similar to: getting a Likert plot from a data frame

Hi, I've been looking at ways to make pyramid plots in R. I like the pyramid.plot method in plotrix as it seems the simplest to use and building them in ggplot looks a bit more code intensive than I'd like, being as I'm new to R. This package does pretty much what I need it to do, however I can't seem to scale the x axis labels. The other labels scale fine with labelcex. I

Hi everyone, I have a problem using rpart (R 2.0.1 under Unix) Indeed, I have a large matrix (9271x7), my response variable is numeric and all my predictor variables are categorical (from 3 to 8 levels). Here is an example : > mydata[1:5,] distance group3 group4 group5 group6 group7 group8 pos_1 0.141836040224967 a c e a g g pos_501

R- Help Forum Working with the "likert" package and I can't figure out why my "bar" graphs are backwards (see attached). The percentages are place correctly but the bars are backwards. #Sample code # libraries library(likert) # create data band <- c("Band 3","Band 3","Band 3","Band 3","Band 3","Band

Hello, unfortunately, I don't know a better subject. I would like to be very flexible in how to process my data. Assume the following dataset: par1 <- seq(0,1,length.out = 100) par2 <- seq(1,100) fac1 <- factor(rep(c("group1", "group2"), each = 50)) fac2 <- factor(rep(c("group3", "group4", "group5", "group6"), each =

Dear R members Could someone tell me how to simulate Likert-type data using the rnorm function. Let's say, 200*15 random numbers in a variable that goes from 1 to 4 in steps of 1 (i.e., 1, 2, 3, 4) belonging to a normal distribution? random.data <— matrix(rnorm(200 * 15), nrow = 200, ncol = 15) random.data The result cannot be reached. could one help me revise the syntax?

R- Help Forum Working with the "likert" package and find that my "bar" graphs are backwards (see attached) > summary(results) Item low neutral high mean sd 4 Q4 5 15 80 2.75 0.5501196 5 Q5 20 40 40 2.20 0.7677719 1 Q1 65 30 5 1.40 0.5982430 3 Q3 5 90 5 2.00 0.3244428 2 Q2 90 10 0 1.10 0.3077935

Hi everyone, I'm stuck on my dissertation which is due next week. I'm a business major student and my project is a comparative research on corporate social responsibility (CSR) between Chinese and German firms. According to my literature review, it's quite obvious that German firms have much better CSR initiatives and strategies than the Chinese ones and I wanted to test whether it was

Dear List, I am looking to perform exploratory analyses of two (relatively) large datasets of categorical data. The first one is a binary 80x100 matrix, in the form: matrix(sample(c(0,1),25,replace=TRUE), nrow = 5, ncol=5, dimnames = list(c( "group1", "group2","group3", "group4","group5"), c("V.1", "V.2", "V.3",

Hi, I have just found this forum, and it looks like a great place to get some help (I hope) For my dissertation, which is due way too soon, I am doing a survey, comparing attitudes of 2 independent groups, with 5 scale likert questions. Basically I want to show if they have similar or different attitudes. I am testing 4 hypotheses, and have in total about 20 questions. I have to say my

Help with survey data: Hello R colleagues, I hope this is an appropriate place to direct this question. It relates specifically to the comparability of a 5-point likert to a 4- point likert scale. One question in my dataset asks "How much should be done to reduce the gap between rich and poor" Much more, somewhat more, about the same, somewhat less and much less. The second

Dear colleagues, I would like to run a cluster analysis on a number of variables. They are Likert Scale (0 to 10), but they also have a "Don't know' option at the end of the scale. Apparently, with the 'Don't Know' option in place, they cannot be considered to be linear or ordinal. How can these variables be analysed using R? One option would be to use poLC and treat

Hi I needed some help with ANOVA I have a problem with My ANOVA analysis. I have a dataset with a known ANOVA p-value, however I can not seem to re-create it in R. I have created a list (zzzanova) which contains 1)Intensity Values 2)Group Number (6 Different Groups) 3)Sample Number (54 different samples) this is created by the script in Appendix 1 I then conduct ANOVA with the command >

Sorry i had a misprint in the appendix code in the last email Hi I needed some help with ANOVA I have a problem with My ANOVA analysis. I have a dataset with a known ANOVA p-value, however I can not seem to re-create it in R. I have created a list (zzzanova) which contains 1)Intensity Values 2)Group Number (6 Different Groups) 3)Sample Number (54 different samples) this is created by the

Hi! I am using R to process some community survey data. Several item responses are recorded via a 7-point Likert-Scale. As I have coded the responses, 1 represents high agreement, and 7 high disagreement. This of course impacts the coefficients in a linear regression (of example agreement to self-perception measures on housing satisfaction). For some purposes, in order to make the coefficients

Dear R users, I have a data frame in the form below, on which I would like to make normality tests on the values in the ExpressionLevel column. > head(df) ID Plant Tissue Gene ExpressionLevel 1 1 p1 t1 g1 366.53 2 2 p1 t1 g2 0.57 3 3 p1 t1 g3 11.81 4 4 p1 t2 g1 498.43 5 5 p1 t2 g2 2.14 6 6 p1 t2 g3 7.85 I

#I am trying to understand how R fits models for contrasts in a #simple one-way anova. This is an example, I am not stupid enough to want #to simultaneously apply all of these contrasts to real data. With a few #exceptions, the tests that I would compute by hand (or by other software) #will give the same t or F statistics. It is the contrast estimates that R produces #that I can't seem to

I'm having trouble with files being marked read-only in Windows because the Solaris file owner does not have write-permissions on the file; group-write is allowed: -r--rw---- 1 user group 32 Feb 13 14:19 testfile.txt I thought that setting "store dos attributes = yes" for this share would allow the "read only" setting to be stored in extended attributes, but it

Hi For first question, maybe I am completely wrong but cor(swiss[,-1], swiss[,1]) should give you what you want in one step. Second question Without an example it is hard to say but maybe aggregate is the way forward. > aggregate(iris[,1:4], list(iris$Species), function (x) c(mean=mean(x), sd=sd(x))) Group.1 Sepal.Length.mean Sepal.Length.sd Sepal.Width.mean Sepal.Width.sd 1

Hello, Before I start to construct something inferior myself I would like to know if such a plot function is already out there. I have count data of a small survey with a few questions which use a scale from "Strongly disagree" to "Strongly agree" and similar things. What I would like to have for a slide is a plot which shows for each question a line over this scale and the

Hola a todos. Estoy intentando instalar el paquete likert utilizando devtools y obtengo el siguiente error library(devtools) install_github('likert','jbryer') Installing github repo(s) likert/master from jbryer Downloading likert.zip from https://github.com/jbryer/likert/archive/master.zip Error en function (type, msg, asError = TRUE) : <not set> Me pasa también con