similar to: [Fwd: Re: kinit]

I think the main bit of the puzzle that's missing for klibc integration at this point, other than the kbuild bits, is a kinit that's a true replacement for prepare_namespace() and everything south of it in init/main.c. This means that it should be able to replace all that code and any code that's removed from it, totalling about 6000 lines of kernel code. The kinit that's

Hi everybody, I'd like to have a list with two elements, where both elements have the same value: z <- list(a=1, b=1) If it happens, that I've to change the value, I've to assure that I change both. This is error prone. Hence, a better way to achieve this is to define: tmp <- 1 z <- list(a=tmp, b=tmp) Now, I'm wondering if it is possible to make this more compact: z

Dear all, I want to use aggregate.formula to conveniently summarize a data.frame. I have quiet some variables in the data.frame and thus I don't want to write all these names by hand, but instead create them on the fly. This approach has the advantage that if there will be even more columns in the data.frame I don't have to change the code. I've hence tried to construct a formula

Dear all, Is there a reason, why there is no +-operator for aes (i.e. uneval) objects (as there is for themes and gg objects)? I had a couple of cases where such an operator would be useful, for instance to combine the result of aes and aes_string in functions. Any flaws with the following proposition: `+.uneval` <- function(e1, e2) { dup <- names(e1) %in% names(e2) if (any(dup)) {

Dear all, I want to get a series of boxplots (grouped by two factors) and I want to overlay the original observations and the following code does almost what I want: library(ggplot) ddf <- data.frame(x=factor(rep(LETTERS[1:4], each=30)), y = runif(120,0,10), grp = factor(rep(rep(1:3, 10), 4))) ggplot(ddf, aes(x, y, colour=grp)) + geom_boxplot() + geom_point() Yet the position of the points

Dear all, Assume that I have the following data structure: d <- expand.grid(subj=1:5, time=1:3, treatment=LETTERS[1:3]) d$value <- 10 ^ (as.numeric(d$treatment) + 1) + 10 * d$subj + d$time d$value2 <- 100000 + d$value where d$treatment == "C" stands for my control group. What I want to achieve now is to subtract the values corresponding to d$treatment == "C" from

Dear all, I produced the following graph with ggplot which is almost fine, yet I don't like that the legend for "Means" and "Observations" includes a line, though no line is used in the plot for those two (the line for "Overall Mean" on the other hand is wanted): library(ggplot2) ddf <- data.frame(x = factor(rep(LETTERS[1:2], 5)), y = rnorm(10)) p <-

i'm somehow embarrassed to even ask this, but is there any built-in method for doing this: my_list <- list() my_list[[1]] <- matrix(1:20, ncol = 5) my_list[[2]] <- matrix(20:1, ncol = 5) now, knowing that these matrices are identical in dimension, i'd like to unfold the list to a 2x4x5 (or some other permutation of the dim sizes) array. i know i can initialize the array, then

Hi everybody, currently I'm working on two packages, where I've included a <package-name>-package.Rd documentation file (with \docType set to "package") in each case. When I run "R CMD check" everything works fine, and a call to "R CMD install" generates the appropriate html, text and pdf documentation. While the package documentation (generated

Hello, I am interesting in using R from a web application, for basic statistics and plots. The server is Java-based (tomcat). The simplest solution is a system call that generates the text or the image, then the servlet forwards the output. This can be done from any language, but it is quite inelegant and slow for the initialization time. Is there any package or approach for accessing R from a

In Mathematica there is a neat feature, where you can change the head of a list from "list" to say "+" and obtain a sum of the list elements. I can't find a way to sum a list of vectors of same length or list of matrices of the same dimension and was curious if something like that exists in R. do.call("+",list) doesn't work because "+" accepts only

Hello, I feel that the klibc package should include an insmod that can be used on an initramfs. While it is possible to use an insmod built statically against glibc, such a binary is (comparatively) huge at 565K. The attached insmod.c is essentially the insmod.c from module-init-tools minus a couple of lines related to calling the old (2.4) version of insmod for backward compat. BTW: Insmod

I want to interlace two vectors. This I can do: > x <- 1:4 > z <- x+0.5 > as.vector(t(cbind(x,z))) [1] 1.0 1.5 2.0 2.5 3.0 3.5 4.0 4.5 but this seems rather inelegant. Any suggestions? Murray -- Dr Murray Jorgensen http://www.stats.waikato.ac.nz/Staff/maj.html Department of Statistics, University of Waikato, Hamilton, New Zealand Email: maj at waikato.ac.nz

Am I correct in believing that one cannot match on multiple columns? One can indeed subset on multiple criteria from different variables (or columns) but not from unique combinations thereof. I need to exclude about 10000 rows from 108000 rows of data based on several unique combinations of identifiers in two columns. Only merge() seems to be able to do that. Merge would allow me to positively

Dear Help, Suppose I have a character vector. x <- c("Bob", "loves", "Sally") I want to combine it into a single string: "Bob loves Sally" . paste(x) yields: paste(x) [1] "Bob" "loves" "Sally" The following function combines the character vector into a string in the way that I want, but it seems somewhat inelegant.

I'm a great fan of read.table(), but this time the data had a lot of cruft. So I used readLines() and editted the char vector to eventually get something like this: " 23.4 1.5 4.2" " 19.1 2.2 4.1" and so on. To get that into a 3 col numeric table, I first just used: writeLines(data,"tempfile")

I would like to do something like the following: Fancyhist<-function(x,...) { # first, process x into xprocess somehow, then ... if (is.null(breaks)) { # yes, I know this is wrong # define the histogram breaks somehow, then call hist: hist(xprocess,breaks=breaks,...) } else { # use breaks give in calling argument hist(xprocess,...) } } But, those of you who know R better

AARRGGHH! Sometimes it's the simple things that are particularly frustrating, especially late at night.... Can anyone suggest a simple means for replacing all of the zero values in a matrix with NANs? I ended up writing an awk script to massage the input file, which works, of course, but is rather an inelegant blunt instrument. I'd prefer an R operation. I'm certain that

Hello, If I make a plot, say something simple like plot( runif(100) ) then the origin (0,0) is not at the bottom-left corner of the box surrounding the plot. The axis limits are "padded" slightly. This is ordinarily a good feature, because it makes plots look better. But now I would like to make a plot with the origin exactly on the bottom left. Through trial and error, I have

I would like to create a method for the generic function "with" applied to a class of fitted models. The method should do two things: 1. Substitute the name of the first argument for '.' throughout the expression 2. Evaluate the modified expression using the data argument to the fitted model as the first element of the search list. The second part is relatively easy. The