similar to: old weird error message

Hi, I have a data frame with 100 variables (numeric and non numeric types), and I want to join them in only one column, like a vector, but i want to keep the non numeric variables like they are. I know that i can do something like this: Suppose that my data is in df variable new_df<-data.frame(c(df[,1],df[,2],df[,3],df[,4],...........) This works but i have 100 variables! Any way of doing

Given: > filename<-paste(tempdir(),"\\","myfile.txt",sep=""); > sub("\\\\","/",filename); [1] "C:/DOCUME~1\\AJAYAS~1\\LOCALS~1\\Temp\\Rtmp2f270T\\myfile.txt" Note: Only the first occurence of \\ is replaced. What is the syntax for replacing every occurence? Thanks. [[alternative HTML version deleted]]

Dear R list, I am trying to read in .xls files. I have tried using package 'gdata', I get the following error. > dataset <- read.xls("June.xls") Wide character in print at /Library/Frameworks/R.framework/Versions/2.14/Resources/library/gdata/perl/ xls2csv.pl line 262. Seems like this is a problem coming from Perl? I tried to install package 'xlsReadWrite', it

Hi all, I'm using a Mac port of R on Mac 10.6. I need to install xlsx package but it does not install. Do any of you know a way to install it? Thanks very much. Sincerely, Victoria Xiao [[alternative HTML version deleted]]

Hi, How to get all list item to one string variable. example a[1]="abc" b[1]="def" output="abc def" Thanks B.Purushothaman -- View this message in context: http://r.789695.n4.nabble.com/How-to-get-all-list-item-to-one-string-variable-tp4636283.html Sent from the R help mailing list archive at Nabble.com.

Dear All, I I have one doubt about use of the command when has the same name (name of command) in two packages. For example: package: Stats package: Signal Both have the filter command. How use the command (filter) to a specific package, when I need work with both packages ? Thanks Julio [[alternative HTML version deleted]]

HI, I have the array list: X<-vector("list", 2) X[[1]] : data frame 1 X[[2]]: dataframe2 now i want to change index 1 and 2 into: "0-10" , "11-20" ,. finally I want to have X[["0-10"]]:dataframe1 X[["11-20"]]:dataframe2 how do I get them? Thanks a lot. Kind regards, Tammy [[alternative HTML version deleted]]

Dear R-help, My dataset (which is a data frame, called 'Calender' here) includes 365 rows representing 365 days for a year. One column ('Season')contains factor data representing seasons, e.g. spring, summer, autumn and winter. Another column (called 'Day') contains data representing wether the day is a working day (I use 'Wd' for short here)or weekend (I use

Hi, I got a small problem on how to define the vector index without manually inspect the vector. example: y=c(2,3,5,2,4,6,8,3,6,2,5) #I have ten set of this kind of vectors (with different values but same length) that I would also like to run the routine below #say; v=the first index in y where the value is larger than 4, in this case index 3, value 5 #what I would like to do is take y[1:v]

Hi! I would like to post the following question: I was trying to figure out how to do the simulation shown in Fig 10.6 of John Verzani's book 'Using R for Intro Statistics'. It is on page 290, with a description on the previous page. It seems like a simple thing... Just needing to duplicate a procedure. (Perhaps I need to do it with a loop?) This is what I was trying:

Hello everybody I have the following problem. I have to load a number of xls files from different folders (each xls file has the same number of columns, and different numbers of rows). Each xls file is named with a number, i.e. 12345.xls and is contained in a folder with same name, say 12345) Once loaded, I want to rbind all of them to obtain a single database. I think I successfully did the

there is a data frame £¬x weekly.returns 2010-1-4 -0.015933327 2010-1-11 -0.015042868 2010-1-18 0.005350297 2010-1-25 -0.049324703 2010-2-1 -0.052674121 when i input colnames(data)[1] <- 'date' it becomes date 2010-1-4 -0.015933327 2010-1-11 -0.015042868 2010-1-18 0.005350297 2010-1-25

Hello together, i have a data.frame, which i want to filter with numbers in a vector. I have a vector (Top10) with these numbers: [1] 205 302 156 378 235 328 183 375 296 374 and i have a data.frame with a Column (CU_NO) with all my Customer numbers. How can i filter this data.frame, with the Numbers in my vector. this one doens't work:

Dear users, I'm trying to learn how to use the "...". I have written a function (simplified here) that uses doBy::summaryBy(): # 'dat' is a data.frame from which the aggregation is computed # 'vec_cat' is a integer vector defining which columns of the data.frame should be use on the right side of the formula # 'stat_fun' is the function that will be run to

Dear users, I am looking for a function to choose a folder interactively, just like file.choose() but for a folder. I have found tcltk::tk_choose.dir() but R hangs when I try to do anything and I have to force exit. I've tried to reinstall tcltk with install.packages(), but "package ?tcltk? is not available (for R version 2.15.2)" even though it's already installed on my

Dear users, I am looking for a function to choose a folder interactively, just like file.choose() but for a folder. I have found tcltk::tk_choose.dir() but R hangs when I try to do anything and I have to force exit. I've tried to reinstall tcltk with install.packages(), but "package ?tcltk? is not available (for R version 2.15.2)" even though it's already installed on my

Hello R Community, I don't post to these things often so excuse me if I stumble on my forum etiquette. This is a complex problem for me, which may require two forum entries, but I will try my best to be concise. Also, I am a self taught coder, so if my code is not to convention, your constructive criticism is always welcome. I need to split up a data frame by participant (gpsarc -

Hi, I have a 1-column dataframe with rownames and I want to sort it based on the single column. The typical procedure that is recommended in diverse posts is to use order in the index. But that "destroys" my dataframe structure. Probabaly it is a very simple solution. Here is a short reproducable example: x <- c(1,3,51,2,34,44,12,33,2,8) df <- data.frame(x) rownames(df) <-

How do I remove a "$" character from a string sub() and gsub() with "$" or "\$" as pattern do not work. > sub("$","","ABC$DEF") [1] "ABC$DEF" > sub("\$","","ABC$DEF") Error: '\$' is an unrecognized escape in character string starting "\$" >

Dear r-users,   Originally my data is in notepad.  I use data.frame(...) to convert the data into columns but it has no header.  The data below is what I got in R.  I would like to extract these data:   19710629        39.3  19701126  19720629        33.8  19720517 ... when I use data2_30min[1, cbind(1,3,5)] command the result is NULL.   Then I tried data2_30min[1], it gives me the whole set of