similar to: image.plot transparent?

Displaying 20 results from an estimated 4000 matches similar to: "image.plot transparent?"

2011 Nov 15
2
points() colored by value
Hi R users, I want to colored points by their value for example: x <- c(1,2,3,4) y <- c(1,2,3,4) z <- c(2,3,4,9) y and x are coordinates z is the value of the coordinates points(x,y,col= rainbow(z)) something like that But haven't found any solution at the moment. Thanks. Chris -- View this message in context:
2013 Mar 28
2
Can R read in .xyz files
Hi, Can R read in .xyz files? If so, what is the package, thanks -- Shane [[alternative HTML version deleted]]
2013 Jan 29
3
Can I define a object array in R?
Here is my problem, 100 decision trees were built(similar to random forest) and I want to replace some of them by new trees. How can I define a tree array including 100 trees, i.e. t[100], and every t[n] is an "C5.0" object, such that when a new tree comes, i can do n<-10 t[n]<-C5.0(...) -- View this message in context:
2013 May 16
1
connect to local mySQL database
Hi, I would like to access a local mysql database. In python using the sqlite3 library it is quite straightforward. I just have to pass the path to the sqlite-file; sqlite3.connect('.../xy.sqlite') Is there something similar in R (or specifically in the RMySQL package)? It seems like I have to use the MySQL function in the RMySQL package in order to ... "initializes a MySQL
2012 Feb 01
6
While loop working with TRUE/FALSE?
Hi R users, is there any possibilty that a while loop is working like that: z <- c(0,1,2,3,4,5,6,7,8,9) r <- 7 while(w == T) { for ( i in 1:10 ){ w <- r == z[i] print(w) } } The loop should stop if w == TRUE best regards -- View this message in context:
2016 Apr 15
1
Decision Tree and Random Forrest
I need the output to have groups and the probability any given record in that group then has of being in the response class. Just like my email in the beginning i need the output that looks like if A and if B and if C then %77 it will be D. The examples you provided are just simply not similar. They are different and would take interpretation to get what i need. On Apr 14, 2016 1:26 AM,
2012 Jul 10
2
how can I show the xlab and ylab information while using layout
hi R-users: I want to draw three plot into one figure by layout and the script has been shown below. But I find R does not show the xlab and ylab information completely as shown the figure attached. How can I midify the script.? thank you . xxlab<-paste(cpmd," (",ro,"%)",sep=" ") yylab<-paste(rfmd," (",co,"%)",sep=" ")
2008 Nov 10
2
Make one vector from matrix comparison
Hello R-users, I have a little problem. I compare each row of a matrix with each row of another matrix. testmat1 <- matrix(c(1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16), nrow=4) testmat2 <- matrix(c(1,2,3,5,5,6,7,8,9,10,11,12,13,14,15,16), nrow=4) Both matrix differs in the last row. Now I create a loop: for (i in (1:4)){ for (j in (1:4)){ b <- (c(setequal(testmat1[j,],testmat2[i,])))
2011 Dec 03
4
Data alignment
Hello! I have a data.frame which looks like: Name - Value A - 400 A - 300 B - 200 B - 350 C - 500 C - 350 D - 450 D - 600 E - 700 E - 750 F - 630 F - 650 I want to add another column where all A,B should get an index 1, all C,D an index of 2 and all E,F an index of 3 so that the data.frame looks like: ID - Name - Value 1 - A - 400 1 - A - 300 1 - B - 200 1 - B - 350 2 - C - 500 2 - C - 350 2
2008 Oct 22
3
Substitute problem
hello R users, I didn't find a solution for a special problem. I have two dataframes. dataframe1: X value row col ID 1 8.973498062 5512625 3460000 1 2 11.656658570 5501625 3464000 2 3 11.121777570 5495625 3473000 3 4 9.310465964 5508625 3477000 4 5 8.883483845 5515625 3496000 5 dataframe2: X value
2018 May 30
0
par(mfrow=c(3,4)) problem
Hi, You're mixing base plot and ggplot2 grid graphics, which as you've discovered doesn't work. Here's av strategy that does: https://cran.r-project.org/web/packages/egg/vignettes/Ecosystem.html This vignette has a good overview, well as info specific to that package. Sarah On Wed, May 30, 2018 at 4:43 AM greg holly <mak.hholly at gmail.com> wrote: > Hi all; >
2012 Nov 22
4
Data Extraction
Hello, I would appreciate if someone could help me resolve the following: 1. df1[!is.na( X1 | X2 | X3 | X4 | X5),][,1:5] # This does not work 2. Is these message harmful? The following object(s) are masked from 'df1 (position 3)': X1, X2, X3, X4, X5 Thanks, Pradip Muhuri #Reproducible Example set.seed(5) df1<-data.frame(matrix(sample(c(1:10,NA),100,replace=TRUE),ncol=5))
2016 Apr 14
3
Decision Tree and Random Forrest
I still need the output to match my requiremnt in my original post. With decision rules "clusters" and probability attached to them. The examples are sort of similar. You just provided links to general info about trees. Sent from my Verizon, Samsung Galaxy smartphone<div> </div><div> </div><!-- originalMessage --><div>-------- Original message
2016 Apr 15
0
Decision Tree and Random Forrest
Since you only have 3 predictors, each categorical with a small number of categories, you can use expand.grid to make a data.frame containing all possible combinations and give that the predict method for your model to get all possible predictions. Something like the following untested code. newdata <- expand.grid( Humidity = levels(Humidity), #(High, Medium,Low)
2008 Sep 17
1
Re adout row and column of a matrix value
Hello R users, I want to readout the row and column postion from a certain matrix value into a csv file. I have only found this syntax "which(a == b, arr.ind = T)" so I get a = matrix [,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [1,] 1 1 2 2 2 1 1 2 [2,] 1 2 3 3 3 4 4 3 [3,] 3 3 3 5 5 6 5 4 [4,] 4 4 4 3
2008 Nov 25
1
add string to a list
hello R users, I didn't find a solution for a simple problem I think. I read 224 lines from a file input <- readLines(con,n=224) and now I create a string x <- "\004" which should be line 225 of input. So I have input and x and want to add x to input, so that it looks like this: [1] "string" [2] "string" . . . [224] "string" [225]
2011 Feb 03
2
substring and paste character with a for loop
Hello R users, I have a little problem with a for loop. Below there is an simple example of my problem. I want to delet the commas in the character string. Fore this reason I create a for loop to unpick the string and rebuild him without the commas. The problem is, that "paste" does not work in the loop as I expected. text <- "aaa,bbb,ccc,ddd" characterseq <-
2013 Apr 16
2
R process slow down after a amount of time
Hi R users, I have mentioned that R is getting slower if a process with a loop runs for a while. Is that normal? Let's say, I have a code which produce an output file after one loop run. Now after 10, 15 or 20 loop runs the time between the created files is stongly increasing. Is there maybe any data which fill some memory? Chris -- View this message in context:
2011 Sep 16
3
How to save row values from a matrix into one vector?
Dear R users, I guess, I have a quit simple problem, but I'm not getting the solution. I create a matrix like this: test <- matrix(seq(1,3,1),ncol=5,nrow=3) then I want to create one vector, consisting of every row of the matrix. My first idea was to do this with a for loop. op <- vector() for (o in 1:3){ op[o] <- as.vector(test.id[o,]) } The results should be like this: [1]
2018 May 30
4
par(mfrow=c(3,4)) problem
Hi all; I need to put 12 different plot2 into the same matrix. So my array for the matrix will be par(mfrow=c(3,4)). I am running ggplot2 to produce my 12 plots. For some reason, par(mfrow=c(3,4)) did not turn out 3*4 matrix. my basic R codes for each plot is par(mfrow=c(3,4)) library(ggplot2) p <- ggplot(a, aes(x=Genotypes, y=Plant_hight, size=Plant_hight, color=Showing_rate)) + . . Best