similar to: Data scaled by lattice::stripplot

I want to make a 2x2 plot on a single page, using stripplot() and boxplot(). I tried the following two alternatives with mfrow() and layout(), but none of them worked. library(lattice) par(mfrow=c(2,2)) boxplot(X1 ~ Y, data=tst1, horizontal=T, las=1) boxplot(X2 ~ Y, data=tst1, horizontal=T, las=1) stripplot(Y ~ X1, data=tst1) stripplot(Y ~ X2, data=tst1) par(mfrow=c(1,1)) nf <-

I'd like to use stripplot for some plots because I want to use the jitter parameter. On the other hand, I'd like to use dotplot because I'd like to have the horizontal lines that it includes. dotplot doesn't have a jitter option and I'm not having any success with getting panel.grid(h=-1) with stripplot. Can anyone show me how to make dotplot-like lines on a stripplot? Or

I have a plot similar to the following library(lattice) stripplot(1:15, rep(1:3, each=5)) In order to save space for a presentation, I would like to have horizontal strips instead of vertical. The argument 'horiz' turns the arguments around, but not the plot. The documentation for 'stripplot' ('xyplot'), 'panel.stripplot' and the FAQ do not seem to provide

All, On p.52 of Deepayan Sarkar's Lattice book there is a nice plot of showing residuals with median lines superimposed or various groups: library("lattice") stripplot(sqrt(abs(residuals(lm(yield~variety+year+site)))) ~ site, data = barley, groups = year, jitter.data = TRUE, type = c("p", "a"), fun = median) Suppose we wanted to make a similar plot for a

Hi, I'd like to change the default orientation of bwplot() and stripplot() so the plots are displayed vertically. Passing horizontal=FALSE into stripplot in the simple code below doesn't seem to be the answer. library(lattice); x <- rnorm(100); y <- as.factor(sapply(1:100, function(k) sample(c("A","B","C"), 1, prob=c(1/2, 1/3, 1/6)))); my.df <-

I would like to plot horizontal box-and-whisker plots in lattice where each factor has its own panel and scales are "free." Below is a stripplot version of what I have in mind. Substituting "bwplot" doesn't work. I know it's gotta be simple but I can't find the way . . . x <- c(runif(100, 0, 1), runif(100, 1, 2), runif(100, 2, 3)) y <-

Dear all, I am using the R 2.4.0 environment on Windows XP SP2 machine and trying to use the lattice package version 0.14-9 which you have kindly written to share with the R community. I have a question concerning the stripplot which I'd be very grateful if you can kindly advise me on: I used the dataset called trydata to plot a graph using stripplot (dataset attached), and the scripts

Hello, I have a stripplot with 200+ labels i.e i have network connections. The y-axis are the server port numbers and am graphing the number of packets in a connection. Roughly stripplot(totpacks~portnum,data=network) Due to the large number of server ports in my dataset, the y-axis labels overlap so I would like to split it across several panels(1 panel per page) with about 25-50 per

For the following code is there a way to make the jitter all line up horizontally, instead of them being just randomly spread around a value. So for ex if there are multiple values at 63 for genotype wt then all the values should be plotted on the same y value of 63 but spaced apart by a certain factor or noise.. library(lattice); dataFrame <- as.data.frame(t(structure(c( 64,'wt',

hello, i can't figure out how to set position of panels of my stripplot - i`d like the panels of one level of the factor stage (nr. of panels within each stage, A: 12, B: 12, C: 12, D: 4, each panel representing a site) to be in one column, with A to D from left to right and with descending site.nr at each row. like: A1 B1 C1 D1 A2 B2 .. .. A3 .. .. .. how is this achieved? any help

I have had a problem with stripplot. Documentation does say that method ="stack" is only appropriate for granular data, but I don't think that means it should fall over. > difference [1] 2.0 1.3 2.8 -2.6 -0.4 -0.4 -1.2 -1.4 -1.0 1.2 -2.6 -1.9 > stripplot(difference) > stripplot(difference,method="jitter") > stripplot(difference,method="stack")

Hello I have the following data.frame and xyplot. I need this plot without the borders. Does anybody know how to get this xyplot without borders o with white borders? Thank's in advance Juan Hernández my.label <- data.frame(quantil=rep(20,8), my.factor=factor(c('FA','FB','FC','FD','FE','FG','FH','FI'))) library(lattice)

Dear all, I am using panel graphics to do a stripplot of a variable versus a shingle and putting a loess curve on the stripplot. I want the data jittered, but I can't seem to get the panel function to work. This jitter's the data, but of course doesn't give me the loess: > stripplot((g[,3]) ~ c,jitter=T,pch=".",scales=list(y=list(log=T))) But this doesn't give me

Hello I'm using R 1.2.1 on Windows. I can't understand how to set up two different plotting characters within a stripplot graph. I would use plot(), but I want to use the 'stacking' option in stripplot as the overplotting is quite severe: patch <- factor(rep(c("S", "M", "B"), c(7, 7, 7))) struc <-

Hello, I'm running into a frustrating problem with the legend on a lattice plot I'm working with. The plot is a stripplot with a panel.linejoin () line running through the mean of each of the categories. Thus there are both points and lines in the plot. In trying to make a key for the plot, I can't figure out how to make a legend for both the points and the lines. What I'd

With 2.7.0 patched (not tested with 2.0.0), I get an error message in a program that ran correctly in R 2.6.2 when the grouping factor of a stripplot contains an Umlaut: I am aware that there are a few locale-changes in R 2.7.0, but I could not easily locate who's at fault Dieter library(lattice) dt = data.frame(x=rnorm(100),y=1:100,levs= as.factor(c("Gru","Gr?")))

Dear all, I need to generate plots in which the points of the plot are replaced by text labels, such as "dog" and "cat". The usual way of specifying the plotting symbol with pch works only if the labels are single characters, as far as I know. So, plot(runif(3), pch=c("A", "B", "C")) will work OK, but plot(runif(3), pch=c("dog",

Hi, I'm creating some lattice plots that have a key and I'd like to put a label on the key. The problem is that the text label for the key prevents the values of the group variables from being shown (see example below). I don't think that this is a feature, but I might be abusing the title arg for key. I'm using R Version 2.3.0 (2006-04-24) on Windows XP and lattice V0.13-8

Hi, My problem is simple: since having updated the lattice package, I cannot load lattice anymore. If I type in the command 'library(lattice)' the loading fails with the following message: --- cut here --- Error in library.dynam(lib, package, package.lib) : shared library 'lattice' not found In addition: Warning messages: 1: In loadNamespace(package, c(which.lib.loc,

-----Original Message----- From: Ghosh, Sandeep Sent: Thursday, June 30, 2005 5:43 PM To: 'Berton Gunter' Subject: plot legend outside the grid Thanks for the pointers... I managed to get everything to look and feel the way I want except for the legend to plot outside the grid... Thanks for the note on the par, but I'm not able to it to plot outside the plot grid.. dataFrame <-