similar to: xtabs or model.frame (PR#5461)

The problem here is Table doesn't seem to have a way to weigh the data. > ToyData Data1 Data2 Data3 Weight 101 Sam Red Banana 1.1 102 Sam Green Banana 2.1 103 Sam Blue Orange 2.1 104 Fred Red Orange 2.1 105 Fred Green Guava 2.1 106 Fred Blue Guava 2.1 107 <NA> Red Pear 50.1 108 <NA> Green Pear 50.1 109 <NA> Blue

Dear listers, I am trying to fit a model using nlsList() using alternately a SSfol() selfstart function or its developped equivalent formulae. This preliminary trial works well mydata<-groupedData(Conc~Tps|Organ,data=mydata) mymod1<-nls(Conc~SSfol(Dose,Tps,lKe,lKa,lCl),data=mydata) as well as a developped form: mymod2<-nls(Conc~Dose * exp(lKe+lKa-lCl) *

Greetings List, I'm having some trouble with the use of the names function in a formula. Below is an example of something that works (i.e first line), and the second line is the same formula which doesn't. I want to be able to reference the column of the dataC table so I can run the variogram iteratively with a loop. > v<-variogram(A1~1,loc=~x+y, dataC) >

Dear list, I may have found a bug in model.frame.default (called by the lm function). The problem arises in my R dev version but not in my R 2.4.0. Here is my config : > version _ platform x86_64-unknown-linux-gnu arch x86_64

I hope you can help me. I am new to "R" and am working through the example of quantile regression analysis in the paper by Roger Koenker (quantile regression in R: a Vignette. I got to page 6 and in trying to execute the following code I received the error below. I have searched on the web and while I have found similar error messages, I have not been able to ascertain the root cause.

Hello! I have a dataset with NA's in some variables (factors), for example: $ P67 : Factor w/ 2 levels "-","+": NA 2 1 NA NA 2 1 1 2 NA ... I need to use 'xtabs' like xtabs(~x$P67) It works well and produces something like this: x$P67 - + 779 1318 but i want to compute NA's too, like this: x$P67 - + NA 779 1318 137 I am trying

I'm trying to learn to use manova(), and don't understand why none of the following work: > data(iris) > fit <- manova(~ Species, data=iris) Error in lm.fit(x, y, offset = offset, singular.ok = singular.ok, ...) : incompatible dimensions > fit <- manova(iris[,1:4] ~ Species, data=iris) Error in model.frame(formula, rownames, variables, varnames, extras,

Hi all, I cannot get xtabs to count NA's like I expect. Below is a sample session, and note that the last two calls to xtabs() yield exactly the same thing. I am running R-2.5.0 -- if there was a bug in xtabs that got fixed, I would love to know about it. If there is a bug tracker somewhere, I can file it too. It isn't my fault that the server is so ridiculously outdated, but I would

>>>>> Milan Bouchet-Valat <nalimilan at club.fr> >>>>> on Thu, 19 Jan 2017 13:58:31 +0100 writes: > Hi all, > I know this issue has been discussed a few times in the past already, > but Martin Maechler suggested in a bug report [1] that I raise it here. > > Basically, there is no (easy) way of printing NAs for all variables > when calling

Dear list, I am trying to make a contingency table with xtabs but I am getting a 0 where I expect a 'NA'. Here is a simple example: options(stringsAsFactors = FALSE) rn <- LETTERS[1:4] df1 <- data.frame(r07 = rep(rn, each=4), r08 = rep(rn, 4), value = 1:16) xtabs(value ~ r07 + r08, df1) # Delete the combination [A, C] df1 <- df1[-3,] # Set 'value'

Hi I haven't found a way to produce a tabulation from factor data with NA values using xtabs. Please find a minimal example below, it's also on R-pubs [1]. Tested with R 3.1.2 and R-devel r67720. It doesn't seem to be documented explicitly that it's not supported. From reading the code [2] it looks like the relevant call to table() doesn't set the "useNA"

I have an application that would generate a cross-tabulation in array format in R. In particular, my application would give me a result similar to that of : array(5,c(2,2,2,2,2)) The above could be seen as a cross-tabulation of 5 variables with 2 levels each (could be 0 and 1). In this case, the data were such that each cell has exactly 5 observations. I Now, I want the output to look like the

(Sorry for obvious mistakes, as I am quite a newby with no Statistics background). My question is going to be what is the gain of logistic regression over odds ratios when none of the input variables is continuous. My experiment: Outcome: ordinal scale, ``quality'' (QUA=1,2,3) Predictors: ``segment'' (SEG) and ``stress'' (STR). SEG is nominal scale with 24

Hoping someone can help me with xtabs and ftable. I'm trying to get a pair of ftables (possibly more) next to each other. For example: > dunhill_lights_xtab<-ftable(xtabs(grossedupobs ~ gender+age_group + dunhill_lights, data = ciggs)) > dunhill_lights_xtab dunhill_lights No Yes gender age_group Female

Dear list members, This is probably a naive question (from a new user), but I'm having problems getting column names to be recognised in loop that is supposed to apply a set of calculations in turn to each column of a dataframe. The dataframe has 33 columns of output from a simulation. The columns each have a text name and I want to apply the same set of calculations to each column in turn.

Dear all I was willing to use argument 'exclude' in function xtabs to remove some levels of factors (xtabs help page says '"exclude: a vector of values to be excluded when forming the set of levels of the classifying factors"). I tried: > mydata <- data.frame( treatment = c("B", "A", "C", "C", "B",

Hi list, is it possible convert the xtabs result xtabs(breaks~tension+wool,data=warpbreaks) wool tension A B L 401 254 M 216 259 H 221 169 to a simple matrix or data frame? A B L 401 254 M 216 259 H 221 169 Thanks a lot! Gianandrea -- View this message in context: http://www.nabble.com/From-xtabs-to-matrix-tp24304588p24304588.html

Hey alltogether, refacturing a package (before it will be released), I ran across the following problem. I have two directories with different text files, I want to read the first and construct a document-term matrix from it (every term=word in a row, every file in a column, occurrence frequencies form the values). The second directory contains different files. It needs to be read in to also

Full_Name: Martin Lenze Version: 1.3.0 22.06.2001 OS: win32,x86 Submission from: (NULL) (194.221.251.1) As a newbie I'm not sure, whether this is a bug, but I don't know how to get around this behaviour: > x <- list("A"=rep(c(1:5),30), + "B"=c(rep(letters[1:3],30),rep(letters[2:4],20))) > y <- as.data.frame(x) > xtabs(~A+B,y) B A a b c d 1 6 10

Hi, I'm using a loop to evaluate several models by taking adjacent variables from my dataframe. When i try to get predictions for new values, i get an error message about a missing variable in my new dataframe. Below is an example adapted from ?gam in mgcv package library(mgcv) set.seed(0) n<-400 sig<-2 x0 <- runif(n, 0, 1) x1 <- runif(n, 0, 1) x2 <- runif(n, 0, 1) x3 <-