similar to: remove descriptions from output

Dear all, I want to concatenate the elements of two vectors such as a<-c("a1","a2") b<-c("b1","b2") and obtain "a1b1", "a1b2","a2b1","a2b2" I tried the paste and paste0 functions, but they yielded elementwise concatenation such as "a1b1","a2b2" I am wondering that is there an efficient

Dear all, I want to manipulate a character string such as ex<-"cbind(data$response1,data$response2)" in R in two ways: 1) extracting the "response1" portion of ex 2) replacing "$" with "." I am wondering that is it possible efficiently doing these in R? Best Ozgur -- View this message in context:

Dear all, Actually I could not decide who to contact, then decided to post here. If not appropriate sorry for that. I have written some functions in R which might be supposed to available in the base package but not available. I am wondering that how can I submit those functions to that package? Best Ozgur ----- ************************************ Ozgur ASAR Research Assistant Middle East

Hello, I have a dataframe (Lx) with 5 Lb, and 5 Lw variables. I want to create several variables according to the loop presented below (data attached). Lx <- read.csv("Lx.csv", header=T, sep=",") for (i in 1:20) { Lx$sb1[i] <- Lx$Lb1[i+1]/Lx$Lb1[i] Lx$sb2[i] <- Lx$Lb2[i+1]/Lx$Lb2[i] Lx$sb3[i] <- Lx$Lb3[i+1]/Lx$Lb3[i] Lx$sb4[i] <-

Hi, Your mistake seems to be in sum(v[1:x]) You create "x" as a vector but your treat it as a single number. v[1:x] expects "x" to be a single number and only considers its first element which is 1. If I understand your query correctly, the following might handle your problem: sum.vec <-NULL for (x in 1:1000){ t <- rbinom(1000, 1, 0.5) v <- replace(t,t==0,-1)

Hello R-Experts, I am facing the problem that I have to estimate several parameters for a lot of different dependent variables. One single regression looks something like this: y = beta0 + beta1 * x1 + beta2 * x2 + beta3 * x1 * x2 + beta4 * x4 + beta5 * lag(x4,-1) where y is the dependent variable and xi are the independent ones. Important to me are the different estimates of betai and their

Hi Do I have to load/download the whole package over and over again everytime when I use the R-Project? It often prompt me the error message "could not find function"- but I'm rather sure I have used the function before so I'm not entirely sure it couldn't find it again when I shut down the computer or so. Is it to do with directory or clashing with other software? Any

Dear all, I have some trouble with special characters while building my R package. I tried to follow the usual LATEX format, but could not fix the problem: For instance, for "greater than or equal", I tried "\geq", but R says that this is an unknown macro. Could anyone direct me how to solve this issue? Best Ozgur ----- ************************************ Ozgur ASAR

Dear Researchers, I am looking for to read a SAS macro in R. Although I searched it on web, I couldn’t find anything. Can you help me or direct me? Thank you for your interest and patience. Best. Ozgur [[alternative HTML version deleted]]

Hi group, I've been thinking of calculating euclidean distance between each column of a data frames that each consists of standardized numerical columns. However, I don't know if there's a way of summarizing the overall distance by some kind of metrics. If anyone know a proper way of doing so and/or a package I would greatly appreciate your suggestions. Thanks very much! Kel --

hello, I try to run simulation of levene's test to find the p-value but the error of replacement has length zero occur, could anyone help me to fix this problem? asim <- 1000 pv<-rep(NA,asim) for(i in 1:asim) {print(i) set.seed(i) g1 <- rnorm(20,0,2) g2 <- rnorm(20,0,2) g3 <- rnorm(20,0,2) x <- c(g1,g2,g3) group<-as.factor(c(rep(1,20),rep(2,20),rep(3,20))) library(Rcmdr)

Dear list users, I have a data frame as below specified. From the 1st of May to the 30th of September of several years (e.g. from 2004 to 2011) I have a frequency of accidents. I need the mean of accidents divided by weeks (i.e. the mean of accidents from the 1st to the 7th of May of all the years, from the 8th to the 14th of May, ..., from the 29th to the 31st of May, from the 1st to the 7th of

https://bugzilla.mindrot.org/show_bug.cgi?id=1285 Vladimir Rutsky <rutsky.vladimir at gmail.com> changed: What |Removed |Added ---------------------------------------------------------------------------- CC| |rutsky.vladimir at gmail.com -- You are receiving this mail because: You are watching the assignee of

Dear R users, I'd like to count the number of integers in a vector y. Here is an example. y <- c(0,1,1,3,3,3,5,5,6) In fact, I know how to count the number of specific number in y. sum(y==0) -> 1 sum(y==1) -> 2 sum(y==2) -> 0 sum(y==3) -> 3 sum(y==4) -> 0 sum(y==5) -> 2 sum(y==6) -> 1 However, in one computation I want to get this vector [1,2,0,3,0,2,1]. Thank

Dear R users, I'd like to compute X like below. X_{i,t} = 0.1*t + 2*X_{i,t-1} + W_{i,t} where W_{i,t} are from Uniform(0,2) and X_{i,0} = 1+5*W_{i,0} Of course, I can do this with "for" statement, but I don't think it's good idea because "i" and "t" are too big. So, my question is that Is there any better idea to avoid "for" statement

I have an *Ubuntu 16.04* mail server with postfix/spamassassin/*dovecot-2.2.2**2* with virtual mailboxes in maildir format. The whole process is working excellently since a year. Spams are marked with "*****SPAM*****" in subject and with "X-Spam-Flag: YES" in email header. I tried now to add sieve to dovecot to move the SPAM messages into the Junk folder without any

#using "rollapply" to calculate a moving sum or running sum? #I am tryign to use rollapply to calcualte a moving sum? #I tried rollapply and get the error message #"Error in seq.default(start.at, NROW(data), by = by) : # wrong sign in 'by' argument" #example: mymatrix <- ( matrix(data=1:100, nrow=5, ncol=20) ) mymatrix_cumsum <- ( matrix(data=NA, nrow=5,

zoo's rollapply() function appears to be extremely useful for plugging in a function on-the-fly to run over a window. With inline, there is a lot more coding and room for error, and the code is less portable because the user has to have R compiling set up or it won't work. However, rollapply() seems to be really slow. Several orders of magnitude slower than inline, in fact. I don't

Hi, i want transform data and using apply(data,2,fuz) , but i don't know why the values < low & > high don't get 0 or 1, they get the value from Formula ,too "((x-low)/(high-low))" what's not the intention ? ....is switch more approriate !? thanks for advance ,Christian fuz <- function (x) { #x <- na.omit(x) low <- quantile(x,0.15)[[1]] high

Hi, Sorry ahead of time for not including data with this question. Using rollapply to calculate mean values for 5 day blocks, I'd use this: Roll5mean <- rollapply(data, 5, mean, by=5, align = c("left")) My question is, can someone tell me how to fill in the days between each of these means with the previously calculated mean? If this doesn't make sense, I will clarify and