similar to: Anomaly with unique and match

R-help - I have this set of aggregated tables (sample data below via dput()). And I would like to have delayValue as the column variables with the "temp" (temp1, temp2, temp3) values as the row variables. However I would like to have the temp variables *aggregated into single rows* so that I have the frequency ("Freq" | counts) of each time each "delayValue" occurs

I am using R 2.1.1 in an windows XP environment. I have 2 dataframes, temp1 and temp2. Each dataframe has 20 variables (“cocolumns") and 525 observations (“rows”). All variables are numeric. I want to create a new dataframe that also has 20 columns and 525 rows. The values in this dataframe should be the sum of the 2 other dataframe. (i.e. temp1$column

i have a time Series of IBM closing px from 1/1/2000 to today I want to graph the time serie by dividing the graph by year and month all the monthly graphs with the same year will go to one page. so from 1/1/2000 to 11/19/2010. i will have 11 pages, and each page will have 12 graphs (jan to dec) except for 2010. I am able to do it in R, but when i use sweave, I can only print the last page.

temp = "~aparch(" temp1 = paste(temp,1, sep = "") temp2 = paste(temp1,1, sep = ",") temp3 = paste(temp2, ")",sep = "") temp 3 is a character but I want to convert to formula object. How do I do this? -- View this message in context: http://r.789695.n4.nabble.com/how-to-convert-string-to-object-tp2999281p2999281.html Sent from the R help mailing

Hi Irucka, I tried it and was able to plot it without any errors.? Here, your code indicates you need two lines. temper[[i]][1] ?temper[[1]][1] # which is the column 1. ? Month 1???? 1 2???? 2 3???? 3 ?temper[[1]][2] #? Data1 #1?? 1.5 #2? 12.3 #3? 11.4 Suppose I use names(temper) instead of seq_along(temper) pdf("irucka.pdf") ?lapply(names(temper),function(i)

Hi all, I have a C code in Linux, it has 7 pointers and compile e run OK, but when I run in R happens problems with calloc function, it returns NULL. ############################################### > int *temp1,*temp2,*temp3,*temp4; temp1 = (int *)calloc(col,sizeof(int)); if(temp1 == NULL){ printf("\n\n No Memory1!"); exit(1); } temp2 = (int *)calloc(col,sizeof(int));

Hi, temp3<- read.table(text=" ID CTIME WEIGHT HM001 1223 24.0 HM001 1224 25.2 HM001 1225 23.1 HM001 1226 NA HM001 1227 32.1 HM001 1228 32.4 HM001 1229 1323.2 HM001 1230 27.4 HM001 1231 22.4236 #changed here to test the previous solution ",sep="",header=TRUE,stringsAsFactors=FALSE) ?tempnew<- na.omit(temp3) ?grep("\\d{4}",temp3$WEIGHT) #[1] 7 9 #not correct

On Mon, September 14, 2015 21:28, Always Learning wrote: > > On Mon, 2015-09-14 at 14:51 -0400, James B. Byrne wrote: > >> The Logwatch imapd service script distributed with CentOS-6 does not >> generate anything when I run logwatch --service all on a cyrus-imapd >> host. Is this expected behaviour? Is there a separate script for >> cyrus-imapd or are their

HI Irucka, Please check this: temp<- structure(list(`:Bostoncitydata` = structure(list(Month = c(1L, 2L, 3L, NA), Data1 = c(1.5, 12.3, 11.4, NA), Data2 = c(9.1342, 12.31, 3.5, NA)), .Names = c("Month", "Data1", "Data2"), class = "data.frame", row.names = c(NA, -4L)), `:Chicagocitydata` = structure(list(Month = c(1L, 2L, 3L, 4L, 5L, NA), Data1 = c(1.52,

Hi, I am writing a function to plot a pdf of a distribution, GNL.pdf.fn = function(x,mu,sigma,alpha,beta,rho) { y = x-rho*mu cf.fn = function(s){ cplex = complex(1,0,1) temp1 = alpha*beta*exp(-sigma*s^2/2) temp2 = (alpha-cplex*s)*(beta+cplex*s) out = (temp1/temp2)^rho out } temp.fn = function(s){ (Mod(cf.fn(s)))*cos(Arg(cf.fn(s))-s*y) } int.fn =

Hello, I'm new to R with a (probably elementary) question. Suppose I have a dataset called /A/ with /n/ locations, and each location contains within it 3 time series of different variables (all of 100 years length); each time series is of a weather variable (for each location there is a temperature, precipitation, and pressure). For instance, location 1 has a temperature1 time series, a

Hi, I have following kind of model : Y = X1 * a1 + X2 * a2 + error Here sampled data for Y, X1, X2 are like that : Y <- replicate(10, matrix(rnorm(2),2), simplify = F) X1 <- replicate(10, matrix(rnorm(4),2), simplify = F) X2 <- replicate(10, matrix(rnorm(4),2), simplify = F) My goal is to calculate LS estimates of vectors "a1" and "a2". Can anyone please guide me

Hi everyone I am new to R and have a question about missing values. I am trying to do a cluster analysis of monthly temperatures and my data are 14 columns with spatial coordinates (lat,lon) and 12 monthly values: /lat - lon - temp1 - //temp2 - temp3 - .... - //temp12/ If I omit missing values (my missing values are 99.00) with /mydata <- na.omit(mydata)/ every row with a

Dear All, I would be grateful if you can help me. My problem is the following: I have a data set like: ID time X1 X2 1 1 x111 x211 1 2 x112 x212 2 1 x121 x221 2 2 x122 x222 2 3 x123 x223 where X1 and X2 are 2 covariates and "time" is the time of observation and ID indicates the

this is a bad question but I can't figure it out and i've tried. if i sort the 2 column matrix , temp1, by the first column, then things work as expected. But, if I sort the 1 column matrix, temp2, then it gets turned coerced to a vector. I realize that I need to use drop=FALSE but i've put it in a few different places with no success. Thanks. temp1 <-

i'm sorry. i had an error in my previous code because i left out a letter in the rownames. while fixing that, i also found a solution. so i'm sorry for the confusion. below is my fix. temp2 <- matrix(rnorm(10),nc=1,nrow=10) rownames(temp2) <-

I have around 200 data frames I want to rbind in a vectorized way. The object names are: m302 m303 ... m500 So I tried: mlist <- paste("m",302:500,sep="") dat <- do.call("rbind", get(list(mlist))) and I get "Error in get(x, envir, mode, inherits) : invalid first argument" I know "rbind" is valid because dat <- rbind(m302, m303,

Okay, someone explain this behaviour to me: Browse[1]> replace(rep(0, 4000), temp1[12] , temp2[12])[3925] [1] 0.4462404 Browse[1]> temp1[12] [1] 3926 Browse[1]> temp2[12] [1] 0.4462404 Browse[1]> replace(rep(0, 4000), 3926 , temp2[12])[3925] [1] 0 For some reason, R seems to shift indices along when doing this replacement. Has anyone encountered this bug before? It seems to crop up

Dear all, I'm trying to gsub() "%" with "\%" with no obvious success. > temp1 <- c("mean", "sd", "0%", "25%", "50%", "75%", "100%") > temp1 [1] "mean" "sd" "0%" "25%" "50%" "75%" "100%" > gsub("%",

Hi, I am using eigen to get an eigen decomposition of a square, symmetric matrix. For some reason, I am getting a column in my eigen vectors (the 52nd column out of 601) that is a column of all NAs. I am using the option, symmetric=T for eigen. I just discovered that I do not get this behavior when I use the option EISPACK=T. With EISPACK=T, the 52nd eigenvector is (up to rounding error) a