similar to: Remove columns from dataframe based on their statistics

Hi, I have a 1-column dataframe with rownames and I want to sort it based on the single column. The typical procedure that is recommended in diverse posts is to use order in the index. But that "destroys" my dataframe structure. Probabaly it is a very simple solution. Here is a short reproducable example: x <- c(1,3,51,2,34,44,12,33,2,8) df <- data.frame(x) rownames(df) <-

Hi, I am looking for a way to save the result of a function, e.g the lm()-function to a file and reload it afterwards again. I'd like to do that in order to minimize the used memory when running the function in a loop. The actual function I want to store is the evaluate() from the dismo package. I tried it with save() and load() but I am not sure if that is the way I should do it as I

Hi, it is easiest to explain what I want to do by an example: lets assume there are two factors/variables: A <- c(1,2,3) B <- c(1,3,3) Now I would like to generate a list of strings that should look like ("A1_B1","A1_B2","A2_B1","A2_B2"). So actually the string contains all possible combinations of A and B (separated by _). This should be also

Hi, I just started with writing functions in R and so some questions popped up. I provide some values as argument to my function such as: function(a,b,c){} Now i want that the function first checks if the arguments are valid for the function. E.g argument "a" has to be a number in the range 0-1. How can that easily done? So far I have: a <- as.numeric(a) if(0 <= a &&

Hi, I have a dataframe with around 100 columns. Now I want to redefine some of the columns as factors (using as.factor). Luckily all the names of the columns I want to redefine start with "crast". Thus I thought I can use grep() for that purpose... ...I found an example for redefining a single column as factor but that is not working with multiple columns I get from grep()... what I

Just to inform: I posted that before in R-sig-ecology but as it might be interesting also for other useRs, I post it also to the general r-user list: Hello Alexandre, thank you very much. I also found another way to extract summarizing information from lm results over e.g. 1000 repeated model runs: results2 <- t(as.data.frame(results)) summary(results2) Although some questions popped up in

Hello, assume we have following dataframe: group <-c(rep("A",5),rep("B",6),rep("C",4)) x <- c(runif(5,1,5),runif(6,1,10),runif(4,2,15)) df <- data.frame(group,x) Now I want to select all cases (rows) for those groups which have more or equal 5 cases (so I want to select all cases of group A and B). How can I use the indexing for such questions? df[??]...

Good day! I'm having trouble changing certificate/keys for my dovecot(version 1.2.9). When I set up the server (unbuntu lts 10.4.4) I did it with a self-signed certificate. I can't remember exactly what I did, just that I followed the wiki and it worked fine =) Now I have to change the certificate because a friend bought an official one (from thawte) and I'm a bit stumped. As dovecot

Hi, I want to create a pdf of my Man-pages from my package. Therefore I run in the terminal Rd2pdf on the package and a pdf of all the pages is created. After the titlepage there is the general package page, which includes "Description" and "Details" etc. Unfortunately after the Subtitle "Details" there is a pagebreak (and 3/4 white page) which I did not set

Hi, i want to plot empirical cumulative density functions for two variables in one plot. For better visualizing the differences in the two cumulative curves I'd like to log-scale the axis. So far I found 3 possible functions to plot ecdf: 1) ecdf() from the package 'stats'. I don't know how to successfully set the log.scales? Combining two plots is not a problem: plot(ecdf(x1))

Hi, I have two variables ranging both from 0 to 1 (n=500 each). Now I am interested in plotting them both in one plot (using ggplot2). So far I used ecdf() (from an example I found with google) to get values for the cumulatice distribution function which gives a relative curve. I also want to do the same plot but using absolute cumulative values instead of relative. Can that be done with ecdf or

Hello, I want to use a for loop for repeadely calculating a maxent model (package dismo, function maxent()) which creates an object of the class maxent (S4). I want to collect all the resulting object in a list. I tried to simplify my for loop to explain what I want. There are two problems/questions: 1) How can I create the new variables in the loop (using paste) and assign the objects 2) How

Hello, I already posted that on stackoverflow[1], but although it's crossposting, I think this question can probably easier to be answered by other R-users on this list, which maintain packages etc. I would like to make a package out of a function. The function is working in a script, but when I install and load it as library() I get an error. The example-function is: #Make generic function

Hi, I want to split a dataframe based on a grouping variable (in one column). The resulting new dataframes should be stored in a new variable. I tried to split the dataframe using split() and to store it using a FOR loop, but thats not working so far: df <- data.frame(A=c("A1","A1","A2","A2"),B=seq(1:4)) Fsplit <- function(x,y){ ls <-

Hello, just to follow up a question from last week. Here what I've done so far (here an example): library(MCMCpack) Y=c(15,14,23,18,19,9,19,13) X1=c(0.2,0.6,0.45,0.27,0.6,0.14,0.1,0.52) X2a=c(17,22,21,18,19,25,8,19) X2b=c(22,22,29,34,19,26,17,22) X2 <- function()runif(length(X2a), X2a, X2b) model1 <- MCMCregress(Y~X1+X2()) summary(model1) but I am not sure if my X2-function is

Hi, I'd like to know if it is possible to use wildcards * for indexing... E.g. I have a vector of strings. Now I'd like to select all elements which start with A_*? I'd also need to combine that with logical operators: "Select all elements of a vector that start with A (A*) OR that start with B (B*)" Probably that is quite easy. I looked into grep() which I think might

Hi, I would like to plot some extra text in my plot. This should be a two line text including a special character (sigma). I tried so far a to use expression in combination with paste and "\n"... but I can't get the line break... Here what I've done so far: plot(1,type="n", xaxt='n', yaxt='n', ann=FALSE) text(1,1,labels=expression(paste(sigma,"\n

Hello, I am doing a simple regression using lm(Y~X). As my response and my predictor seemed to be skewed and I can't meet the model assumptions. Therefore I need to transform my variables. I wanted to ask what is the preferred way to find out if predictor and/or response needs to be transformed and if yes how (log-transform?). I found a procedure in "A modern approach to Regressoin in

Hi, I've kind of a tricky question, which I don't know how to solve yet: I get multiple dataframes loaded (readRDS) in a loop function. Each loaded dataframe contains two columns one with a var-name and one with a value. The rownumber (order) is very important as it is a value of the rank (1:x). A example with a similar looped structure: df1 <-

Hi, I used to use reshape and moved to reshape2 (R 2.15.1). Now I tried some of my older scripts and was surprised that my cast function wasn't working like before. What I did/want to do: 1) Melt a dataframe based on a vector specifying column names as measure.vars. Thats working so far: dfm <- melt(df, measure.vars=n, variable_name = "species", na.rm = FALSE) 2) Recast the