similar to: How to extract from a column in a table?

Hi, A column of my df looks like A 10/20/30 40/20 60/10/10/5 80/10 I want to split it such that the last column has the last composition and if there are not enough the middle columns get the 0s. That way my df would look like A1 A2 A3 A4 10 20 0 30 40 0 0 20 60 10 10 5 80 0 0 10 How can I do that ?? [[alternative HTML version deleted]]

Hi, I have 6 columns in my dataframe (test) A B C D E F a b c d 40 30 a f a b 20 10 x m y m 50 30 If character value in column A matches with that in column C, it gets the percentage in column E, similarly if value in column B matches the value in D, it gets the percentage in F column. If it doesn't match, it gets 0 percentage. How can I do that ? thanks [[alternative HTML version

I have 5 (A,B,C,D,E) columns in my dataframe. I want to replace all "x" with "y" and all "a" with "b" within these 5 columns. Can I do it in one step? Thanks [[alternative HTML version deleted]]

Hi, My data frame looks like A B C a b a x y z I want to add a new column which says "y" if either A or B matches with C and "n" if there is no match. How can I do that? Thanks [[alternative HTML version deleted]]

Hi, My data.frame "A" has FID like this FID a a b b b c c d d d d Now my second data.frame "B" has age value for a, b, c, d like FID Age a      5 b      7 c      9 d      3 How can search for the Age column in "B" and replace the values in "A" so that my new "A" looks like this FID Age a      5 a      5 b      7 b      7 b      7

Hi, my data frame is x<-data.frame(ID=c("abc/def","abc/def/ghi","abc","mno/pqr/st/ab")) I want to split my column ID using "/" as the place to split. How can I do that without telling the code how many sub-columns. I could use nchar(gsub("[^/]","",x$ID)) to get how many "/" are in each row of the column, but could

Hi, My dataframe has two columns one with area and other with percent. How can i add the areas that are within a range of percentage?? My dataframe looks like Area Percent 456       0 3400      10 79          25 56           18 467         0 67          67 839        85 1120      0 3482      85 I want to add the area for values whose percent is <0, 0-25, 25-50, 50-75, >75. How

Warning - Puppet newby here. I am trying to set up a puppetmaster 3.3.2 and have run into a snag right out of the box. I want to add a new directory to modulepath= in /etc/puppet/puppet.conf So I added the following line in the [main] header modulepath = /etc/puppet/modules:/opt/our-repo/puppetmaster/modules And populated new new directory with modules I have written. I then run puppet

Hi everybody, I would like to know whether it is possible to compare to tables for certain parameters. I have these two tables: gene table name chr start end str accession Length gen1 4 646752 646838 + MI0005806 86 gen12 2L 243035 243141 - MI0005821 106 gen3 2L 159838 159928 + MI0005813 90 gen7 2L

Hi, From your example data, dat1<- read.table(text=" id1?? id2?? value a????? b?????? 10 c????? d??????? 11 b???? a???????? 10 c????? e???????? 12 ",sep="",header=TRUE,stringsAsFactors=FALSE) #it is easier to get the output you wanted dat1[!duplicated(dat1$value),] #? id1 id2 value #1?? a?? b??? 10 #2?? c?? d??? 11 #4?? c?? e??? 12 But, if you have cases like the one

HI Elisa, You could use ?cut() vec1<-c(33,18,13,47,30,10,6,21,39,25,40,29,14,16,44,1,41,4,15,20,46,32,38,5,31,12,48,27,36,24,34,2,35,11,42,9,8,7,26,22,43,17,19,28,23,3,49,37,50,45) label1<-unlist(lapply(mapply(c,lapply(seq(0,45,5),function(x) x),lapply(seq(5,50,5),function(x) x),SIMPLIFY=FALSE),function(i) paste(i[1],"<x<=",i[2],sep="")))

Hi All: I have some questions when writing a lib with libsmbclient-dev ,my target environment is on any linux system. 1 I want to static link libsmbclient.a instead of using libsmbclient.so, but I got a lot of error , am I able to use libsmbclient-dev using static link? 2 I found that ?smbtree? command is more stable in finding all those domains and servers than