similar to: Strange R object

The following cut command takes nearly 10 seconds on my machine even though the length of input vector is only 6. I am running on Windows Vista with C2D BLAS using R 2.11.1. Using the default BLAS and either R 2.10.1 or "R version 2.12.0 Under development (unstable) (2010-05-31 r52164)" also gives me results in the 9-11 second range. I would have expected it to take much less time.

Hi all and thanks for your time in advance, I can't figure out why summary.lmrob complains when lmrob is used on a zooreg object. If the zooreg object is converted to vector before calling lmrob, no problems appear. Let me clarify this with an example: >library(robustbase) >library(zoo) >dad<-c(801.4625,527.2062,545.2250,608.2313,633.8875,575.9500,797.0500,706.4188,

Hello, Can anyone explain the following behaviour? To me it seems a bug, but maybe it is intentional. It seems that a diff on a zooreg class that is not _strictly_ regular only considers those entries that are 'deltat' apart. In the following, diff on the zooreg class only returns values where the index was one second apart. The example replicates by dev code, but I've also tested

Dear all, please consider my following workbook: library(zoo) lis1 <- vector('list', length = 2) lis2 <- vector('list', length = 2) lis1[[1]] <- zooreg(rnorm(20), start = as.Date("2010-01-01"), frequency = 1) lis1[[2]] <- zooreg(rnorm(20), start = as.yearmon("2010-01-01"), frequency = 12) lis2[[1]] <- matrix(1:40, 20) lis2[[2]] <-

I create a zooreg object that runs from Jan-1-2002 0:00 to Jun-1-2005 0:00... regts.start = ISOdatetime(2002, 1, 1, hour=0, min=0, sec=0, tz="") regts.end = ISOdatetime(2005, 6, 1, hour=0, min=0, sec=0, tz="") regts.zoo <- zooreg( NA, regts.start, regts.end, deltat=3600 ) Upon inspection: > regts.zoo[1:3] 2002-01-01 00:00:00 2002-01-01 01:00:00 2002-01-01 02:00:00

Dear R community, I have the following two zoo objects: MONTHLY CPI > plot(z) > par("usr") [1] 1977.76333 2011.15333 70.39856 227.03744 > z=zooreg(cpius$Value,as.yearmon("1979-11"),frequency=12) > str(z) ?zooreg? series from Nov 1979 to Oct 2010 Data: num [1:372] 76.2 77 77.8 78.5 79.5 80.3 81.1 82 82 82.6 ... Index: Class 'yearmon' num [1:372]

No he podido crear una matriz con dos columnas una de fechas y la otra columna con números de casos de una enfermedad x library(zoo) zooreg(1:300, start = as.Date("2012-03-01")) cbind(zooreg(1:300, start = as.Date("2012-03-01")) , c(1:300)) #?como incluir un vector o una ts? -- Este mensaje le ha llegado mediante el servicio de correo electronico que

Hi, I'm trying to plot the forecasts I generated using the Plot.Fore function of the BootPR package. But I got an error from zoo: My data: Time Series: Start = 1 End = 18 Frequency = 1 [1] 38731 38628 39117 92809 71984 31226 58613 72360 107956 92066 [11] 95208 99098 95848 120383 110717 105680 98469 101916 Script: y1<-ts(y1);

Hi, I'm trying to make a ts object that has both NA values and a frequency other than 1 (so I can use stl). I've tried all permutations I can think of, but cannot get the desired (expected?) results. The values live in x and the corresponding semi-regular time stamps are in t: > library('zoo') > z = zoo(x, order.by=t, frequency=24) > zzr = as.zooreg(z, start=0) > zr

Dear R users, I am currently working in subsetting a zooreg() object using either window or subset. I have a solution but it may be a bit cumbersome when I start working with actual data. Your inputs would be greatly appreciated. Example: I have a zooreg() object that starts in 1997 and ends in 2001. This object contains daily data for the 4 years

Hi,   I observed that if I use window() function available with the 'zoo' package to extract a portion of my times series and if that time series data is stored in some 'zoo' object with only 1 column, then the resulting zoo object is becoming vector.   Here is my observation:   > library(zoo) > Dat <- matrix(1:3, nc = 1) > Dat      [,1] [1,]    1 [2,]    2 [3,]    3

Estimados ?como se puede llevar el archivo que adjunto a vector? necesito hacer lo siguiente con el archivo a library(zoo) x <- c (1,3,1,1,1,1,2,1,1,2,1,1,2,1,1,1,2,1,2,2,1,1,1,3,1,1,2,2,2,2,1,1,1,2,1,1,1,1,1,2,2,5,1,1,1,1,2,1,1,1,2,4,1,2,1,3,1,1,1,1,3,1,2,1,1,3,1,3,3,1,2,1,2,2,2,3,1,2,1,1,1,1,2,1,1,1,1,1,1) names(x) <- format(index(zooreg(1:89, start =as.Date("2015-01-01"))),

Hi, I have a financial (zoo) time series with prices and volumes (although I can get the coredata as a matrix). Due to the data-source some indices have multiple observations. I want to aggregate these according to a weighted average. 11:00:01 34 1000 11:00:01 35 500 11:00:01 35 1000 11:00:02 34 500 11:00:02 35 500 should become 11:00:01 34.6 2500 11:00:02 34.5 1000 I currently do this

R-listers, I am using xts with a yearmon index, but am getting some inconsistent results with the date index when i drop observations (for example by using na.omit). The issue is illustrated in the example below. If I start with a monthly zooreg series starting in 2009, yearmon converts this to "Dec-2008". Not such a worry for my example, but strange. Having converted to xts, i drop

Dear all, Please forgive me if there is a duplicate post; my previous mail perhaps didnt reach the list....... Let say I have following time series library(zoo) > dat1 <- zooreg(rnorm(10), start=as.Date("2010-01-01"), frequency=1) > dat1[c(3, 7,8)] = NA > dat1 2010-01-01 2010-01-02 2010-01-03 2010-01-04 2010-01-05 2010-01-06 2010-01-07 2010-01-08 2010-01-09

Hi, Can you tell me what is the meaning for "tail, 1" in "aggregate"? I also want to get some similar graph, but the data is not time series data. Suppose here is my data one, I want a graph with x-axis is just the index(1:9). The graph plot all the variable A, B,C,D. So there should be 4 lines for each graph. For the A line, at each time point, the letter A should be on

Please see that correlogram for a arbitrary time series : acf(zooreg(rnorm(39), start=as.yearmon("2008-01-01"), frequency=12)) What is the meaning of lag 0.2, 0.4, ........ in the plot? Those should not be integers? Or I am missing something? Thanks -- View this message in context: http://n4.nabble.com/Meaning-of-lag-0-2-0-4-tp1765093p1765093.html Sent from the R help mailing list

Hi R Users! I would like to create an high frequency series but I am experiencing some difficulties. My series should start at 09.30 a.m. each day and end at 16.00 for, let's say, 2 years. I don't care on how many observations are for each day. It's ok also one observation each minute. In this case, I would have 390 observations each day. I have tried the following: start <-

Hi, I have a zoo object with monthly frequency : library(zoo) dat <- zooreg(rnorm(50), as.yearmon("2000-01-01"), frequency=12) Now I want to make a zoo object with daily frequency from "dat" wherein value for a each day for a particular month will be value of "dat" at that particular month. Is there any easy way to do that? Thanks, -- View this message in

Dear all, I have an error message, when I try to convert a zoo object (called test) to ts (on R 2.4.0, Package zoo version 1.2-1, Windows XP) > test 1994-05-10 1994-06-09 1994-07-09 0.0024943889 0.0024881824 0.0006955831 > str(test) atomic [1:3] 0.002494 0.002488 0.000696 - attr(*, "index")=Class 'Date' num [1:3] 8895 8925 8955 > is.regular(test) [1] TRUE