similar to: Median computation

Does anyone know if it is possible to add a dictionary file of known words that becomes part of the *built* package to tell 'R CMD check --as-cran' not to report these words as misspelled. I want this dictionary to come with the *.tar.gz such that it will be available regardless where the package is checked. For instance, currently I get: * using log directory

Hello All, I need your help. I am analysing affymetrix data and have to select the probe-set that has median expression among all the probe-sets for same gene. This way I want to remove the redundancy by keeping the analysis to single gene entry level. I am fully aware that it is not a nice thing to do but I just have to do it. To do so, I came across 'findLargest' function of

I have a question about shallow copies in R. Since R 3.1.0, subsetting a dataframe with respect to its columns no longer result in deep copies. This is an amazing change in my opinion. Now, subsetting a data.frame by rows (or subsetting a matrix by columns or rows) still does deep copies. In particular, it is my understanding that running a command on a very large subset of rows (say

Hi, I am trying to using SAMseq() to analyze my RNA-seq experiment (20000 genes x 550 samples) with survival endpoint. It quickly give the following error: > library(samr)Loading required package: imputeLoading required package: matrixStats Attaching package: ?matrixStats? The following objects are masked from ?package:Biobase?: ? ? anyMissing, rowMedians Warning messages:1: package ?samr? was

Sorry forgot to use plain text format, hope this time it works: Hi, I am trying to using SAMseq() to analyze my RNA-seq experiment (20000 genes x 550 samples) with survival endpoint. It quickly give the following error: > library(samr) Loading required package: impute Loading required package: matrixStats Attaching package: ?matrixStats? The following objects are masked from

Hi is anybody aware of a function to calculate a the median for specified columns in a dataframe or matrix - so analogous to rowMeans? Thanks Max --

Dear R gurus, I have been struggling with this for a while and thought you might be able to give me some guidance. I have a data frame, on which I apply a row function. The result looks to me like a vector that retains the old row names. I then sort the vector and subsequently need to be able to identify the rank of certain values by searching for their row names. See this mock example: >

I am sure I am opening myself up to looking stupid, but I have two samples with medians of 613.5 and 189 (difference in location of 424 compared to the difference suggested from the wilcoxon of 291.5) > wilcox.test(pipwtCount,pipwdCount, conf.int=TRUE, na.rm=TRUE) Wilcoxon rank sum test data: pipwtCount and pipwdCount W = 822, p-value = 0.01227 alternative hypothesis: true location

Hi, I tried looking through google search on whether there's a way to computer the median for each row of a nxn matrix and return the medians for each row for further computation. And also if the number of columns in the matrix are even, how could I specify which median to use? Thank you very much! -- Edward Chen [[alternative HTML version deleted]]

Dear list! I work with multiple Kruskal-Wallis test (kruskalmc, package pgirmess), which evaluates differences in medians among groups (5 groups). A result of a test is significant differences among some groups, while median values are the same for 4 groups (using tapply). Why? p.s.: number of samples in groups vary from 50 to 4900. Thanks to all, OV .

Dear R-users, Does anyone knows how I can order my serie of boxplots from lowest to highest median (which is much better for visualization purposes). thanks in advance, willem [[alternative HTML version deleted]]

Dear R users, I am new to R and I would like to ask your help with the following topic. I have three sets of numeral data, 2 sets are paired and a third is independent of the other two. For each of these sets I have obtained their basic statistics (mean, median, stdv, range ...). Now I want to compare if these sets differ. I could compare the mean doing a basic T test . However, I was

Hi, A client has a consumption measure on each of four products. The sample size is 75. The consumption distributions are highly skewed for each product. He would like a pairwise comparison test of the products, much like Tukey's HSD but using medians rather than means. Is there such a median comparison test in R? Thanks, Walt ________________________ Walter R. Paczkowski, Ph.D.

Dear all, What is the right test to test whether the median of two groups are statistically significant? Is it the wilcox.test, mood.test or the ks.test? In the text book I have got there is explanation for the Wilcoxon (Mann Whitney) test which tests ob the two variable are from the same population and also ks.test! Regards, Cheba [[alternative HTML version deleted]]

Can someone show me some code to do normalization by the median of some control genes for the example below? Many Many Thanks in advance This strategy selects a subset of genes (called ?control genes?) and makes the median of their data distribution similar across arrays. ??? ??? id1??? id2??? id3 control1??? 0.8??? 0.7??? 0.6 control2??? 0.6??? 0.2??? 0.4 probe1??? ??? 0.3??? 0.2??? 0.5

Dear all, I want to apply a weighted median on a huge dataset, and I remember a function from the package R.basic that could do this using an internal sorting algorithm qsort. This speeded things up quite a bit. Alas, I can't find that package anywhere anymore. There is a weighted.median function in the package limma too, but I didn't use that before. Anybody who knows what happened to

Hi, I drew a plot with R of my data and now I would like to display the median values of each group above the respective datapoint in the plot. I already search for ages, but maybe I am just blind. I am sure that this has to be an option somewhere... I appreciate any kind of input! Best, Christian

Hi, I'm sure this should be simple but I can't figure it out! I want to get the median survival calculated by the survfit function and use the value rather than just be able to print it. Something like this: library(survival) data(lung) lung.byPS = survfit(Surv (time, status) ~ ph.ecog, data=lung) # lung.byPS Call: survfit(formula = Surv(time, status) ~ ph.ecog, data = lung) 1

Hello everyone, I am new to R, I have been using SAS for a while. Not surprisingly, I find R much better in graphics, which is publication ready right away. Recently, I have been trying to calculate some basic statistics using R. I have a dataset of multiple rows per subject. For example: Subject Date Factor1 Factor2 Factor3 P1 0.5 1 1 3 P1 1 3 2 5 P1 2 3 5 NA ... P2 0.5 1 6 4 P2 1 2 NA 7 P2

Dear friends, I'm probably wrong but is there anything better than bootstrap to get a confidence interval of the median from a population with unspecified distribution ? Best wishes Troels Ring, Aalborg, Denmark