Displaying 20 results from an estimated 10000 matches similar to: "summary() after changing contrasts"
2010 Dec 03
3
Checking for orthogonal contrasts
A common point made in discussion of contrasts, type I, II, III SS etc
is that for sensible comparisons one should use contrasts that are
'orthogonal in the row-basis of the model matrix' (to quote from
http://finzi.psych.upenn.edu/R/Rhelp02/archive/111550.html)
Question: How would one check, in R, that this is so for a particular
fitted linear model object?
Steve Ellison
2011 May 11
1
Help with contrasts
Hi,
I need to build a function to generate one column for each level of a factor
in the model matrix created on an arbitrary formula (instead of using the
available contrasts options such as contr.treatment, contr.SAS, etc).
My approach to this was first to use the built-in function for
contr.treatment but changing the default value of the contrasts argument to
FALSE (I named this function
2005 Apr 13
2
multinom and contrasts
Hi,
I found that using different contrasts (e.g.
contr.helmert vs. contr.treatment) will generate
different fitted probabilities from multinomial
logistic regression using multinom(); while the fitted
probabilities from binary logistic regression seem to
be the same. Why is that? and for multinomial logisitc
regression, what contrast should be used? I guess it's
helmert?
here is an example
2010 Apr 21
5
Bugs? when dealing with contrasts
R version 2.10.1 (2009-12-14)
Copyright (C) 2009 The R Foundation for Statistical Computing
ISBN 3-900051-07-0
R is free software and comes with ABSOLUTELY NO WARRANTY.
You are welcome to redistribute it under certain conditions.
Type 'license()' or 'licence()' for distribution details.
Natural language support but running in an English locale
R is a collaborative project with
2006 Aug 17
1
Setting contrasts for polr() to get same result of SAS
Hi all,
I am trying to do a ordered probit regression using polr(), replicating a
result from SAS.
>polr(y ~ x, dat, method='probit')
suppose the model is y ~ x, where y is a factor with 3 levels and x is a
factor with 5 levels,
To get coefficients, SAS by default use the last level as reference, R by
default use the first level (correct me if I was wrong),
The result I got is a
2008 Aug 26
2
options("contrasts")
Code:
> options("contrasts")
$contrasts
factor ordered
"contr.treatment" "contr.poly"
I want to change the first entry ONLY, without retyping "contr.poly". How do
I do it? I have tried various possibilities and cannot get anything to work.
I found out that the response to options("contrasts") has class
2006 Aug 22
1
summary(lm ... conrasts=...)
Hi Folks,
I've encountered something I hadn't been consciously
aware of previously, and I'm wondering what the
explanation might be.
In (on another list) using R to demonstrate the difference
between different contrasts in 'lm' I set up an example
where Y is sampled from three different normal distributions
according to the levels ("A","B","C")
2001 Feb 08
2
Test for multiple contrasts?
Hello,
I've fitted a parametric survival model by
> survreg(Surv(Week, Cens) ~ C(Treatment, srmod.contr),
> data = poll.surv.wo3)
where srmod.contr is the following matrix of contrasts:
prep auto poll self home
[1,] 1 1 1.0000000 0.0 0
[2,] -1 0 0.0000000 0.0 0
[3,] 0 -1 0.0000000 0.0 0
[4,] 0 0 -0.3333333 1.0 0
[5,] 0 0
2004 Mar 03
1
Confusion about coxph and Helmert contrasts
Hi,
perhaps this is a stupid question, but i need some help about
Helmert contrasts in the Cox model.
I have a survival data frame with an unordered factor `group'
with levels 0 ... 5.
Calculating the Cox model with Helmert contrasts, i expected that
the first coefficient would be the same as if i had used treatment
contrasts, but this is not true.
I this a error in reasoning, or is it
2008 Oct 11
2
R vs SPSS contrasts
Hi Folks,
I'm comparing some output from R with output from SPSS.
The coefficients of the independent variables (which are
all factors, each at 2 levels) are identical.
However, R's Intercept (using default contr.treatment)
differs from SPSS's 'constant'. It seems that the contrasts
were set in SPSS using
/CONTRAST (varname)=Simple(1)
I can get R's Intercept to match
2001 Jun 15
1
contrasts in lm and lme
I am using RW 1.2.3. on an IBM PC 300GL.
Using the data bp.dat which accompanies
Helen Brown and Robin Prescott
1999 Applied Mixed Models in Medicine. Statistics in Practice.
John Wiley & Sons, Inc., New York, NY, USA
which is also found at www.med.ed.ac.uk/phs/mixed. The data file was opened
and initialized with
> dat <- read.table("bp.dat")
>
2010 Aug 29
2
glm prb (Error in `contrasts<-`(`*tmp*`, value = "contr.treatment") : )
glm(A~B+C+D+E+F,family = binomial(link = "logit"),data=tre,na.action=na.omit)
Error in `contrasts<-`(`*tmp*`, value = "contr.treatment") :
contrasts can be applied only to factors with 2 or more levels
however,
glm(A~B+C+D+E,family = binomial(link = "logit"),data=tre,na.action=na.omit)
runs fine
glm(A~B+C+D+F,family = binomial(link =
2019 Feb 21
2
model.matrix.default() silently ignores bad contrasts.arg
Dear Ben,
Perhaps I'm missing the point, but contrasts.arg is documented to be a list. From ?model.matrix: "contrasts.arg: A list, whose entries are values (numeric matrices or character strings naming functions) to be used as replacement values for the contrasts replacement function and whose names are the names of columns of data containing factors."
This isn't entirely
2002 Nov 07
4
Preferable contrasts?
Dear all,
I'm working with Cox-regression, because data could be censored.
But in this particular case not.
Now I have a simple example: PRO and PRE are (0,1) coded.
The response is not normal distributed.
We are interested in a model which could describe interaction.
But my results are depending strongly in the choose of the contrast option.
It is clear that there is some dependence in
2007 Jan 08
2
Contrasts for ordered factors
Dear all,
I do not seem to grasp how contrasts are set for ordered factors. Perhaps someone can elighten me?
When I work with ordered factors, I would often like to be able to reduce the used polynomial to a simpler one (where possible). Thus, I would like to explicetly code the polynomial but ideally, the intial model (thus, the full polynomial) would be identical to one with an ordered factor.
2002 Dec 01
1
generating contrast names
Dear R-devel list members,
I'd like to suggest a more flexible procedure for generating contrast
names. I apologise for a relatively long message -- I want my proposal to
be clear.
I've never liked the current approach. For example, the names generated by
contr.treatment paste factor to level names with no separation between the
two; contr.sum simply numbers contrasts (I recall an
2010 Oct 15
1
creating 'all' sum contrasts
OK, my last question didn't get any replies so I am going to try and ask a different way.
When I generate contrasts with contr.sum() for a 3 level categorical variable I get the 2 orthogonal contrasts:
> contr.sum( c(1,2,3) )
[,1] [,2]
1 1 0
2 0 1
3 -1 -1
This provides the contrasts <1-3> and <2-3> as expected. But I also want it to create <1-2> (i.e.
2019 Feb 22
2
model.matrix.default() silently ignores bad contrasts.arg
>>>>> Ben Bolker
>>>>> on Thu, 21 Feb 2019 08:18:51 -0500 writes:
> On Thu, Feb 21, 2019 at 7:49 AM Fox, John <jfox at mcmaster.ca> wrote:
>>
>> Dear Ben,
>>
>> Perhaps I'm missing the point, but contrasts.arg is documented to be a list. From ?model.matrix: "contrasts.arg: A list, whose entries are
2006 Sep 23
1
contrasts in aov
useRs,
A no doubt simple question, but I am baffled. Indeed, I think I
once knew the answer, but can't recover it. The default contrasts
for aov (and lm, and...) are contr.treatment and contr.poly for
unordered and ordered factors, respectively. But, how does one
invoke the latter? That is, in a data.frame, how does one indicate
that a factor is an *ordered* factor such that
2012 May 11
1
set specific contrasts using lapply
I have the following data set
> data
A B X1 X2 Y
1 A1 B1 1.1 2.9 1.2
2 A1 B2 1.0 3.2 2.3
3 A2 B1 1.0 3.3 1.6
4 A2 B2 0.5 2.6 3.1
> sapply(data, class)
A B X1 X2 Y
"factor" "factor" "numeric" "numeric" "numeric"
I'd like to set a specific type of contrasts to all the categorical factors