outcomes_info") odbcClose(cdb_cnct) rm(cdb_cnct)

In this following example Id 4 is duplicated with Id 1. Like this I want both Ids (Duplicated and Duplicated with). Can anyone help? df <- data.frame( "Publication" = c(1, 2, 3, 1, 4, 5, 2, 3), "Reference" = c("a", "b", "c", "a", "d", "e", "b", "c"), "Id"= c(1, 2, 3, 4,

After importing data from Excel through ODBC. In the inclusion dataset, class(inclusion$Value) is coming as factor. After filtering the data, length(inclusion$Value == 0),the answer is coming as 4879, but actually Value contains only 225 rows. So how can I get the length as 225. Can anyone help? setwd("D:/AZ") library("RODBC") cdb_cnct <-

x=c(5, 8, 28, 29, 30) y=c(5, 8, 28, 29, 31) How can we compare these two vectors, whether each element is exactly matched with the elements in the other vector ? How can we get the non matched elements from both the vectors? Can anyone help? ________________________________ Notice: The information contained in this electronic mail message is intended only for the use of the designated recipient.

df <- data.frame ( "RowId" = 4:7, "x"=c("1_1", "2_2", "3_3", "3_3"), "y"=c("1_1", "3_3", "2_2", "3_3") ) How can we compare corresponding values of x and y (first value of x exacly matches with the first value of y)? If they were not matced

Why the result is coming as NULL. Can anyone help. I want to find the outliers for a reference setwd("D:/AZ") library("RODBC") cdb_cnct <- odbcConnectExcel("Book1.xls") cdb_frame <- sqlFetch(cdb_cnct, "Sheet1") odbcClose(cdb_cnct) rm(cdb_cnct) x<- cdb_frame$Publication >=1990 & cdb_frame$Publication <=2012 invalid <- cdb_frame[!x,

Suppose I want the output as "Trial and a sheet" without quotes x=c("a", "b", "c") print("Trial and x[1] sheet") Getting "Trial and x[1] sheet" Can anyone help? Notice: The information contained in this electronic mail message is intended only for the use of the designated recipient. This message is privileged and confidential. and the

a=c(1,2,3) b=c(23, 24, 25) x=c("a", "b") #if (length(x[1]) == 0) {cat("x[1] is having 3 elements")} Suppose I want to send the vector a into the Object A, um getting only "a" as the ouput for Object A but not getting required output as the vector with the elements 1, 2, 3 with the following code A<- x[1] How to code it? Can anyone help? Notice: The

Hi Everyone, Can anyone help why the errors are coming and rectify it? invalid.ids <- c(1,3,5) if (length(invalid.ids)==0) { cat("No Errors found") } else {

Even though the sheet name Publication exists. The error is coming. Can anyone help? library("RODBC") cdb_cnct <- odbcConnectExcel("Copy of AZIF_DC_GVK_NSCLC_MSALL_287papers_02072012_141450_v1_4.xls") cdb_frame <- sqlFetch(cdb_cnct, "Publication") odbcClose(cdb_cnct) Error in odbcTableExists(channel, sqtable) : 'Publication': table not found on

key1.=c(1, 2, 3) key2.=c(2) if (identical(key1.,key2.) == "TRUE") { cat("No Errors found") } if (length(setdiff(key1., key2.)) !=0) {

Hi All, Can you please help me, why this code in not generating line chart? library(ggplot2) par(mfrow=c(1,3)) #qplot(TIME1, BASCHGA, data=Orange1, geom= c("point", "line"), colour= ACTTRT) unique(Orange1$REFID) -> refid for (i in refid) { Orange2 <- Orange1[i == Orange1$REFID, ] pdf('PGA.pdf') qplot(TIME1, BASCHGA, data=Orange2, geom= c("line"),

I''m writing a bloggish/CMSish thing. I had been using simple_format, but my users requested a rich editor, so I added TinyMCE. Anyway, I was trying to migrate the existing content (since TinyMCE assumes it''s reading HTML-formatted text), and realized that I couldn''t call simple_format (or other helper methods) from Migrations. Can someone enlighten me here?

Hi all, A small problem raising. Suppose the follow raw data is stored in a csv file. And the error is coming as NULL with the following code. Can you please help? Thank you in advance. SUBJCET 9999 9999 9999 9999 9999 1Ito 1Ito 1Ito 1Ito 1Ito 1Ito 9999 9999 9999 9999 read.csv("Noname3.csv") -> FD FD$SUBJECT NULL Regards Devarayalu [[alternative HTML version

Hello, I am just starting off with Rails, so I apologize in advance if there is a terribly obvious answer to my problem. I''ve done some searching and found similar problems to my own, but nothing which yielded a solution. I have a handful of models that I am unit testing. The tests for each unit run successfully, but when I do a rake test, many of the tests fail. The assertions that

This is probably easy for experienced users but I could not find a solution. I have several R scripts that process several columns of a dataframe (several dataframes and columns actually, but simplified for my question). References such as: myDF$myCol are all over. I like to automate this for other dataframes and columns by defining a reference only once in the beginning of the script. One

Suppose I have "Orange1" data like this. TIME1 RESPONSE RESPSTAT RESPUT REFID ARM SUBARM 0 299.5 Mean 8-item scale 68 0 0 0 287 Median 8-item scale 68 0 0 0 303.9 Mean 8-item scale 68 1 0 0 286 Median 8-item scale 68 1 0 0 295 Mean 8-item scale 85 0 0 12 254 Mean 8-item scale 85 0 0 0 287 Mean 8-item scale 85 1 0 12 216 Mean

Hello I am fitting a Cox PH model using the function coxph(). Does anyone know how to obtain the estimate of the covariance matrix under the null hypothesis. The function coxph.detail() does not seem to be useful for this purpose. Thanks, KD. [[alternative HTML version deleted]]

Hello R users, I am a fairly new R user, however, one of the problems I am having is the use of applying if-, and-, then-, else- statements in R against datasets & dataframe. Rtips mentions it, but without simple examples I am not quite sure what my syntax should look like. I am particularly interested in syntax that can be used with the transform function. for example if foo[,1] ==