similar to: loop in list

Hello I have a loop to draw few samples and I want to but this samples in one list, how I can make this? when I use it , the list show just the last sample. I want to know the correct way to put all samples in one list.   Regards Sulafah [[alternative HTML version deleted]]

Hello If I have x=c(3,2,6,1) and n=length(x), are the following codes equivalent?? sample(x,1,replace=TRUE)    and       sample(x,1,replace=TRUE,prob=rep(1/n , n) ) Regards [[alternative HTML version deleted]]

Hello I used SIGN.test function in R 2.12.2 to apply one sample sign test and it is worked well ,but I want to put statistic in a variable and I could not get this value, I used : x=rnorm(100) t=SIGN.test(x,md=0,alt="less") t$rval[1]$statistic   the last command work in the old version of R but it does not work in R 2.12.2. what can I do to get value of statistic??   Regards Sulafah

Hello If I have this vector x=c(5,1,2,9) and n=length(x) and I want to sample one value from x , and each value of x has equal probability to appear (1/n). Are the following codes equivalent?? sample(x,1,replace=TRUE)  and   sample(x,1,replace=TRUE,prob=rep(1/n , n))   Regards [[alternative HTML version deleted]]

Hello If i want to resampl from the tails of normal distribution , are these commans equivelant??   upper tail:qnorm(runif(n,pnorm(b),1))  if b is an upper tail boundary   or   upper tail:qnorm((1-p)+p(runif(n))  if p is the probability of each interval (the observatins are divided to intervals)   Regards [[alternative HTML version deleted]]

Hello How to compare  two statistical histograms? How i can know if these histograms are equivalent or not??   Regards [[alternative HTML version deleted]]

Hello   I want to know how can i sampling from upper and lower tail of normal distribution , in two cases , if i know the upper and lower bounds of distribution and if i do not.   Regards [[alternative HTML version deleted]]

Is there a way to estimate a nominal response model? To be more specific let's say I want to calibrate: \pi_{v}(\theta_j)=\frac{e^{\xi_{v}+\lambda_{v}\theta_j}}{\sum_{h=1}^m e^{\xi_{h}+\lambda_{h}\theta_j}} Where $\theta_j$ is a the dependent variable and I need to estimate $\xi_{h}$ and $\lambda_{h}$ for $h \in {1...,m}$. Thank you, Mauricio Romero Quantil S.A.S. Cel: 3112231150