similar to: A graph with a positive y-axis intercept

Hi I have a follow up question, relating to subsetting to list items. After using the list and min(sapply()) method to adjust the length of the variables, I specify a dynamic regression equation using the variables in the list. My list looks like this: Dcr<- list(Dcre1=DCred1,Dcre2=DCred2,Dcre3=DCred3,Dbobc1=DBoBC1,Dbobc2=DBoBC2,Dbobc3=DBoBC3,...) By specifying the list items with names, I

hi all, after fitting a multiple linear regression model <- lm(y ~ a + b+ c+d) i wanted to plot diagnostics plot(model) but get the error message Error in object$coefficients : $ operator is invalid for atomic vectors. which does not make a lot of sense, since there is no "$" - i am working with an attached dataset. can anyone help, please?? thanks a lot, kat

Hi R users, How can I automatically export results and graphs to a file? Thanks in advance Pedro Mota Veiga -- View this message in context: http://r.789695.n4.nabble.com/Export-Results-tp2268622p2268622.html Sent from the R help mailing list archive at Nabble.com.

I'm using Solaris 8, samba 3, kerberos and openldap. I'm anexing: log.smbd, smb.conf, krb5.conf, nsswitch.conf and the ktpass command in AD. Somebody can help me? I get this output in log.smbd: ----------------------------------- [2005/08/11 12:41:45, 0] smbd/server.c:main(802) smbd version 3.0.20rc1 started. Copyright Andrew Tridgell and the Samba Team 1992-2004 [2005/08/11

Dear R experts: Here is my problem: #Data 1 Y <- c(0.5, 0.1, 0.5, 1.3, 1.4, 1.6, 1.65, 2.4, 2.6, 3.4, 3.6, 4.3, 4.42, 4.8, 4.7, 3.4, 3.3, 2.8, 2.8, 1.2, 1.1, 0.5, 0.2, 0.1, -0.2, -1.5, -2.5, -1.3, -0.5, -0.1) X <- seq(1:30) X1 <- c(rep("T1", 24), rep("T2", 6)) dat1 <- data.frame(Y, X, X1) require(lattice) mcol <- c("green", "red")

Hi, I have my data in below format. position var1 var2 2 .1 10 3 .29 89 12 .56 100 425 .34 1234 6546 .12 21 .... ..... ..... .... ..... ......

Dear R users,   I need to draw a barplot with 2 Y axis. I have 3 days each of wich having 2 groups (and error bar for each of them). The height of the 3rd day is too tall compared to others. That's why I have to use a second Y axis for that. I am using  "barplot2" function of "gplots" library (to be able to add error bars as well). Data and  codes currently I am using is

Hi all, After writing data in MMF(Memory Map File) using SEXP structure, can i reference in R? If input data is larger than 2GB, Can i reference MMF Data in R? my work environment : R version : 2.11.1 OS : WinXP Pro sp3 Thanks and best regards. Park, Young-Ju from Korea. ---------[ ???????? ???????? ???????? ]---------- ???????? : R-help Digest, Vol 89,

Dear All, Having a bit of trouble with plotting two y variables on the same graph. I cannot manage to get the secondary y axis label on to the right of the axis - it gets plotted beyond the graphic window I assume?! The way I constructed the graph is thus: plot(data[,3],data[,2],axes=F, type="b") ## plots my data from two data colums without axes - fine axis(1, at=data[,3])

Since I have a mixture of RH 7.1, 7.2, 7.3 and Advanced Server 2.1 boxes, I've made a set of RPMs for those platforms. I do not have a RedHat 8.0 box to make RPMs. Since RedHat <= 7.2 is out of support by RedHat, I don't think we'll see any officially created RPMs (but I could be wrong about that) so I thought I'd offer these to the general community. These were all built

Hello, R-help, does anybody have already a work-around for the problem that the formula version of sunflowerplot() throws an error when provided with a value for xlab (or ylab) different from NULL: > sunflowerplot( Sepal.Length ~ Sepal.Width, data = iris, xlab = "A") Error in model.frame.default(formula = Sepal.Length ~ Sepal.Width, data = iris, : variable lengths differ

dear useRs, i want to overlap graphs of two matrices in such a way that the y-axis of graph should be "logarithmic" against normal x-axis. i am, unsuccessfully, trying the followings >matplot(mata, log="mata",type = "l", col="red)>lines(mata, log="matb",type = "l", col="yellow") could you please help me out on it?? thanks in

I like the functionality provided by outer=TRUE, but when it comes time to place separate xlabs or ylabs, I always end up 'eyeballing' it on a case-by-case basis. For example, ##begin example require(lattice) cars.lo <- loess(dist ~ speed, cars) print(xyplot(cars.lo$residuals+cars.lo$fitted~cars.lo$x, strip=FALSE, outer=TRUE, layout=c(1,2),

Hello- My question is a short one. How can I specify a single point which through the fitted linear model has to go through? To illustrate my problem, the fit to following data must go through the point (-37.25(effect), 50(prob)). Note: you can ignore the label column. Effect Prob Label 1 -1143.75 7.142857 L 2 -572.75 21.428571 D 3 -223.75 35.714286 GL 4 123.25

Hello everyone, Quick question...is there a way of specifying a y-intercept value within a lm statement. For example, if I wanted to specify the regression to pass through the origin I would enter lm(y~0+x). But can I specify an actual term such as 1,2,3,4, etc. as an intercept value? Thank you! -- Benjamin Zuckerberg Doctoral Candidate State University of New York College of

R-gurus, I am plotting data against each other using t-tests. In this scenario, I am plotting coinage / total money. When there is no total money, then there is no coinage, but the plots I generate do not reflect this. Instead the y-axis always has an intecept that is not zero in these instances. Is there any way to force the y-intercept to begin at zero? Thank you in advance for any

Hi, In my discpipline, it is common to plot one acoustic property on a positive scale but from top to bottom on the ordinate and the same for another measurement on the abscissa. So, the origin of the plot is on the top right of the plot, with increasing values to the left /down. This is to highlight the correlation between the acoustic measurement and the position of the forming structure, for

Hello everyone, Is it possible to specify a 2 line y-axis label on the same lef-hand side y-axis? I am using the \n regular expression, but only the 2nd line appears (I assume the 1st line is printed off the page...) plot(PRE_SHB,R1, main="Figure 1.1: Scatterplot of Residualized Post Score", xlab = "Pre Score", ylab = "Residualized Post Score \n (Adjusted for Age

Dear R-help team I have tried hard to turn my Y axis 90 degrees, so that it is written horizontally, and placing it above the Y axis, but I did not succeed. I have tried to adapt the following functions: - plot() - title() - mtext() And some more that did not prove to be useful (e.g. text() etc). The closest I got to my aim was with mtext(): mtext("Yield

My personal archive of RPM packages for RedHat 7.1 - 7.3, Redhat 9.0 and Redhat Advanced Server 2.1 are updated for OpenSSH 3.7.1p2 at http://bamboo.lexi.com/openssh -- Jason