similar to: time series line plot: Error in plot.window(...) : invalid 'xlim' value

Displaying 5 results from an estimated 5 matches similar to: "time series line plot: Error in plot.window(...) : invalid 'xlim' value"

2012 Aug 03
5
replacement has length zero. In addition: Warning message: In max(i) : no non-missing arguments to max; returning -Inf
Hi, Here is my data, the first 10 rows > u=regCond_all[1:10,] > dput(u) structure(c(999, 999, 999, 999, 999, 999, 999, 999, 999, 999, 99, 99, 99, 99, 99, 99, 99, 99, 99, 99, 99, 99, 99, 99, 99, 99, 99, 99, 99, 99, 1.9, 2, 1.97, 1.99, 1.83, 1.78, 1.6, 1.52, 1.52, 1.36, 10.53, 9.88, 9.88, 10.53, 10.53, 10.53, 5.26, 9.88, 10.53, 10.53, 5.4, 5.57, 5.46, 5.34, 5.5, 5.59, 5.62, 5.76, 6.23, 6.19,
2012 Jul 16
4
Error in as.xts
Hi I got the following error using as.xts Error in xts(x, order.by = order.by, frequency = frequency, ...) : NROW(x) must match length(order.by) Here is how the data looks like > d1 <- read.csv(file.path(dataDir,"AppendixA-FishCountsTable-2009.csv"), as.is=T) > d1[1:3,] dive_id date time species count size site depth level TRANSECT VIS_M 1 62 10/12/2009
2012 Jul 18
2
loop searching the id corresponding to the given index (timestamp)
Hello, I have the following loop for two data sets: diveData_2008 and diveData_2009. It uses two other data: diveCond_all and fishTable. The problem is at the point to identify the dive_id for the given index (index is timestamp). It keeps on saying for the1st loop Error in fishReport$dive_id[i] <- dive_id : replacement has length zero for the 2nd loop Error in fishReport$dive_id[i + j] <-
2006 Apr 17
0
difference of means as response?
Dear R users, I am looking for some advice on the proper construction of a mixed model in R, using the difference in means as the response and treating within-means residuals as a random effect. I have a dataframe (my own, a snippet of which is given below) that is composed of observations of pollen viability in flowers along tree branches. Flowers (1 to 3 per position) were collected from
2006 May 20
1
intervals from cut() as numerics?
Hi, Given some example data: dat <- seq(4, 7, by = 0.05) x <- sample(dat, 30) y <- sample(dat, 30) error <- x - y I have broken the rage of x into 10 groups and I can calculate the bias (mean(error)) for each of these 10 groups: groups <- cut(x, breaks = 10) max.bias <- aggregate(error, list(group = groups), mean) max.bias group x 1 (4,4.3] -0.7750000 2