Displaying 20 results from an estimated 9000 matches similar to: "?nchar ?strsplit"
2012 Aug 31
7
splits with 0s in middle columns
Hi,
A column of my df looks like
A
10/20/30
40/20
60/10/10/5
80/10
I want to split it such that the last column has the last composition and if there are not enough the middle columns get the 0s. That way my df would look like
A1 A2 A3 A4
10 20 0 30
40 0 0 20
60 10 10 5
80 0 0 10
How can I do that ??
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2005 May 30
4
Very simple traffic shaping script for H.323
Hello -
What I want to do seems very simple - I want to make sure any H.323
traffic gets processed before anything else entering or leaving this
network. The network has a videoconferencing device on the LAN at
192.168.16.4. A Linux firewall NATs an external IP Address to this
internal address and I have appropriate SNAT and DNAT rules that work.
The NAT and connection tracking rules all work
2012 Aug 16
8
How to extract from a column in a table?
Hi,
I have a table in which one column has the name of the objects as shown below.
Name
Budlamp-Woodcutter Complex - 15 to 60% slope (60/25/15)
Budlamp-Woodcutter Complex - 15 to 60% slope (60/25/15)
Terrarossa-Blacktail-Pyeatt Complex - 1 to 40% slope (40/35/15/10)
Terrarossa-Blacktail-Pyeatt Complex - 1 to 40% slope (40/35/15/10)
How can I split the single column into three columns
2011 Dec 01
2
Counting the occurences of a charater within a string
I am new to R but am experienced SAS user and I was hoping to get some help on counting the occurrences of a character within a string at a row level.
My dataframe, x, is structured as below:
Col1
abc/def
ghi/jkl/mno
I found this code on the board but it counts all occurrences of "/" in the dataframe.
chr.pos <- which(unlist(strsplit(x,NULL))=='/')
chr.count <-
2012 Aug 20
7
relating data in two data frames
Hi,
My data.frame "A" has FID like this
FID
a
a
b
b
b
c
c
d
d
d
d
Now my second data.frame "B" has age value for a, b, c, d like
FID Age
a 5
b 7
c 9
d 3
How can search for the Age column in "B" and replace the values in "A" so that my new "A" looks like this
FID Age
a 5
a 5
b 7
b 7
b 7
2012 Aug 28
7
check and verify
Hi,
I have 6 columns in my dataframe (test)
A B C D E F
a b c d 40 30
a f a b 20 10
x m y m 50 30
If character value in column A matches with that in column C, it gets the percentage in column E, similarly if value in column B matches the value in D, it gets the percentage in F column. If it doesn't match, it gets 0 percentage.
How can I do that ?
thanks
[[alternative HTML version
2012 Aug 27
6
find and replace
I have 5 (A,B,C,D,E) columns in my dataframe. I want to replace all "x" with "y" and all "a" with "b" within these 5 columns. Can I do it in one step?
Thanks
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2012 Aug 29
4
Use or ??
Hi, My data frame looks like
A B C
a b a
x y z
I want to add a new column which says "y" if either A or B matches with C and "n" if there is no match. How can I do that?
Thanks
[[alternative HTML version deleted]]
2012 Oct 02
2
add values in one column getting range from other column
Hi,
My dataframe has two columns one with area and other with percent. How can i add the areas that are within a range of percentage??
My dataframe looks like
Area Percent
456 0
3400 10
79 25
56 18
467 0
67 67
839 85
1120 0
3482 85
I want to add the area for values whose percent is <0, 0-25, 25-50, 50-75, >75. How
2012 Jul 11
4
MODE , VARIANCE , NTH PERCENTAILE
Hi,
Here i have an matrix like this,
ABC PQR XYZ MNO
------ ------- ------ --------
3 6 7 15
2 12 24 15
20 5 1 2
25 50 15 35
i need to get the
"MODE" - for each column-wise
"VARIANCE" - for
2012 May 25
4
Hash Table - Select and Change Data iniside Matrix
Hi,
Here i have been a matrix like this,
*NAME AGE PALCE TRUE/FALSE*
ABC 20 INDIA
XYZ 30 FRANCE
PQR 40 USA
MNO 30 KENIYA
DEF 25 AUSTRALIA
Here,* TRUE/FALSE* Column containing empty values.
So my requirement what is , need to change all the *TRUE/FALSE *column value
into "*TRUE*" where *AGE =
2012 May 28
2
Hash Table - Select and Change Data iniside Matrix Using "Between"
Hi,
Here i have been an matrix like this,
*NAME AGE PALCE TRUE/FALSE*
ABC 20 INDIA
XYZ 30 FRANCE
PQR 40 USA
MNO 30 KENIYA
DEF 25 AUSTRALIA
GTY 34 CANADA
BNH 38 JAPAN
Here, *TRUE/FALSE *Column containing empty values.
So my requirement what is, need to change all the TRUE/FALSE
2015 May 22
5
[Bug 2404] New: scp skips file/directory on permissions error
https://bugzilla.mindrot.org/show_bug.cgi?id=2404
Bug ID: 2404
Summary: scp skips file/directory on permissions error
Product: Portable OpenSSH
Version: 6.7p1
Hardware: All
OS: All
Status: NEW
Severity: major
Priority: P5
Component: scp
Assignee: unassigned-bugs at mindrot.org
2009 Oct 02
3
break up a string into strings with a fixed length
dear all,
I have some very long strings and would like to break up each long string
into multiple strings with a fixed length, e.g. to break up
abcdefghijkl
into
abc, def, ghi, jkl
I tried a couple of commands but was not successful. Any help will be
appreciated.
Best,
Jimmy
--
View this message in context:
2012 May 29
2
Use variable inside Function for updating the matrix
Hi,
Here i have a data frame like this,
frame name is "dat"
*NAME AGE ELIGIBLE*
A 20
B 14
C 35
D 10
E 50
In this, i want to change the column '*ELIGIBLE*' status to '*YES*' If, AGE
between 18 to 35
Which means that, i should get a put like
2016 Oct 04
1
error handling in strcapture
It is also not catching the cases where the number of capture expressions
does not match the number of entries in proto. I think all of the
following should give an error about the mismatch.
> strcapture("(.)(.)", c("ab", "cde", "fgh", "ij", "lm"),
proto=list(A="",B="",C=""))
A B C
1 a b cd
2 d
2013 Nov 18
3
Sending a matrix in an email
I have a matrix which has colnames and I would like to send this matrix using sendmailR. How can I convert this simple matrix to a format which can be used as the body variable in sendmailR? I see how I can create a file attachment using mime_part but I would like to send the matrix in the body of the email.
The matrix looks like:
ABD DEF GHI JKL MNO TOT
[1,] 0.44 0.81 1.67 0.37
2008 Oct 29
6
substring/strsplit question
Dear R People:
Here is a toy example:
> x <- c("2E","5W","12H")
> substr(x,2,2)
[1] "E" "W" "2"
>
Sometimes x has 3 elements, sometimes 2. I want to extract the last
element, and then extract the other 1 or 2 elements.
How can I do this, please?
TIA,
Sincerely,
Erin
--
Erin Hodgess
Associate Professor
Department of
2013 Apr 29
2
Adding elements in data.frame subsets and also subtracting an element from the rest elements in data.frame
Dear R forum
I have a data.frame as
cashflow_df = data.frame(instrument = c("ABC","ABC","ABC","ABC","ABC","ABC","ABC","ABC","ABC","ABC","ABC","ABC","ABC","ABC", "ABC", "PQR", "PQR",
2011 Oct 18
1
Function to "lump" factors together?
Sorry about the odd terminology, but I suspect that my intent might be
completely missed had I used "aggregate" or "classify" (each of which
appears to have some rather special meanings in statistical analysis and
modeling).
I have some data about software builds; one of the characteristics of
each is the name of the branch.
A colleague has generated some fairly interesting