similar to: extracting rows and columns from a big matrix

Hello All, I have a question about glm in R. I would like to fit a model with glm function, I have a vector y (size n) which is my response variable and I have matrix X which is by size (n*f) where f is the number of features or columns. I have about 80 features, and when I fit a model using the following formula,? glmfit = glm(y ~ x1 + x2 + x3 + x4 + x5 + x6 + x7 + x8 + x9 + x10 + x11 + x12 + x13

I don't see the issue here. It would be helpful if people would report their sessionInfo() when reporting whether or not they see this issue. Mine is > sessionInfo() R version 3.4.3 (2017-11-30) Platform: x86_64-pc-linux-gnu (64-bit) Running under: Arch Linux Matrix products: default BLAS/LAPACK: /usr/lib/libopenblas_haswellp-r0.2.20.so locale: [1] LC_CTYPE=en_US.UTF-8

Hello, I have looked on https://www.r-project.org/bugs.html , but it seems that this is the only way to do it. The issue is that the precision used by write.csv is on consistant for big files. See the following code: First I create a large dataframe filled with random uniform values. Then I write it to .csv and print out the first and last lines. df = data.frame(replicate(100, runif(1000000,

To my surprise, I can confirm on Windows 10 using R 3.4.3 . As tail is not recognized by Windows cmd, I replaced with: system('powershell -nologo "& "Get-Content -Path temp.csv -Tail 1') The last line shows only 7 digits after the decimal, whereas the first have 15 digits after the decimal. I agree with Dirk though, 1.6Gb csv files are not the best way to work with

Dear List, I've around 1000 *.txt files, I've generate with other software. I've now done the following code (below). My question is how can I automate this (with do.call () ?), so it could be done for all the *.txt files. Thanks in advance, Rog??rio names<- list.files() file <- "BLU_Var_%04d.txt" for(i in 1:1000){

Hi - a newbie question, if someone can please help.... I want to change X1, X2,,.....to X.1 X.2 etc in the names below. I am using the Principal Component Regression function (pcr) and it seems to want it this way > datap3.pcr <- pcr(water ~ X, 10, data = datap3, Validation ="cv") Error in model.frame.default(formula = water ~ X, data = datap3) : invalid type (list) for

If you want a character representation of a long formula (or a formula with long names), you can use: as.character(my.formula) However restriction on length of an as.character result returns only the beginning of a long formula, and without comment. In most cases, the following expression provides the complete result: paste(my.formula[[2]], " ~ ",

Hi, I was wondering how it was possible to access the actual cluster exemplars from the APResult class. Currently it only spits it out onto the terminal if you type the object but there is no other way to see which one is the examplar. Would appreciate any help. Thanks, Sachin [[alternative HTML version deleted]]

Hello everyone, I am trying to fit the following model All X. variables are continuous, while the conditions are categoricals. model <- lm(X2

Hallo, All, I have a question about changing the height or scale of the y axis. When I use following two R codes, I can get two plots. Please look at the y axes, the number of indices (x1, x2, ?) on the y axis in the first plot is smaller than that in the second plot, and hence the space between any two indices in the first plot is wider than that in the second plot. As the number of indices

Hi All, I have a query about time based sequences. I know such questions have been asked a lot on forums, but I couldnt find the exact thing that I was looking for. I want to create a time-based sequence which will mimic the trading window AND would span multiple days. Something like below: "2011-01-03 09:15:00 IST" "2011-01-03 09:15:01 IST" .... .... .... "2011-01-03

Hi.. i have an expression of the form: model1<-nls(y~beta1*(x1+(k1*x2)+(k1*k1*x3)+(k2*x4)+(k2*k1*x5)+(k2*k2*x6)+(k3*x7)+(k3*k4*x8)+(k3*k2*x9)+(k3*k3*x10)+ (k4*x11)+(k4*k1*x12)+(k4*k2*x13)+(k4*k3*x14)+(k4*k4*x15)+(k5*x16)+(k5*k1*x17)+(k5*k2*x18)+(k5*k3*x19)+

Full_Name: Derek Elmerick Version: 2.4.0 OS: Windows XP Submission from: (NULL) (38.117.162.243) hello - i have some code that i run regularly using R version 2.3.x . the final step of the code is to build a multinomial logit model. the dataset is large; however, i have not had issues in the past. i just installed the 2.4.0 version of R and now have memory allocation issues. to verify, i ran

I have a dataset that is basically structureless. Its dimension varies from row to row and sep(s) are a mixture of tab and semi colon (;) and example is HEADER1 HEADER2 HEADER3 HEADER3 A1 B1 C1 X11;X12;X13 A2 B2 C2 X21;X22;X23;X24;X25 A3 B3 C3 A4 B4 C4 X41;X42;X43 A5 B5 C5 X51 etc., say. Note that a blank

Hello, I'm working with an array; I'm trying to make it so that an array of dim(42,2,2) has names whose length corresponds to that of the array, and am hoping someone with experience with this can see what I'm not doing correctly: data11 = array(0,c(41,2,2)) y = lsoda(x0,times,fhn$fn.ode,pars)#This is make.fhn() from colloc infer package# y = y[,2:3]

Hello Folks, I have a database of 2000+ days with 35 observations each. I am trying to modeling a time series by day, but it seems a problem that I don<t have the time of the observation. I achieve something interesting by using the barplot function, but I`d rather working with ggplot2, since I have the book by Hadley Wickham in hands. I start by transforming my data into a dataframe, but

Hello, I have a couple of questions with regards to fitting a coxph model to a data set in R: I have a very large dataset and wanted to get the baseline hazard using the basehaz() function in the package : 'survival'. If I use all the covariates then the output from basehaz(fit), where fit is a model fit using coxph(), gives 507 unique values for the time and the corresponding cumulative

Hi All I am having 2 very long character strings (550chars) and I want to put them as expressions together with c(). The problem is that I also get these double-quotes, as seen below in 'fct'. How can I remove these double-quotes? I tried as.name() but it did not work (because of size?). These are creating trouble with subsequent programs, which I tested with strings that for some

I've never seen this, and have no idea how to reproduce it. For resloution you are going to have to give me a working example of the failure. Also, per the posting guide, what is your sessionInfo()? Terry Therneau On 08/09/2012 04:11 AM, r-help-request at r-project.org wrote: > I have a couple of questions with regards to fitting a coxph model to a data > set in R: > > I have a

My apologies for not including sessionInfo(), and I'm a bit angry at myself for that. Retrying in a fresh session of R, I get different results. More specifically, I get the expected result where accuracy is the same in the first and the last line. As I didn't include my sessionInfo() in my previous mail, I can't figure out why I now have a different result. So I'm positive