similar to: ?nchar ?strsplit

Hi, A column of my df looks like A 10/20/30 40/20 60/10/10/5 80/10 I want to split it such that the last column has the last composition and if there are not enough the middle columns get the 0s. That way my df would look like A1 A2 A3 A4 10 20 0 30 40 0 0 20 60 10 10 5 80 0 0 10 How can I do that ?? [[alternative HTML version deleted]]

Hello - What I want to do seems very simple - I want to make sure any H.323 traffic gets processed before anything else entering or leaving this network. The network has a videoconferencing device on the LAN at 192.168.16.4. A Linux firewall NATs an external IP Address to this internal address and I have appropriate SNAT and DNAT rules that work. The NAT and connection tracking rules all work

Hi, I have a table in which one column has the name of the objects as shown below. Name Budlamp-Woodcutter Complex - 15 to 60% slope (60/25/15) Budlamp-Woodcutter Complex - 15 to 60% slope (60/25/15) Terrarossa-Blacktail-Pyeatt Complex - 1 to 40% slope (40/35/15/10) Terrarossa-Blacktail-Pyeatt Complex - 1 to 40% slope (40/35/15/10) How can I split the single column into three columns

I am new to R but am experienced SAS user and I was hoping to get some help on counting the occurrences of a character within a string at a row level. My dataframe, x, is structured as below: Col1 abc/def ghi/jkl/mno I found this code on the board but it counts all occurrences of "/" in the dataframe. chr.pos <- which(unlist(strsplit(x,NULL))=='/') chr.count <-

Hi, My data.frame "A" has FID like this FID a a b b b c c d d d d Now my second data.frame "B" has age value for a, b, c, d like FID Age a      5 b      7 c      9 d      3 How can search for the Age column in "B" and replace the values in "A" so that my new "A" looks like this FID Age a      5 a      5 b      7 b      7 b      7

Hi, I have 6 columns in my dataframe (test) A B C D E F a b c d 40 30 a f a b 20 10 x m y m 50 30 If character value in column A matches with that in column C, it gets the percentage in column E, similarly if value in column B matches the value in D, it gets the percentage in F column. If it doesn't match, it gets 0 percentage. How can I do that ? thanks [[alternative HTML version

I have 5 (A,B,C,D,E) columns in my dataframe. I want to replace all "x" with "y" and all "a" with "b" within these 5 columns. Can I do it in one step? Thanks [[alternative HTML version deleted]]

Hi, My data frame looks like A B C a b a x y z I want to add a new column which says "y" if either A or B matches with C and "n" if there is no match. How can I do that? Thanks [[alternative HTML version deleted]]

Hi, My dataframe has two columns one with area and other with percent. How can i add the areas that are within a range of percentage?? My dataframe looks like Area Percent 456       0 3400      10 79          25 56           18 467         0 67          67 839        85 1120      0 3482      85 I want to add the area for values whose percent is <0, 0-25, 25-50, 50-75, >75. How

Hi, Here i have an matrix like this, ABC PQR XYZ MNO ------ ------- ------ -------- 3 6 7 15 2 12 24 15 20 5 1 2 25 50 15 35 i need to get the "MODE" - for each column-wise "VARIANCE" - for

Hi, Here i have been a matrix like this, *NAME AGE PALCE TRUE/FALSE* ABC 20 INDIA XYZ 30 FRANCE PQR 40 USA MNO 30 KENIYA DEF 25 AUSTRALIA Here,* TRUE/FALSE* Column containing empty values. So my requirement what is , need to change all the *TRUE/FALSE *column value into "*TRUE*" where *AGE =

Hi, Here i have been an matrix like this, *NAME AGE PALCE TRUE/FALSE* ABC 20 INDIA XYZ 30 FRANCE PQR 40 USA MNO 30 KENIYA DEF 25 AUSTRALIA GTY 34 CANADA BNH 38 JAPAN Here, *TRUE/FALSE *Column containing empty values. So my requirement what is, need to change all the TRUE/FALSE

https://bugzilla.mindrot.org/show_bug.cgi?id=2404 Bug ID: 2404 Summary: scp skips file/directory on permissions error Product: Portable OpenSSH Version: 6.7p1 Hardware: All OS: All Status: NEW Severity: major Priority: P5 Component: scp Assignee: unassigned-bugs at mindrot.org

dear all, I have some very long strings and would like to break up each long string into multiple strings with a fixed length, e.g. to break up abcdefghijkl into abc, def, ghi, jkl I tried a couple of commands but was not successful. Any help will be appreciated. Best, Jimmy -- View this message in context:

If I have this object: x <- c("abc\ndef", "", "ghi") and I write it to a file using `writeLines(x, "test.txt")`, my text editor sees a 5 line file: 1: abc 2: def 3: 4: ghi 5: which is what I'd expect: the last line in the editor is empty. If I use `readLines("test.txt")` on that file, I get the vector

Thanks to Rui, Peter and Tanvir! Peter's seems to be the fastest of the 3 suggestions so far on the little test case, but on the real data (where x contains several thousand lines), Rui's seems best. Duncan On 2025-02-05 9:13 a.m., peter dalgaard wrote: > This also seems to work: > >> strsplit(paste(x,collapse="\n"),"\n")[[1]] > [1] "abc"

Hi, Here i have a data frame like this, frame name is "dat" *NAME AGE ELIGIBLE* A 20 B 14 C 35 D 10 E 50 In this, i want to change the column '*ELIGIBLE*' status to '*YES*' If, AGE between 18 to 35 Which means that, i should get a put like

A 3rd option could be scan(text=x, what="", blank.lines.skip=FALSE) (all because readLines() doesn't obey the text=x convention, perhaps it should? I'm unsure whether the textConnection is left open in Rui's method.) -pd > On 5 Feb 2025, at 15:35 , Duncan Murdoch <murdoch.duncan at gmail.com> wrote: > > Thanks to Rui, Peter and Tanvir! Peter's seems

This also seems to work: > strsplit(paste(x,collapse="\n"),"\n")[[1]] [1] "abc" "def" "" "ghi" > On 5 Feb 2025, at 14:44 , Duncan Murdoch <murdoch.duncan at gmail.com> wrote: > > If I have this object: > > x <- c("abc\ndef", "", "ghi") > > and I write it to a file

It is also not catching the cases where the number of capture expressions does not match the number of entries in proto. I think all of the following should give an error about the mismatch. > strcapture("(.)(.)", c("ab", "cde", "fgh", "ij", "lm"), proto=list(A="",B="",C="")) A B C 1 a b cd 2 d