similar to: POSIX time anomaly (PR#7317)

Full_Name: Christoph Schmutz, MeteoSchweiz, Switzerland Version: R1.7.1, R1.8.1 OS: windows2000, solaris sunOS 5.8 Submission from: (NULL) (141.249.133.6) I'm not sure if I don't get the clue, but please consider this: > strptime("19930870150","%Y%j%H%M") [1] "1993-03-28 01:50:00" > strptime("19930870250","%Y%j%H%M") [1]

On Sun, 11 Jan 2004, Dirk Eddelbuettel wrote: > On Fri, Jan 09, 2004 at 06:01:27PM +0100, christoph.schmutz@meteoschweiz.ch wrote: > > Full_Name: Christoph Schmutz, MeteoSchweiz, Switzerland > > Version: R1.7.1, R1.8.1 > > OS: windows2000, solaris sunOS 5.8 > > Submission from: (NULL) (141.249.133.6) > > > > > > > > I'm not sure if I

Full_Name: Allen McIntosh Version: 2.0.0 OS: Linux Submission from: (NULL) (67.80.175.118) Observed the bug with the following combinations: (RedHat 7.3, R 1.6.0) (RedHat 7.3, R 1.9.1) (Redhat 9, R2.0.0). In the second plot (.png file) produced by the following sequence: png(file="x%d.png") plot(1:10,1:10,main="ooo",type="n") segments(1:9,1:9,2:10,1:9)

Hi all; I've already send a similar e-mail to the list and Prof. Brian Ripley answered me but my doubts remain unresolved. Thanks for the clarification, but perhaps I wasn't clear enough in posting my questions. I've got a postgres database which I read into R. The first column is Timestamp with timezone, and my data are already in UTC format. An 'printed' extract of R

Hello! I've been trying to get this right for quite a while now and fear there is an easy solution I just don't see. I did not have this problem in Linux, and I searched r-help and Google but did not find a solution, but of course I am grateful for and resources I might not have found our not understood yet. I try to parse a time stamp with time zone. I essentially just want to parse the

Dear R-users, I use unlist of POSIX dates to extract the year, hour etc. With that I can search for files in my database which are in the form 'yyyymmddhh_synops.txt' However, I get stucked during midnight where unlist just gives NA's. The script is given below, the problem accurs at acc.period[16] (midnight). However when I write out the character, unlist works well. But

Hi Gabor and everybody; Thanks Gabor, with the alternative step you've told me the problem is resolved. Comparing the two procedures: Extract from the source 'character' data: > rain$ts[2039:2046] [1] "25/03/2000 22:00:00 UTC" "25/03/2000 23:00:00 UTC" [3] "26/03/2000 00:00:00 UTC" "26/03/2000 01:00:00 UTC" [5] "26/03/2000 02:00:00

R 2.6.1 on a Thinkpad T60 running up-to-date Gentoo: Despite the documentation, which says: 'strftime' is an alias for 'format.POSIXlt', and 'format.POSIXct' first converts to class '"POSIXlt"' by calling 'as.POSIXlt'. Note that only that conversion depends on the time zone. strftime fails on POSIXct objects: > foo <-

In attempting to build R using rpmbuild --rebuild R-2.1.0-0.fdr.2.fc3.src.rpm on a fairly up-to-date RedHat 9 system (that is, with patches installed through May 1 2004), it failed at the make check-all step. The problem was reproducible by going into the tests directory and make test-Segfault The last lines of the saved file no-segfault.Rout.fail are > > ## c.POSIXct : > >

For the r script below >datestr <- "01/01/2004" >as.POSIXct(as.Date(datestr, "%d/%m/%Y")) I get the following output "2003-12-31 18:00:00 Central Standard Time" Why is the date a day before. I guess its something to do with the time, but is there a way to get it to return 2004-01-01 instead? Thanks in advance... -Sandeep [[alternative HTML version

Hi, Is it possible to create a ts() object, whose data is daily based BUT measured only on working days? In other words, suppose I have a data set with 255 observations, measured from 29 June 1959 to 30 June 1960. How would I create such a data? I tried something like: ts(c(...), start(1959, 180)) but I'm not sure what to use for frequency. In other words I don't know how to

I am trying to use POSIX datetime objects rather than chron datetime objects but am having difficulty with POSIX in a time series. My question: Once a POSIXct vector is bound to a time series, is there a function to convert back to POSIXct? The following code demonstrates what I am trying to do. > ts(as.POSIXct(strptime(tmp,"%m/%d/%Y %H:%M:%S")),freq=1440) Time Series: Start =

Hello, I am an advanced user of R. Recently I found out that apparently I do not fully understand vectors and lists fully Take this code snippet: T = c("02.03.2008 12:23", "03.03.2008 05:54") Times = strptime(T, "%d.%m.%Y %H:%M") Times # OK class(Times) # OK is.list(Times) # sort of understand and not understand that length(Times)

I read a few days back on the list where the tzdata rpm was to take care of the new DST rules. I run CentOS 3 servers, and did a 'yum update tzdata' , but received a 2006a update of the rpm. Is this proper? It sure didn't fix anything. Thanks Steve Campbell campbell at cnpapers.com Charleston Newspapers

Hi. I frequently convert date and time data to and from character representations. I'm frustrated with chron, because 'seconds' are required to create a time object (my input data never has seconds). More importantly, I cannot make chron print the format 12/30/2006 (which my output data requires). I really like the format flexibility of strftime() and strptime(), but of course

Hi all, I ran into a segfault while playing with dates. $ R --no-init-file ... > library(lubridate); d=as.POSIXlt(floor_date(Sys.time(),"year")); d$zone=NULL; d$zone=""; d Attaching package: ?lubridate? The following object is masked from ?package:base?: date Warning message: package ?lubridate? was built under R version 3.4.0

On the documentation page for DateTimeClasses, in the Examples section, there are the following two lines: format(.leap.seconds) # the leap seconds in your time zone print(.leap.seconds, tz = "PST8PDT") # and in Seattle's The second line (using print) seems to ignore the tz argument, and prints the dates in my time zone, while: format(.leap.seconds, tz =

Dear Listers, Apologize to pile up on the 'tz' issue in POSIX objects. I have a 'simple' thing on which I must make up my mind but cannot do it from the existing R-help threads. I am currently working on dog telemetry in China, and download time information from GPS collars. I would like to set up the corresponding POSIXxx variables in R to a given time zone. Eg Pekin

Dear R-list users, I need to use strptime because I have to deal with date with hours and minutes. I read the manual for strptime and I also looked at many examples, but when I try to apply it to my code, I always encounter some problems. I try to change the default format, with no success. Why? How can I change the format? 1. init_day <- as.factor("2015-02-24-00-30")

I think the following examples illustrate the crux of the matter (version and OS info are below). The problem has to do with the transition from standard time to daylight savings time. My timezone, US/Pacific, has two parts: standard time (PST) 8 hours behind GMT and daylight savings time (PDT) 7 hours behind GMT. The transition takes place this year on 7 April at 02:00, when 02:00 is