similar to: referencing headers to extract components of a data frame

Displaying 20 results from an estimated 3000 matches similar to: "referencing headers to extract components of a data frame"

1997 Aug 20
1
R-alpha: R-0.50-a3(+) Method despatching bug ?
It is very wierd... Can some of you confirm the following behavior ? It is a new bug (feature ?) which was not yet in 0.49 ... noquote <- function(obj) { ## constructor for a useful "minor" class if(!inherits(obj,"noquote")) class(obj) <- c(class(obj),"noquote") obj } "[.noquote" <- function (x, subs) structure(unclass(x)[subs], class =
2020 Nov 05
1
Named class vector
The source to the noquote() function looks like this: noquote <- function(obj, right = FALSE) { ## constructor for a useful "minor" class if(!inherits(obj,"noquote")) class(obj) <- c(attr(obj, "class"), if(right) c(right = "noquote") else "noquote") obj } Notice what happens with right =
1997 Aug 15
1
R-alpha: (minor?) S-R inconsistency: NULL =~= list() -- useful is.ALL function
In S, NULL and list() are not the same. In R they are (I think). --------------------------------------------------- At least, is.list(NULL) #-> 'F' in S; 'TRUE' in R Yes: I had an instance where this broke correct S code: match(c("xlab","ylab"), names(list(...))) when '...' is empty, gives an error in R, but gives c(NA,NA) in S.
2011 Jan 24
2
normality and equal variance testing
I currently have a program that automates 2-way ANOVA on a series of endpoints, but before the ANOVA is carried out I want the code to test the assumptions of normality and equal variance and report along with each anova result in the output file.  How can I do this? I have pasted below the code that I currently use.   library(car) numFiles = x #
2009 Aug 11
1
Passing a list object to lapply
Hello, I'm having difficulty passing an object name to a lapply function. Can somebody tell me the trick to make this work? #Works T13702 <- TRACKDATA[["13702.xls"]][["data"]] min(unlist(lapply(list(T13702), function(x) mdy.date(x[1, 2], x[1, 1], x[1, 3])))) 16553 #Works d<-2 assign(paste("T",substr(names(TRACKDATA)[d],1,(nchar(names(TRACKDATA)[d]
2008 Jun 15
1
c.noquote() weirdness
I haven't been able to get anywhere tracking this down. It seems that c.noquote() does something strange with its third (and subsequent) parameters: R-2.7.0 under NetBSD, R-2.6.0 under Solaris, and R-2.8.0 (unstable) (2008-06-10 r45893) under WinXP, I get: > c(noquote('z'), 'y', 'x', '*') [1] z y x * x * > or: > c(noquote('z'),
2002 Jun 02
2
selections using text strings (result of noquote)
G'day all, I am trying to use a string as an argument in a selection but things are not working as I expect, seems the selection is not seeing the expanded string and I do not know how to make it. Perhaps the noquote class value that is returned is the problem. Here is an example. > selection #this is my string [1] "attackprogress$Se=='Toona ciliata [19825: JMM35]'"
2011 Mar 30
1
Class noquote to matrix
Hi, I apologize if the solution is right in front of me, but I can't find anything on how to convert a class of 'noquote' to 'matrix'. I've tried as.matrix and I've tried coercing it by 'class(x)<-matrix', but of course that didn't work. I've been using the function 'symnum' which returns an object of class 'noquote'. Here is an
2017 Oct 13
1
Quotation marks hinder for loop
Dear mailing list members, My question is maybe very basic, but I could not find the solution. I would like to do the following things 1) colnames(V1)[2] <- par$V2[1] colnames(V2)[2] <- par$V2[2] colnames(V3)[2] <- par$V2[3] ... colnames(V37)[2] <- par$V2[37] 2) V1 <- V1[,-1] V2 <- V2[,-1] V3 <- V3[,-1] ... V37 <- V37[,-1] 3) ms <- merge(V1,V2) ms <- merge(ms,V3)
2009 Apr 07
3
write text file as output without quotes
Hi R, When I use the below to write the text file try=data.frame(rep("a",5), rep("b",5)) write.table(try,"z:\\try.txt",row.names=F,col.names=F,sep="\t") the output contains two columns with quotes! Is there a way to write without quotes? I tried try[,1]=noquote(try[,1]) try[,2]=noquote(try[,2]) Thank you, Regards, Ravi Shankar
2009 Jan 05
1
How to extract range of colums in a data frame
Dear all, I have the following data frame: > dat V1 V2 V3 V4 V5 V6 V7 V8 V9 1 1 AAAACACCCACCCCCCCCCCCCCCCCCCCCCCCC 9.0 18 12.00 18.0 15.0 12.0 6.0 2 1 ACGATACGGCGACCACCGAGATCTACACTCTTCC 18.0 8 12.00 18.0 15.0 12.0 18.0 3 1 ACTACTGCTCCCCCCCCACTCCCCCCCCCCCCCC 15.0 8 12.00 12.0 18.0 12.0 12.0 4 1 ACTTATACGGCGACCACCGAGATCTACACTCTTT 15.0
2013 Mar 07
1
Error: no 'dimnames' attribute for array
Dear XpeRts, I prepared a no qoute Character string by the following command s<-noquote(paste (b1, collapse=",")) where, b1 is the vector of 24 intergers. > dput(b1) c(1L, 2L, 6L, 7L, 12L, 16L, 17L, 20L, 21L, 23L, 25L, 34L, 46L, 48L, 58L, 64L, 65L, 68L, 82L, 97L, 98L, 101L, 113L, 115L) > dput(s)
2010 Aug 21
1
R-level expansion of Rplot%03d.png
Dear list, I'm using the brew package to generate a report containing various plots. I wrote a function that creates a plot in png and pdf formats, and outputs a suitable text string to insert the file in the final document using the asciidoc syntax, <% tmp <- 1 makePlot = function(p, name=paste("tmp",tmp,sep=""), width=300) {
2009 Mar 23
2
Looping of read.table and assignment
Dear all, I am trying to read in and assign data from 50 tables in an automated fashion. I have the following code, which I created with the help of textbooks and the internet, but it only seems to read in the final data file over and over again. For example, when I type:> table_1951 I get the same values in the table as when I type> table_2000 despite the values in the source tables
2007 Nov 30
1
No quote
Hello, I define a dataframe named "Price" first and there are other dataframes as well. Then I built an array named "code" containing all the dataframe name. So If I call code[1], it is "Price". Basicly, I would like to call the datafram with reference to the array"code".e,g, If I want to call dataframe "Prices", I use sth containing code[1]. It
2009 Aug 20
0
Using 'unlist' (incorrectly?!) to collate a series of objects
Dear R Users, I am attempting to write a new netCDF file (using the ncdf) package, using 120 grids I've created and which are held in R's memory. I am reaching the point where I try to put the data into the newly created file, but receive the following error: > put.var.ncdf(evap_file, evap_dims, unlist(noquote(file_list))) Error in put.var.ncdf(evap_file, evap_dims,
2010 May 16
1
improvement
Hi, if i just want a vector filled with names which has length(index) > 0. For example if nombreC <- c("Juan", "Carlos", "Ana", "Mar?a") nombreL <- c("Juan Campo", "Carlos Gallardo", "Ana Iglesias", "Mar?a Bacaldi", "Juan Grondona", "Dario Grandineti", "Jaime Acosta",
2002 Sep 10
0
Old-style classes: bug fix & request
Bug fix: A bug introduced in version 1.6 failed to "initialize" some old-style (aka "S3") classes, producing possible warning messages if those classes were used in the signature of a method in the methods package. The real bug, though, was that old-style inheritance could not be included, until the setOldClass function was provided. Initializing the methods package now
2017 Sep 19
0
remove quotes from matrix
Works fine for me. What do you object to in the following? Calling the above df "d", > dm <- as.matrix(d) > dm Sub_Pathways BMI_beta SAT_beta VAT_beta 1 "Alanine_and_Aspartate" " 0.23820" "-0.02409" " 0.94180" 2 "Alanine_and_Aspartate" "-0.31300" "-1.97510" "-2.22040" 3
2008 Feb 04
1
Concatenation and Evaluation
Hello all, I've run into what I bet is a silly problem; however, I've been trying to get around it now for a couple weeks and every time I think I have the answer it still doesn't work. So I apologize in advance if this is painfully obvious, but I've run out of ideas and would really appreciate any input. My situation is this, I'm importing a number of tab