similar to: Error in if (n > 0)

Displaying 20 results from an estimated 400 matches similar to: "Error in if (n > 0)"

2009 Jul 21
1
package quantreg behaviour in weights in function rq,
Dear all, I am having v.4.36 of Quantreg package and I noticed strange behaviour when weights were added. Could anyone please explain me what if the results are really strange or the behavioiur is normal. As an example I am using dataset Engel from the package and my own weights. x<-engel[1:50,1] y<-engel[1:50,2] w<-c(0.00123, 0.00050, 0.00126, 0.00183, 0.00036, 0.00100, 0.00122,
2003 May 20
0
intermittent failure of ability to connect to samba share from win (NT/2k) client
First, my installation is samba 2.2.8 running as a daemon (not inetd) on Solaris 8 configured to use a WINS server and provide authentication via a PDC (same host as WINS server). I do have an lmhosts file in the samba /lib directory with the PDC/WINS server address in it. My globals section; [global] workgroup = WORKGROUP netbios name = SAMBASERVER security =
2005 Nov 27
1
the output of coxph
Dear All: I have some questions about the output of coxph. Below is the input and output: ---------------------------------------- > coxph(formula = Surv(futime, fustat) ~ age + rx + ecog.ps, data = + ovarian, x = TRUE) Call: coxph(formula = Surv(futime, fustat) ~ age + rx + ecog.ps, data = ovarian, x = TRUE) coef exp(coef) se(coef) z p age 0.147 1.158
2003 May 23
0
intermittent failure of ability to connect to samba share from win (NT/2k) client]]
I am not sure if your problem is similar to what we have just experienced. we are using samba 2.2.3a-12.3 on debian with winxp sp1 clients we are using roaming profiles first logon after reboot fails sortof Windows cannot find a server copy of roaming profile will logon with local profile funny thing we never saw any activity in hostname.log (seperate smb.log for each machine) smbstatus showed
2006 Jun 13
2
Garch Warning
Dear all R-users, I wanted to fit a Garch(1,1) model to a dataset by: >garch1 = garch(na.omit(dat)) But I got a warning message while executing, which is: >Warning message: >NaNs produced in: sqrt(pred$e) The garch parameters that I got are: > garch1 Call: garch(x = na.omit(dat)) Coefficient(s): a0 a1 b1 1.212e-04 1.001e+00 1.111e-14 Can any one
2025 Mar 27
1
Problem with minimization that I failed to understand
My code is to minimize the objective function therefore, shouldnt I expect that StartingValue = c(0.12, 0.04, 0.07, 0.03, 0.06, 0.07, 0.07, 0.04, 0.09, 0.08, 0.02, 0.02, 0.03, 0.06, 0.02, 0, 0.07, 0.05, 0.02, 0.02, 0.02) Fn(q1$par) < Fn(StartingValue) ## FALSE Below is the corrected code that can be reproduced: MyDat = structure(list(c(50L, 0L, 0L, 50L, 75L, 100L, 50L, 0L, 50L, 0L, 25L,
2012 Oct 07
1
Why do I get different results for type III anova using the drop1 or Anova command?
Dear experts, I just noticed that I get different results conducting type III anova using drop1 or the Anova command from the car package. I suppose I made a mistake and hope you can offer me some help. I have no idea where I got wrong and would be very grateful for explaination as R is new terrain for me. If I run the commands in line, they produce the same results. But if I run them in
2025 Mar 27
1
Problem with minimization that I failed to understand
?s 19:36 de 27/03/2025, Daniel Lobo escreveu: > My code is to minimize the objective function > > therefore, shouldnt I expect that > > StartingValue = c(0.12, 0.04, 0.07, 0.03, 0.06, 0.07, 0.07, 0.04, 0.09, > 0.08, 0.02, 0.02, 0.03, 0.06, 0.02, 0, 0.07, 0.05, 0.02, 0.02, 0.02) > Fn(q1$par) < Fn(StartingValue) > ## FALSE > > Below is the corrected code that can
2025 Mar 27
1
Problem with minimization that I failed to understand
?s 18:35 de 27/03/2025, Daniel Lobo escreveu: > Hi, > > I have below minimization problem > > > MyDat = structure(list(c(50L, 0L, 0L, 50L, 75L, 100L, 50L, 0L, 50L, 0L, > 25L, 50L, 50L, 75L, 75L, 75L, 0L, 75L, 75L, 75L, 0L, 25L, 75L, > 75L, 0L, 75L, 100L, 0L, 25L, 100L), c(75L, 0L, 0L, 50L, 100L, > 50L, 75L, 75L, 100L, 25L, 0L, 25L, 100L, 0L, 50L, 0L, 25L, 25L, >
2025 Mar 28
1
Problem with minimization that I failed to understand
I haven't run your code, but since Kendall correlation is based on ranks, your Fn is probably locally constant with jumps when the ranks change. That's a really hard kind of function to maximize, and the algorithm used by fmincon is not appropriate to do it. Sorry, but I don't know if there is an R function that can do constrained discrete maximization. Duncan Murdoch On
2025 Mar 27
2
Problem with minimization that I failed to understand
Hi, I have below minimization problem MyDat = structure(list(c(50L, 0L, 0L, 50L, 75L, 100L, 50L, 0L, 50L, 0L, 25L, 50L, 50L, 75L, 75L, 75L, 0L, 75L, 75L, 75L, 0L, 25L, 75L, 75L, 0L, 75L, 100L, 0L, 25L, 100L), c(75L, 0L, 0L, 50L, 100L, 50L, 75L, 75L, 100L, 25L, 0L, 25L, 100L, 0L, 50L, 0L, 25L, 25L, 100L, 75L, 0L, 0L, 0L, 50L, 0L, 75L, 75L, 0L, 50L, 25L), c(50L, 0L, 0L, 0L, 100L, 25L, 0L, 0L,
2025 Mar 28
1
Problem with minimization that I failed to understand
?s 13:59 de 28/03/2025, Daniel Lobo escreveu: > Hi Duncan, > > Thanks for your comment, I agree with that. > > But, how it can be justified that an Optimizer gives a result which is > inferior to the starting value? At most, resulting value can remain at the > same level, isnt it? > > On Fri, 28 Mar 2025 at 14:34, Duncan Murdoch <murdoch.duncan at gmail.com>
2025 Mar 28
3
Problem with minimization that I failed to understand
Hi Duncan, Thanks for your comment, I agree with that. But, how it can be justified that an Optimizer gives a result which is inferior to the starting value? At most, resulting value can remain at the same level, isnt it? On Fri, 28 Mar 2025 at 14:34, Duncan Murdoch <murdoch.duncan at gmail.com> wrote: > I haven't run your code, but since Kendall correlation is based on >
2017 Nov 07
1
fill histogram in ggplot
Hi all, I have the following data and I have a histogram for mms like ggplot(hist,aes(x=hist$mms))+ geom_histogram(binwidth=1,fill="white",color="black")and then I want to fill the color of histogram by probable=1 and probable=0, could anyone help me in this? My data: structure(list(probable = c(1L, 0L, 1L, 1L, 0L, 1L, 0L, 1L, 1L, 0L, 1L, 0L, 1L, 0L, 1L, 0L, 1L, 1L,
2012 Mar 21
2
Type II and III sum of squares (R and SPSS)
To whom it may concern I made some analysis with R using the command Anova. However, I found some problmes with the output obtained by selecting type II o type III sum of squares. Briefly, I have to do a 2x3 mixed model anova, wherein the first factor is a between factor and the second factor is a within factor. I use the command Anova in the list below, because I want to obtain also the sum
2009 Oct 17
2
Putting names on a ggplot
Putting names on a ggplot Can anyone suggest what I am doing wrong here. I am plotting daily temperatures at Ottawa Ontario for 2008 broken down by months, I seperate them by lines and want to put the names of the months at the top of the chart ( with in the graphing area) Everything is working as I want until I try to add the names of the months. I did something similar a few days ago and I
2012 Jul 21
2
changing cex pointwise in lattice
Dear R-users, I have tried, and I imagine it should be somewhere in the lines of passing extra arguments to the panel function, but does anyone know how to change the character expansion factor that is affecting an individual point in each of the panels of a lattice plot? I have tried to pass an overall cex argument containing the desired size for each point, but then the sizes are reused for the
2011 Nov 28
1
Comparing data
Hi all, i have a data set cintaining 14 columns and 11 rows. Rows represent single point and columns represent the parameter measured. I wiuld like to compare the data to see which are more alike. I used the cluster analysis, but now i ma wondering if there are some other methods, since the cluster analysis did not give me the result i like. I tried to use factanal() for factor analysis
2009 Oct 09
1
Placing text in a ggplot
I am attempting to graph 12 months of temperatures, delineate the months with a vline and place the names of the months at the top of the graph. So far I have gotten everything to work except the names, despite getting a similar graph to work yesterday the day before yesterday with Baptise A's help. Can anyone suggest what I am doing wrong. Data set is below code. Thanks. Code
2006 Feb 19
5
can you give a answer?
when i tail -f my log: i find this: "Completed in 0.00233 (428 reqs/sec) | Rendering: 0.00005 (2%) | DB: 0.00118 (50%)" i am sure, this request didn''t access DB. but why here DB is (50%) it''s log wrong or my fault? regards -- Posted via http://www.ruby-forum.com/.