similar to: Date period

Hello. I have for example 4 or more dataframe which like such this example: date value 2006-11 0.4577647 2006-12 NaN 2006-10 0.1577647 2006-11 0.3577647 2006-12 NaN 2007-01 NaN 2007-02 NaN 2007-03 0.2956429 2007-01 0.3677647 2007-02 NaN They have the same length. I need merge by date undefined number of dataframes. End result output will look like

Dear All I am trying to graph a proportion and CI95% by a factor with ooplot (any other better solution ?) It works well until I try to add the confidence interval. this is the error message and and a description of the data: > dat1 PointEst TT1 1 3.6 TT2 2 5.0 TT3 3 5.8 TT4 4 11.5 TT5 5 7.5 TT5 6 8.7 TT7 7 17.4 > dat2

Hello I'm trying to compile LLVM, Clang and LLDB on Ubuntu 14.04 LTS as described on llvm.org [1][2]: ``` sudo apt-get install subversion cmake ninja-build doxygen \ swig libedit-dev libncurses5-dev libxml2-dev mkdir llvm-src cd llvm-src svn co http://llvm.org/svn/llvm-project/llvm/trunk llvm cd llvm/tools svn co http://llvm.org/svn/llvm-project/cfe/trunk clang svn co

Good Afternoon, I have the following code, but it seems that something must be doing wrong, because it is giving the results I want. The idea is to create segments while the value of Commutation is less than 1000. for example, from the small set of data below text=" val_user pos v v_star v_end commutation v_source v_destine 1 1 96-96 1173438391 1173438391 0

Hi, I have encountered an issue about finding a date closest to another date So this is how the data frame looks like: PT_ID IDX_DT OBS_DATE DAYS_DIFF OBS_VALUE CATEGORY 13 4549 2002-08-21 2002-08-20 -1 183 2 14 4549 2002-08-21 2002-11-14 85 91 1 15 4549 2002-08-21 2003-02-18 181 89 1 16 4549 2002-08-21 2003-05-15

Hi all, I am trying to merge several data sets and end up with a long data format by date & time so I can run correlations and plots. I am using Deducer as an R GUI but can just use the R console if easier. The data sets are weather with wind speed, relative humidity and temperatures by date and minute and bat activity with date, time, label, and an activity index number. The bat

Hello, Maybe something like the following. splitDF <- function(data, col, s){ n <- nrow(data) inx <- which(data[[col]] %in% s) lapply(seq_along(inx), function(i){ k <- if(inx[i] < n) (inx[i] + 1):(inx[i + 1]) data[k, ] }) } splitDF(DF, "name", split_str) Hope this helps, Rui Barradas On 5/19/2018 12:07 PM, Christofer Bogaso

Hi, I am struggling to split a data.frame as will below scheme : DF = data.frame(name = c('a', 'v', 'c'), val = 0); DF split_str = c('a', 'c') Now, for each element in split_str, R should find which row of DF contains that element, and return DF with all rows starting from next row of the corresponding element and ending with the preceding value of the

Hi. This is likely a trivial problem but have not found a solution. Imagine the following dataframe: Lat Lon x1 x2 x3 01 10 NA NA .1 01 11 NA .2 .3 01 12 .4 .5 .6 I want to generate another column that consist of the first value in each row from columns x1 to x3. That is NewColumn .1 .2 .4 Any input greatly appreciated, Thanks, Camilo Camilo Mora, Ph.D.

Can anybody help me write a code on the following data example, which fills out all NA values by using a linear interpolation with the two closest values? Doy is day of year (%j). Code example: yr<-c(rep(2000,14)) doy<-c(16:29) dat<-c(3.2,NA,NA,NA,NA,NA,NA,5.1,NA,NA,NA,NA,NA,4.6) ta<-cbind(yr,doy,dat) ta yr doy dat [1,] 2000 16 3.2 [2,] 2000 17 NA [3,] 2000 18 NA

Good Afternoon, I believe that my to the problem, the R has a more effective solution. in place the use the loop I have the following set of data, and needs to extract some sections. user pos communications source v_destine 7 1 109 22 22 7 2 100 22 22 7 3 214 22 22 7 4 322 22 22 7 5 69920 22 161 7 6

Hi everyone- I have a dataset with multiple "pre" and "post" variables I want to compare. The variables are named "apple_pre" or "pre_banana" with the corresponding post variables named "apple_post" or "post_banana". The variables are in no particular order. apple_pre orange_pre orange_post pre_banana apple_post post_banana person_1

Hi, I have an DNAT ISSUE with PREROUTING. This is my setup. I have 2 firewalls running iptables. Pls asume 1.2.3.4/29 is the internet interace of FIRST firewall. 2.3.4.5/29 is the internet interface of SECOND firewall. it has DMZ zone. in that DMZ zone, mail server runnig @ 192.168.100.3 Now I want to DNAT port 25 of FISRT firewall ( i.e - its ip address - 1.2.3.4/29) to the internet ip

In an effort to select the most appropriate number of clusters in a mixture analysis I am comparing the expected and actual membership of individuals in various clusters using the Fisher?s exact test. I aim for the model with the lowest possible p-value, but I frequently get p-values below 2.2e-16 and therefore does not get exact p-values with standard Fisher?s exact tests in R. Does anybody know

Hi >i have this data > X [1] 5.79 1579.52 2323.70 68.85 426.07 110.29 108.29 1067.60 17.05 22.66 [11] 21.02 175.88 139.07 144.12 20.46 43.40 194.90 47.30 7.74 0.40 [21] 82.85 9.88 89.29 215.10 1.75 0.79 15.93 3.91 0.27 0.69 [31] 100.58 27.80 13.95 53.24 0.96 4.15 0.19 0.78 8.01 31.75 [41] 7.35 6.50

Hello I have a data frame like this: dput(states) structure(list(Date = c("24/07/2012", "25/07/2012", "26/07/2012", "27/07/2012", "28/07/2012", "24/07/2012", "25/07/2012", "26/07/2012", "27/07/2012", "28/07/2012"), State = c(1L, 1L, 1L, 1L, 1L, -1L, -1L, -1L, 1L, -1L)), .Names = c("Date",

Hi List, I have one column of beginning dates and one column of ending dates, I want to find their difference. And I want to ignore the trailing zeros, basically everything after the first colon mark. Begin_date End_date 01JAN2000:00:00:00:000 02FEB2002:00:00:00:000 24MAR2012:00:00:00:000 18MAY2012:00:00:00:000 01OCT2003:00:00:00:000

[My previous message rejected, therefore I am sending same one with some modification] I have 3 vectors with object name : dat1, dat2, dat3 Now I want to create a loop, like : for (i in 1:3) { cat(sd(dati)) } How I can do this in R? Regards,

HI Elisa, You could use ?cut() vec1<-c(33,18,13,47,30,10,6,21,39,25,40,29,14,16,44,1,41,4,15,20,46,32,38,5,31,12,48,27,36,24,34,2,35,11,42,9,8,7,26,22,43,17,19,28,23,3,49,37,50,45) label1<-unlist(lapply(mapply(c,lapply(seq(0,45,5),function(x) x),lapply(seq(5,50,5),function(x) x),SIMPLIFY=FALSE),function(i) paste(i[1],"<x<=",i[2],sep="")))

Hi, Could you please advice some easy way to do the following for a dataframe (header=F) having unequal column- & row- length. 1. Combine/stack/join contents from - a) multiple rows into one column. b) multiple columns into one row. 2. Stack contents from multiple columns (or, rows) into one column (or, row). Thank you. Cheers, Santana [[alternative HTML