similar to: Splitting Data Into Different Series

Dear R Discussion List, I would like to save my data as a xlsx file. But at first I need to split it and then save each series into a Excel column. Please take a look at the following code: dados <- data.frame(matrix(c("2012-01-01","2012-02-01", "2012-03-01","2012-04-01","2012-05-01","2012-06-01",

Hi all, I'm having this error, since I'm working with a data matrix I don't understand what's happening; I've tried several ways to solve this, even working with sparse matrix, but nothing seems to solve it, I've also tried svm (with a simple matrix 3*3 and still got the same error. > dados<-read.table("b.txt",sep="",nrows=30000) >

Hi, I have 35 data files for reading. I would like get a program for performing reading of 35 files at once. All are of the type: Dados1.raw, Dados2.raw and so on. If the files have the same number of columns, I can read with the following commands: rm(list=ls()) filenames = list.files(path="~/Silvano/Arq", pattern="Dados+.*raw") names = substr(filenames, 1, 7) for(i in

Dear R helpers,   I am a beginner at R so please be gentle :) I have already read manuals and FAQs, with no help. I have a monthly time series data on public debt with 40 variables, it starts on January 1994 and ends on June 2011. I am loading the data into R using read.csv and the data looks ok when I do edit(dados): > dados<-read.csv("dadosR3.csv", header=T) then I tried making

Hi, I have a dummy question. Suppose that I have two explanatory variable, T1 (A, B) and T2 (C, D) and one response variable. > attach(dados) > tapply(Y,list(T1,T2),mean) C D A 2.200000 10.20000 B 2.223333 20.26667 In this case, "A" and "B" inside "C" have no difference, but have differences inside "D" I make this model: > m

2017-06-26 10:38 GMT-03:00 Rowland Penny via samba <samba at lists.samba.org>: > Your 'samba' password and your windows password MUST be the same to > allow you to connect to a Samba share from a Windows machine without > being prompted for a password. I do not understand why, after being > prompted for the correct username & password, that it doesn't connect,

Hi There, I'm facing one problem to construct a vector using the "for" command: I have one matrix named 'dados' (same as /data/ from portuguese), for example: > dados[140:150,] [,1] [,2] [,3] [1,] 212.7298 0.14 0.11 [2,] 213.3778 0.14 0.11 [3,] 214.0257 0.15 0.11 [4,] 214.6737 0.15 0.12 [5,] 215.3217 0.15 0.12 [6,] 215.9696 0.15 0.12 [7,] 216.6176 0.16

Hi, I want to remove the outliers of my database with the following program (an observation is considered an outlier if it is bigger than second quartile + 1,5* distance interquartiles or less than second quartile - 1,5*distance interquartiles): for(i in 1:length(dados)){ q3=quantile(dados[i], probs=.75) q3=quantile(dados[i], probs=.50) q1=quantile(dados[i], probs=.25) d=q3-q1 for(i2 in

Hi all, I have problems in a dataframe variables types. Look: from a loop function: for(...){ ... dados.fin <- rbind(dados.fin, c(L=j, A=j^2, Nsp=nsps, N=length(amosfin$SP), AmT="am",NAm=nam, AMST=amst)) dados.fin <- rbind(dados.fin, c(L=j, A=j^2,

Hi all, Sorry to be bothering again with probably an easy error to fix, but I've been trying to solve the problem and haven't been able yet to do it. So I'm doing this: > dados<-read.table("b.txt",sep="",nrows=30000) >

----- Original Message ----- From: "Silvano" <silvano at uel.br> To: <r-help at r-project.org> Sent: Thursday, June 30, 2011 9:07 AM Subject: Tables and merge > Hi, > > I have 21 files which is common variable CODE. > Each file refers to a question. > > I would like to join the 21 files into one, to construct > tables for each question by CODE. >

Hi R-masters! I have a problem and need your help. I have 9 discrete variables with 2 levels each. In exploratory analisys I generate one matrix with chi-square for tables with 2 ariables each with this script setwd("F:/") dados<-read.csv("log.csv")[,2:10] dados.x<-matrix(NA,ncol=9,nrow=9) for(i in 1:8){ for(j in (i+1):9){ tab<-table(dados[,i],dados[,j])

Hi, I am having some problems using bwplot(lattice) in my data. I want change some parameters: 1) Fontfamily to serif 2) The size of the font 3) Put it in a bold face 4) Change de color of the lines How can I do that?! Now, I am using this to plot my boxplot. dados <- data.frame(varsep=as.factor(rep(1:2,10)),i=runif(20))

I am using pyramid.plot() from the plotrix package. I have something like this ############################################ xy.pop<-dados$masfr xx.pop<-dados$femfr #agelabels<-dados$femlab xycol<-color.gradient(c(0,0,0.5,1),c(0,0,0.5,1),c(1,1,0.5,1),11) xxcol<-color.gradient(c(1,1,0.5,1),c(0.5,0.5,0.5,1),c(0.5,0.5,0.5,1),11) xylab<-dados$maslab xxlab<-dados$femlab

Hi all, I'm trying to plot an svm model and I'm the following error: > plot(model, data= dados[,-1], formula=formula(dados[,2]~dados[,3]),svSymbol = 1, dataSymbol = 2, symbolPalette = rainbow(4),color.palette = terrain.colors) Error in terms.default(x) : no terms component Anyone knows how to solve this??? Best regards, Pedro Marques

I was trying to make some multi figure plots and I had some strange problems. I'm using R 0.61.2. When I make this plot >postscript(file="timeplot5.ps",horizontal=TRUE) >par(mfrow=c(2,2)) >plot(dados$a1) >plot(dados$a2) >plot(dados$a3) >plot(dados$a4) The last panel is ploted without the box and it is always ploted in landscape mode. Can anyone reproduce this

Hola, ¿hay alguna forma de colocar la leyenda de un gráfico sin que se superponga con las barras de mi gráfico? Os dejo mi ejemplo para que me entendáis: ## dado_1<-sample(1:6,1200,replace=T)dado_2<-sample(1:6,1200,replace=T)dado_3<-sample(1:6,1200,replace=T) dados<-matrix(c(table(dado_1),table(dado_2),table(dado_3)),6) barplot(t(dados),beside=TRUE,ylab="Frecuencias

Bom dia eu chamo-me Ana, estou a tentar fazer matriz de correla??o e covariancia para comparar 4 variaveis e saber quais s?o as mehores... fiz o segundo codigo mas devo tar a fazer alguma confus?o para nao me aparecer o output correcto: cor(dados[,2:5],method=c("pearson")) cor_with_p_test(dados[2:5]) ct <- cor.test(dados[,2:5]) ct$p ct$v #matriz de covariancias cov(dados[,2:5],

Hello rowland, follow the informations: 1) ./configure --prefix=/opt/samba --enable-selftest --enable-debug 2) samba-tool domain provision --domain=CMC --adminpass=Mudar2016 --dns-backend=BIND9_DLZ --server-role=dc --use-rfc2307 --realm=CMC.CORP 3) I created a script to start this as described in the manual Samba4 [global] netbios name = SAMBA realm = CMC.CORP

GUYS, I NEED HELP WITH ERROR: library(MASS) > dados<-read.table("mediaRGinverno.txt",header=FALSE) > vento50<-fitdistr(dados[[1]],densfun="weibull") Erro em fitdistr(dados[[1]], densfun = "weibull") : Weibull values must be > 0 WHY RETURN THIS ERROR? WHAT CAN I DO? BEST REGARDS [[alternative HTML version deleted]]