similar to: How to use Sys.time() while writing a csv file name

Displaying 20 results from an estimated 800 matches similar to: "How to use Sys.time() while writing a csv file name"

2011 Mar 25
1
Appending data to a data.frame and writing a csv
Dear R helpers exposure <- data.frame(id = c(1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20), ead = c(9483.686,50000,6843.4968,10509.37125,21297.8905,50000,706152.8354, 62670.5625, 687.801995,50641.4875,59227.125,43818.5778,52887.72534,601788.7937, 56813.14859,4012356.056,1419501.179,210853.4743,749961,6599.0862), pd =
2011 Jan 20
0
Bandwidth - Kernel Density Estimation
Dear R helpers I am having recovery rates as given below and I am trying to estimate the Loss Given Default (LGD) and for this I am using Kernel Density estimation method. recovery_rates = c(0.61,0.12,0.10,0.68,0.87,0.19,0.84,0.81,0.87,0.54,0.08,0.65,0.91, 0.56,0.52,0.30,0.41,0.24,0.66,0.35,0.36,0.64,0.55,0.43,0.36,0.28,0.89,0.11,0.23,0.07,
2011 Aug 15
2
A small nag
Hi, I am not sure how to fix the following error. LGD <- c(11.6, 12.3, 15.8, 33.1, 43.5, 51.3, 67.3, 84.9) cor (x=(file [1:47231,3:10]), y= rep (LGD, 47231), method = "pearson") Error in cor(x = (file[1:47231, 3:10]), y = rep(LGD, 47231), method = "pearson") : incompatible dimensions > sessionInfo() R version 2.13.0 (2011-04-13)
2012 Jul 18
4
The best solver for non-smooth functions?
# Hi all, # consider the following code (please, run it: # it's fully working and requires just few minutes # to finish): require(CreditMetrics) require(clusterGeneration) install.packages("Rdonlp2", repos= c("http://R-Forge.R-project.org", getOption("repos"))) install.packages("Rsolnp2", repos= c("http://R-Forge.R-project.org",
2005 Apr 12
2
not plotting when non-existent
R-help, I'm trying to plot the following: year lgd 1 1986 136.97479 2 1987 69.10377 3 1988 67.66744 4 1989 71.60316 5 1990 62.06897 6 1992 6.25000 7 1993 27.72021 8 1995 23.83648 9 1996 10.29412 10 1997 95.67487 11 1998 82.09367 12 1999 56.60401 13 2000 29.80864 14 2001 23.77535 15 2002 48.30378 16 2003 83.47571 17 2004 74.58711 There are 2 missing years
2010 Jan 21
1
Cannot join domain
Hello, I just configured a computer on my local network to work as a PDC with Samba, although I'm not able to join the Domain from the windows computer I want to add. I though it was that the server was unreachable, but I can ping the server from the computer and viceversa. If someone please can help me, I'll appreciate it. The smb.conf file is here: ------------------- [global]
2007 Dec 16
1
./configure perfparse -> "configure: error: required library libgd unusable"
I recently had a problem with the configure script from perfparse running properly so that I could 'make install' it to work with Nagios 2.10 on latest CentOS 4.x + RPMForge (see http://readlist.com/lists/centos.org/centos/5/28966.html). Thinking it was a problem that was a result of "yum remove gd", I formatted the box and reinstalled everything. Now, oddly, I still have the
2011 Apr 06
1
executing from .R source file in the src package
Can I run R code straight from R src (.R) file instead of .rdb/.rdx? I of course tried simply unzipping tar.gz in the R_LIBS directory but R complains with "not a valid installed package". Real issue: I am very new to R and all, so this could be something basic. I'm trying to use ess-tracebug (Emacs front-end to trace/browser et al). It works great when I trace functions in .R
2010 Sep 01
2
Makefile bug in nut-2.4.3
I'm just in the process of upgrading from nut-2.4.1 to 2.4.3 on a dual-Xeon box running Solaris 10 amd64 (i686-pc-solaris2.10). I configured as follows: ./configure --prefix=/opt/nut --with-gnu-ld --with-serial --without-usb --with-cgi --with-gd-includes=-I/usr/local/include --with-gd-libs="-L/usr/local/lib -R/usr/local/lib -lgd" --with-user=nut --with-group=nut
2014 Jan 06
2
Reversing the Equation to find value of variable
Dear R forum I have following variables - EAD = 10000 LGD = 0.45 PD = 0.47 M = 3 # Equation 1 R = 0.12*(1-exp(-50*PD))/(1-exp(-50)) + 0.24*(1-(1-exp(-50*PD))/(1-exp(-50))) b = (0.11852 - 0.05478 * log(PD))^2 K = (LGD * pnorm((1 - R)^(-0.5) * qnorm(PD) + (R / (1 - R))^0.5 * qnorm(0.999)) - PD * LGD) * (1 - 1.5 * b)^(-1) * (1 + (M - 2.5) * b) RWA = K * 12.5 * EAD > RWA [1] 22845.07 #
2014 Oct 20
2
config file locations
On Sunday 19 October 2014 22:03:23 Charles Lepple did opine And Gene did reply: > Hi Gene, > > On Oct 18, 2014, at 7:35 PM, Gene Heskett <gheskett at wdtv.com> wrote: > > Greetings; > > > > I found pdf user manual which explains a few things that might help. > > > > However, for a ubuntu flavor, the various .conf etc files seem to be > > in
2006 May 19
1
make error for R-2.3.0
Hello, I'm trying to install R on a linux machine running Red Hat 8. I ran ./configure make and get the following error. I've installed several versions of R (2.2.1 most recently) on this machine and haven't had any problems until now. I wondered if the outdated compiler (gcc version 3.2) was the problem and attempted to install my own, more recent version. I tried gcc versions 4.1.0
2011 Aug 23
4
Correlation discrepancy
Dear R list, I have one very elementary question regrading correlation between two variables. x = c(44,46,46,47,45,43,45,44) y = c(44,43,41,41,46,48,44,43) > cov(x, y) [1] -2.428571 However, if I try to calculate the covariance using the formula as covariance = sum((x-mean(x))*(y-mean(y)))/8       # no of of paired obs. = 8 or     covariance = sum(x*y)/8-(mean(x)*mean(y)) gives
2011 Mar 29
3
Reversing order of vector
Dear R helpers Suppose I have a vector as vect1 = as.character(c("ABC", "XYZ", "LMN", "DEF")) > vect1 [1] "ABC" "XYZ" "LMN" "DEF" I want to reverse the order of this vector as vect2 = c("DEF", "LMN", "XYZ", "ABC") Kindly guide Regards Vincy [[alternative HTML
2023 Jan 31
0
New package - LGDtoolkit
Dear all, my new R package LGDtoolkit is now on CRAN. The goal of this package is to cover the most common steps in Loss Given Default (LGD) rating model development. The main procedures available are those that refer to bivariate and multivariate analysis. In particular two statistical methods for multivariate analysis are currently implemented ? OLS regression and fractional logistic
2023 Jan 31
0
New package - LGDtoolkit
Dear all, my new R package LGDtoolkit is now on CRAN. The goal of this package is to cover the most common steps in Loss Given Default (LGD) rating model development. The main procedures available are those that refer to bivariate and multivariate analysis. In particular two statistical methods for multivariate analysis are currently implemented ? OLS regression and fractional logistic
2010 Oct 27
4
One silly question about "tapply output"
Dear R helpers I have a data which gives Month-wise and Rating-wise Rates. So the input file is something like month           rating           rate January        AAA             9.04 February      AAA             9.07 .......................................... .......................................... Decemeber     AAA            8.97  January           BBB           11.15 February        
2011 Mar 09
3
Rearranging the data
Dear R helpers, xx = data.frame(country = c("USA", "UK", "Canada"), x = c(10, 50, 20), y = c(40, 80, 35), z = c(70, 62, 10)) > xx        country      x     y    z 1      USA        10    40  70 2      UK          50   80   62 3     Canada    20   35   10 I need to arrange this as a new data.frame as follows - country       type     values USA           
2014 Oct 22
0
config file locations
On Tuesday 21 October 2014 22:06:48 Charles Lepple did opine And Gene did reply: > Hi Gene, > > On Oct 21, 2014, at 9:12 PM, Gene Heskett <gheskett at wdtv.com> wrote: > >> configure: error: libgd not found, required for CGI build > >> > >> And gdlib does not appear to be available from the repo's. > > Sorry, I must have missed that message.
2011 Jan 25
4
Subtracting elements of data.frame
Dear R helpers I have a dataframe as df = data.frame(x = c(1, 14, 3, 21, 11), y = c(102, 500, 40, 101, 189)) > df    x   y 1  1 102 2 14 500 3  3  40 4 21 101 5 11 189 # Actually I am having dataframe having multiple columns. I am just giving an example. I need to subtract all the rows of df by the first row of df i.e. I need to subtract each element of 'x' column by 1. Likewise I