Displaying 10 results from an estimated 10 matches similar to: "Problem building dll in R-2-15-1"
2012 Jun 26
3
plotting two histograms on one plot with hist function
I would like to plot two data sets (frequency (y-axis) of mean values for 0-1(x=axis)) on a single histogram for comparison. The hist() only allow the overlay of two histograms, and although barplot() allows beside=TRUE, it does not show frequency values (like hist) but rather all of the values. Is there any way that I can use the hist() to plot two data sets similar to the barplot(). Any help or
2012 Mar 12
1
2 images on one plot
Dear all
with image I can plot only one set of values in one plot.
Do somebody have any insight how to put those 2 matrices into one picture
so that in one cell in image picture are both values from mat[1,1] and
mat2[1,1].
mat<-matrix(1:4, 2,2)
mat2<-matrix(4:1,2,2)
x <-1:2
y <-1:2
image(x, y, mat)
image(x, y, mat2)
The only way I found is to mix x or y for both matrices let
2003 Feb 27
2
PRESS again
Sorry for the repeat.
The PRESS statistic is defined as
sum(y-yhat(i))^2, where yhat(i) denotes the ith predicted value using
all the data except the ith case (as used typically in linear models).
Thanks again
Jacob
Jacob L van Wyk
Department of Mathematics and Statistics
Rand Afrikaans University
P O Box 524
Auckland Park 2006
South Africa
Tel: +27-11-489-3080
Fax: +27-11-489-2832
2011 Jul 21
2
Latex Table Help on R
Hello everyone,
Peter (see my earlier post) recommended the following script for finding the
means and standard deviations and putting them in table form.
However, I would like the standard deviations under the means in brackets.
Can anyone check this code to see how this can be adjusted?
library(xtable)
dataset1 = matrix( c(1,2,3,4, 5, 6 ), 2 , 3)
dataset2 = matrix( c(4,3,5,10, 1, 0), 2, 3)
2003 Mar 07
1
Boot
Hallo
Could anybody please help.
I have a simple linear regression model with 5 predictors. I want to
use "bootstrap residuals" to make inferences regarding beta(2)hat. After
fitting the model y=b0+b1+b2+b3+b4+b5 I tried the following:
mod <- lm(y ~ x1+x2+x3+x4+x5)
res <- resid(mod)
pred <- predict(mod)
Now, I have tried
boot(res, lm(res+pred ~ x1+x2+x3+x4+x5)$coef[3],
2009 Sep 23
1
graduation
Hi everyone
I want help in graduating the attached rates and checking for goodness
of fit and smoothness using R please help.
Many thnk
TOo every one around the world
This message and attachments are subject to a disclaimer. Please refer
to www.it.up.ac.za/documentation/governance/disclaimer/ for full
details. / Hierdie boodskap en aanhangsels is aan 'n vrywaringsklousule
onderhewig.
2010 Feb 18
0
Appropriate test for overdispersion in binomial data
Dear R users,
Overdispersion is often a problem in binomial data. I attempt to model a
binary response (sex-ratio) with three categorical explanatory variables,
using GLM, which could assume the form:
y<-cbind(sexf, sample-sexf)
model<-glm(y ~ age+month+year, binomial)
summary(model)
Output:
(Dispersion parameter for binomial family taken to be 1)
Null deviance: 8956.7 on 582
2019 Feb 20
0
Please Recommend Affordable and Reliable Cloud Storage for 50 TB of Data
I gave you a lengthy description of the Fedora lists.
It's rather rude to see your question here again.
Met vriendelijke groet,
Hans Witvliet, J, Ing., DMO/OPS/I&S/APH, Kennis Team Opensource
Coldenhovelaan 1 Maasland 3531RC Coldehovelaan 1, kamer B213
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2012 Jul 09
0
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2006 Aug 28
0
Splancs Query
Dear R Users;
I have been using the space-time K-function analysis to detect the existence
of clustering in both space and time. I wish to ask and know what the
minimum number of cases should be for such analyses to be valid. I have
data with 23 cases and don't know how careful i should be in the
interpreting the results.
Secondly, i wish to find out if there is any bond between the