similar to: R Beginner : Loop and adding row to dataframe

Hi! I will calculate sum??s in the following way: E.g.: a <- rpois(100,20) b <- rpois(100,5) x <- data.frame(cbind(a,b)) # the sum??s should be calculated based on a. attach(x) sort.nace <- unique(sort(x[,1])) sum1 <- matrix(ncol=1, nrow=length(sort.nace)) # I calculate the sum of all values of b, which have the same category in a. Eg.: sum1[1,] <- sum(subset(x,

Folks, It has been a whole day spent on this but I still can''t get my mind around the most probably very stupid/basic mistake here... First, the code I use: <h3>List A</h3> <ul id="lista" > <li id="item1"> Item 1</li> <li id="item2"> Item 2</li> <li id="item3"> Item 3</li> </ul>

Hi, I am attempting to use phyper to test the significance of two overlapping lists. I keep getting a zero and wondered if that was determining non-significance of my overlap or a p-value too small to calculate? overlap = 524 lista = 2784 totalpop = 54675 listb = 1296 phyper(overlap, lista, totalpop, listb,lower.tail = FALSE, log.p=F) [1] 0 If I plug in some different values I get a p-value but

Hola, necesito contar la cantidad de caracteres de cada elemento de un vector o factor Por ejemplo si el factor es: a<-c("jose", "javier", "mariano") aplicando alguna funcion, el resultado q quiero es 4, para jose 6 para javier 7, para mariano q es la cantidad de caracteres q tiene cada uno de los elementos del factor a probe usando length(a) y me da la

Hi R friends, I am posting this question even though I know that the nature of it is closer to general stats than R. Please let me know if you are aware of a list for general statistical questions: I am looking for a simple method to distinguish two groups of data in a long vector of numbers: list <- c(1,2,3,2,3,2,3,4,3,2,3,4,3,2,400,340,3,2,4,5,6,4,3,6,4,5,3) I would like to

Hola alguien sabe una sentencia simple para calcular la mediana ponderada por una variable? Gracias -- "*El peor analfabeto, es el analfabeto político.* Él no ve, no habla, no participa de los acontecimientos políticos. Él no sabe que el costo de la vida, el precio del pescado, de la harina, del alquiler, del calzado o del remedio dependen de las decisiones políticas. *El analfabeto

Hi. This is likely a trivial problem but have not found a solution. Imagine the following dataframe: Lat Lon x1 x2 x3 01 10 NA NA .1 01 11 NA .2 .3 01 12 .4 .5 .6 I want to generate another column that consist of the first value in each row from columns x1 to x3. That is NewColumn .1 .2 .4 Any input greatly appreciated, Thanks, Camilo Camilo Mora, Ph.D.

Hi there, Given 2 lists of integer vectors, i.e.: > lista1 $"1" [1] 1 34 5 $"2" [1] 2 1 $"3" [1] 3 10 15 > lista2 $"1" [1] 1 5 $"2" [1] 2 1 $"3" [1] 3 10 29 I want to obtain the union of both, defined as the union of the vectors, that is lista.union[[1]] <- union(lista1[[1]],lista2[[1]]): > lista.union

Hola tengo q hacer un trabajo, donde me piden q todas las salidas q haga sean en Power Point (graficos, tablas, etc). Para eso habia empezado a leer algo del paquete R2PPT, pero la verdad es q hay cosas q no entiendo de este paquete. Queria saber si alguien estuvo trabajando con el y obtuvo buenos resultados o si han usado otro paquete para hacerlo. Por ultimo una pregunta: desde Sweave se

I have 3 sortables, namely lista, listb and listc. Lista being a static list of items and will be drag n drop to listb and listc. Everytime I drag from lista to either listb or listc, the items in lista will be removed. Is that normal? If so, can anyone advice how can I maintain the items in lista so that I can have duplicate items in listb and listc. I am using rails for the development.

Hello Jeremy and Ralph Thanks for your suggestions. I compiled samba-4.8.0 and running it instead of samba-4.6.2. I saw the changes that you mentioned in the latest vfs_nfs4acl_xattr module. The operation not supported error is gone but it is now failing with access denied. Here is what I tried: *[root at test3 ajain]# net conf showshare local[local] path = /home/ajain/mount

Hi everyone- I have a dataset with multiple "pre" and "post" variables I want to compare. The variables are named "apple_pre" or "pre_banana" with the corresponding post variables named "apple_post" or "post_banana". The variables are in no particular order. apple_pre orange_pre orange_post pre_banana apple_post post_banana person_1

In an effort to select the most appropriate number of clusters in a mixture analysis I am comparing the expected and actual membership of individuals in various clusters using the Fisher?s exact test. I aim for the model with the lowest possible p-value, but I frequently get p-values below 2.2e-16 and therefore does not get exact p-values with standard Fisher?s exact tests in R. Does anybody know

Hi >i have this data > X [1] 5.79 1579.52 2323.70 68.85 426.07 110.29 108.29 1067.60 17.05 22.66 [11] 21.02 175.88 139.07 144.12 20.46 43.40 194.90 47.30 7.74 0.40 [21] 82.85 9.88 89.29 215.10 1.75 0.79 15.93 3.91 0.27 0.69 [31] 100.58 27.80 13.95 53.24 0.96 4.15 0.19 0.78 8.01 31.75 [41] 7.35 6.50

Hi List, I have one column of beginning dates and one column of ending dates, I want to find their difference. And I want to ignore the trailing zeros, basically everything after the first colon mark. Begin_date End_date 01JAN2000:00:00:00:000 02FEB2002:00:00:00:000 24MAR2012:00:00:00:000 18MAY2012:00:00:00:000 01OCT2003:00:00:00:000

[My previous message rejected, therefore I am sending same one with some modification] I have 3 vectors with object name : dat1, dat2, dat3 Now I want to create a loop, like : for (i in 1:3) { cat(sd(dati)) } How I can do this in R? Regards,

HI Elisa, You could use ?cut() vec1<-c(33,18,13,47,30,10,6,21,39,25,40,29,14,16,44,1,41,4,15,20,46,32,38,5,31,12,48,27,36,24,34,2,35,11,42,9,8,7,26,22,43,17,19,28,23,3,49,37,50,45) label1<-unlist(lapply(mapply(c,lapply(seq(0,45,5),function(x) x),lapply(seq(5,50,5),function(x) x),SIMPLIFY=FALSE),function(i) paste(i[1],"<x<=",i[2],sep="")))

Hello I have dataframe How to remove dates in hourly time seriesThe example time series likedate value 2000-01-05 00:00:00 1.0 2000-01-05 01:00:00 1.0 2000-01-05 05:00:00 3.6 2000-01-05 06:00:00 3.6 2000-01-05 07:00:00 2.2 2000-01-05 08:00:00 2.2 2000-01-05 09:00:00 2.2 2000-01-05 10:00:00

Hi, Could you please advice some easy way to do the following for a dataframe (header=F) having unequal column- & row- length. 1. Combine/stack/join contents from - a) multiple rows into one column. b) multiple columns into one row. 2. Stack contents from multiple columns (or, rows) into one column (or, row). Thank you. Cheers, Santana [[alternative HTML

Hello, I have a data set that needs to be combined so that rows are summed by a group based on a certain variable. I'm pretty sure rowsum() or rowsums() can do this but it's difficult for me to figure out how it will work for my data based on the examples I've read. My data are structured like this: Plot SizeClass Stems 12 Class3 1 12 Class4