similar to: Split CSV as per file size

Hello R user, I have four data sets in dir "D:/Bharat Warule/Rdata_file" which are output_data_prod_1.rda, output_data_prod_2.rda, output_data_prod_3.rda, output_data_prod_4.rda. Each data set is huge size like number of rows 343297 and columns are near to 50. For example: x1 <- data.frame(x11=c(1,2,3,4,5),x112=c(10,10,10,10,10)) x2 <-

Hi, Here in R, I need to load a huge file(.csv) , its size is 200MB. [may come more than 1GB sometimes]. When i tried to load into a variable it taking too much of time and after that when i do cbind by groups, getting an error like this " Error: cannot allocate vector of size 82.4 Mb " My requirement is, spilt data from Huge-size-file(.csv) to no. of small csv files. Here i will give

Hi all, > diff_operator <- "\\(" > strsplit(cond, diff_operator) [[1]] [1] "andsin" "log_angle_1_4)" > diff_operator <- "\\sin(" > strsplit(cond, diff_operator) Error in strsplit(cond, diff_operator) : invalid regular expression '\sin(', reason 'Missing ')'' When I am going to split with "("

With some help from those with expertise on this list, I managed to produce a plot using trellis that looked like I wanted it to look. Now, I need to take the same plot and make the lines on it color, but I want to specify the color for the lines myself. I've managed to make the key use the colors I want. I've managed to make the symbols of the actual plot use the colors I want. But I

Hi All I am getting the above mentioned error when I run the code below. I don't know why because I have implemented the function and I'm calling the function with a parameter. I'm obviously missing the plot ... Can someone perhaps point out the error of my ways? Error: > out<-ode(y=init, times=times, func=G1999, parms=parms, method="lsoda") Error in m_Na(v) : attempt

In below graph, I would like to add two vertical lines using panel.abline(). ?Is this possible? Thanks, Naresh mydf <- data.frame(hour = rep(6:20, 2), traffic = c(round(dnorm(6:20, 9, 3) * 10000), round(dnorm(6:20, 17, 4) * 10000)), direction = rep(c("inbound", "outbound"), c(15, 15))) vehicles <- data.frame(hour = 6:20, count = c(100, 120, 140, 125, 105, 80, 70, 75,

Hi, I meet a strange trouble writing shapefiles with write.pointShape() from maptools. > write.pointShape(mylines[,5:9], file="Sxtplinshp", mycoordspt) Error in write.pointShape(mylines[, 5:9], file = "Sxtplinshp", mycoordspt) : shapefile names must conform to the 8.3 format It seems that the function request a special shapefile name spelling (conformed to 8.3

On Sat, 18 Nov 2023 at 06:44, Naresh Gurbuxani <naresh_gurbuxani at hotmail.com> wrote: > > In below graph, I would like to add two vertical lines using > panel.abline(). Is this possible? I assume you want the 'v' variable in panel.abline() to be interpreted in the context of your x-axis, which here represents a factor variable. Unless two factor variables have the same

I'd like to plot n (say n = 10) semi-transparent lines in such a way that if all n happen to exactly overlay each other, the resulting line is completely opaque. In principle, I believe that this is what setting alpha = 1/n should accomplish. In practice, different values of n produce different results. Consider the following function, which overlays n semi-transparent red lines: mylines

Hi, I am new to R. How can I get labels/different colours on the lines in my xy-plots. I plot "het" against "temp" conditional on "year" and "station". library(lattice) MyLines <- function(xi, yi, ...){ #Draws line in the panels while avoiding spaghetti-plots I <- order(xi) panel.lines(xi[I], yi[I], col = 1)} xyplot(het ~ temp | fstation,

Hello fellow R users, I am trying to read a 6.9 million row text file with 26 columns separated by spaces into R using ff. When I specify a small number for first.rows, next.rows and nrows it is read with no issue. However, when I try to specify larger next.rows values and no nrows parameter to read the entire file, I keep getting errors. Please see code below. I am trying to this on a m1.large

Hi There are new versions of the grid and lattice packages on CRAN: grid 0.2 and lattice 0.3-0 These packages are still _under development_ (they are in CRAN/src/contrib/Devel) There have been some bug fixes and, especially in lattice, there are lots of new features. Descriptions of the changes are included below. If you have any grid code, it may break under the new version because of a

Hi There are new versions of the grid and lattice packages on CRAN: grid 0.2 and lattice 0.3-0 These packages are still _under development_ (they are in CRAN/src/contrib/Devel) There have been some bug fixes and, especially in lattice, there are lots of new features. Descriptions of the changes are included below. If you have any grid code, it may break under the new version because of a

Dear R-ers, I hope there is a really simple solution to my problem. I've written a function that I saved in an .r file. I source this file in my code. For a while it worked fine. But then when I run the line: source("F mylineplot.r") I started getting a warning: In readLines(file) : incomplete final line found on 'F mylineplot.r' I have no idea why - I tried to check and

FYI, I will be traveling for the next week, and may not see email much until then. Your questions... On 8/31/24 04:59, Strahil Nikolov wrote: > One silly question: Did you try adding some files on the source volume > after the georep was created ? Yes. I wondered that, too, whether geo-rep would not start simply because there was nothing to do. But yes, there are a few files created

Dear R-list members, I have a problem with translating a mathematica script into R. The whole script is at the end of the email (with initial values for easy reproduction) and can be pasted directly into R. The problematic part (which is included below of course) is <--- Original Mathematica ---> (* p_svbar *) UiA = Ni (Dsi - 2Di A + A^2)/2; UiiA = Nii (Dsii - 2Dii A + A^2)/2; psvbar =

Hi, I have huge matrices in which the response variable is in the first column and the regressors are in the other columns. What I wanted to do now is something like this: #this is just to get an example-matrix DataMatrix <- rep(1,1000); Disturbance <- rnorm(900); DataMatrix[101:1000] <- DataMatrix[101:1000]+Disturbance; DataMatrix <- matrix(DataMatrix,ncol=10,nrow=100); #estimate

Hi, I need to permute the rows of a matrix, where each row is independently rearranged. A simple solution is this: shuffled <- datamatrix <- matrix(1:24, ncol = 4) for (i in 1:nrow(datamatrix)) { shuffled[i, ] <- sample(datamatrix[i, ]) } > datamatrix [,1] [,2] [,3] [,4] [1,] 1 7 13 19 [2,] 2 8 14 20 [3,] 3 9 15 21 [4,] 4 10 16 22 [5,]

In datamatrix[, "y"] == datamatrix[, "y"][-1] : longer object length is not a multiple of shorter object length out = c(FALSE,datamatrix[,'y'] == datamatrix[,'y'][-1]) and I do not know why I get that error, the resulting out matrix is somehow one row larger than datamatrix... all I try to do is filter matrix by dropping rows where [,'y'][-1] ==

Hi All, I have a 1000x1000000 matrix. The calculation I would like to do is actually very simple: for each row, calculate the frequency of a given pattern. For example, a toy dataset is as follows. Col1 Col2 Col3 Col4 01 02 02 00 => Freq of ?02? is 0.5 02 02 02 01 => Freq of ?02? is 0.75 00 02 01 01 ? My code is quite simple as the following to find the pattern ?02?.