similar to: decomposing a single intact vector

Hello, May someone help me with how in R I can rank a vector from highest to lowest. i.e rank 1 (smallest rank) is given to the highest value instead of the usual way that it get's the highest rank. Regards, Jessy [[alternative HTML version deleted]]

Hi, Can R read in .xyz files? If so, what is the package, thanks -- Shane [[alternative HTML version deleted]]

Here is my problem, 100 decision trees were built(similar to random forest) and I want to replace some of them by new trees. How can I define a tree array including 100 trees, i.e. t[100], and every t[n] is an "C5.0" object, such that when a new tree comes, i can do n<-10 t[n]<-C5.0(...) -- View this message in context:

Hi, I would like to access a local mysql database. In python using the sqlite3 library it is quite straightforward. I just have to pass the path to the sqlite-file; sqlite3.connect('.../xy.sqlite') Is there something similar in R (or specifically in the RMySQL package)? It seems like I have to use the MySQL function in the RMySQL package in order to ... "initializes a MySQL

I need the output to have groups and the probability any given record in that group then has of being in the response class. Just like my email in the beginning i need the output that looks like if A and if B and if C then %77 it will be D. The examples you provided are just simply not similar. They are different and would take interpretation to get what i need. On Apr 14, 2016 1:26 AM,

hi R-users: I want to draw three plot into one figure by layout and the script has been shown below. But I find R does not show the xlab and ylab information completely as shown the figure attached. How can I midify the script.? thank you . xxlab<-paste(cpmd," (",ro,"%)",sep=" ") yylab<-paste(rfmd," (",co,"%)",sep=" ")

Hello! I have a data.frame which looks like: Name - Value A - 400 A - 300 B - 200 B - 350 C - 500 C - 350 D - 450 D - 600 E - 700 E - 750 F - 630 F - 650 I want to add another column where all A,B should get an index 1, all C,D an index of 2 and all E,F an index of 3 so that the data.frame looks like: ID - Name - Value 1 - A - 400 1 - A - 300 1 - B - 200 1 - B - 350 2 - C - 500 2 - C - 350 2

Hi, You're mixing base plot and ggplot2 grid graphics, which as you've discovered doesn't work. Here's av strategy that does: https://cran.r-project.org/web/packages/egg/vignettes/Ecosystem.html This vignette has a good overview, well as info specific to that package. Sarah On Wed, May 30, 2018 at 4:43 AM greg holly <mak.hholly at gmail.com> wrote: > Hi all; >

Hello, I would appreciate if someone could help me resolve the following: 1. df1[!is.na( X1 | X2 | X3 | X4 | X5),][,1:5] # This does not work 2. Is these message harmful? The following object(s) are masked from 'df1 (position 3)': X1, X2, X3, X4, X5 Thanks, Pradip Muhuri #Reproducible Example set.seed(5) df1<-data.frame(matrix(sample(c(1:10,NA),100,replace=TRUE),ncol=5))

I still need the output to match my requiremnt in my original post. With decision rules "clusters" and probability attached to them. The examples are sort of similar. You just provided links to general info about trees. Sent from my Verizon, Samsung Galaxy smartphone<div> </div><div> </div><!-- originalMessage --><div>-------- Original message

Since you only have 3 predictors, each categorical with a small number of categories, you can use expand.grid to make a data.frame containing all possible combinations and give that the predict method for your model to get all possible predictions. Something like the following untested code. newdata <- expand.grid( Humidity = levels(Humidity), #(High, Medium,Low)

Hi all; I need to put 12 different plot2 into the same matrix. So my array for the matrix will be par(mfrow=c(3,4)). I am running ggplot2 to produce my 12 plots. For some reason, par(mfrow=c(3,4)) did not turn out 3*4 matrix. my basic R codes for each plot is par(mfrow=c(3,4)) library(ggplot2) p <- ggplot(a, aes(x=Genotypes, y=Plant_hight, size=Plant_hight, color=Showing_rate)) + . . Best

1. Emma is performing an experiment that requires individual handling of some animals. The sizes of the animals are lognormally distributed: The natural logarithms of their sizes has a normal distribution with mean 3 and standard deviation 0.4. The time (in minutes) it takes to handle each animal is given by 10 + s · 1.5 + eε for animals with s ≤ 20 20 + s · 0.8 + eε for animals with s > 20

Dear Gabor You got solution for your problem? "I have just got a laptop with win 7 64 bit installed on it. I installed R and quite a few packages I use. When I try to start BiodiversityR the library loads without any problems but when starting the GUI it gives me the following error message: Sourced: BiodiversityGUI.R Error : .onAttach failed in attachNamespace() for 'Rcmdr',

dear sir/madam, while i am trying to convert the data into timeseries using xts command.i am getting this error. please help me to resolve this issue xts(mydata$MCP, as.Date(rdate, format='%d-%m-%Y') + xts(mydata$MCP, as.Date(rdate, format='%d-%m-%Y') Error: unexpected symbol in: "xts(mydata$MCP, as.Date(rdate, format='%d-%m-%Y') xts"

Hi R user, Can we calculate sample size when only mean and SE are given? Let say one example, I have mean with SE is 0.54+-0.0517 (mean+-SE). Is there any way to find the samples (sample size n) in that condition in R? i think this question is not related to R, I hope you won't mind. Thanks [[alternative HTML version deleted]]

Sir, I would like to create a combined line-bar plot, with the line up top and bar plot below, but with the x-axes suppressed on the topmost plot, the line and bar plot areas joined by a common line, and the x-axes (of dates) joined to the bottom part of the bar plot. i have been able to format the area using the layout(matrix( ... commands, but cannot figure out the final step. here's the

How can I make a reference i this case? I want to make a reference to 'Artikel XXX' For example In The Artikel 'XXXX' there is two tables. .. Litterature Artikel XXX -- View this message in context: http://r.789695.n4.nabble.com/Make-a-reference-tp4634611.html Sent from the R help mailing list archive at Nabble.com.

What is the size of the boostrapped subsample in ecodist mantel() thanks [[alternative HTML version deleted]]

Hi R users, I have a maybe strange problem. Normaly I do image.plot() with x,y coordinates and add=T and if I have some NA values in my data matrix z, the color will be transparent of these pixels. But now I have a disorted coordinate system and x,y are a matrix. It works also fine, but now NA values are white colored and not transparent anymore. It is problematic if I have a secondary