similar to: Possible bug in "unsplit" (PR#14084)

Folks, I'm running into something which looks like a bug in linearscan allocator. Of course I can't be 100% sure it's not some unobvious mistake on my part, so I'd like to hear your opinion. First, I attach two files -- LLVM asm and the asm for my target. The problem with assembler is: on line 171 it uses register gr2, which is copied from gr6 above, on line 161. The only

On Tue, 22 Jun 2004, Vladimir Prus wrote: > First, I attach two files -- LLVM asm and the asm for my target. The problem > with assembler is: on line 171 it uses register gr2, which is copied from gr6 > above, on line 161. The only predecessor of this basic block is jump on line > 90. The problem is that gr6 is not initialized in the interval from the > function entry till the

Chris Lattner wrote: > On Tue, 22 Jun 2004, Vladimir Prus wrote: > > First, I attach two files -- LLVM asm and the asm for my target. The > > problem with assembler is: on line 171 it uses register gr2, which is > > copied from gr6 above, on line 161. The only predecessor of this basic > > block is jump on line 90. The problem is that gr6 is not initialized in > >

Dear R-users, I would like to maximize the function g above which depends on 4 parameters (2 vectors, 1 real number, and 1 matrix) using optim() and BFGS method. Here is my code: # fonction to maximize g=function(x) { x1 = x[1:ncol(X)] x2 = x[(ncol(X)+1)] x3 = matrix(x[(ncol(X)+2):(ncol(X)+1+ncol(X)*ncol(Y))],nrow=ncol(X),ncol=ncol(Y)) x4 = x[(ncol(X)+1+ncol(X)*ncol(Y)+1):length(x)]

Hi, looking at the fresh CVS state I see: class Register<string n> : RegisterBase<n> { list<RegisterBase> Aliases = []; } while previously the Register class did not require any parameters. The change log is just: * Target.td: Revamp the Register class, and allow the use of the RegisterGroup class to specify aliases directly in register definitions. and I

When I create a lattice/Trellis type graph, I typically write a function that returns the graph, as in do.graph <- function(x, y, ...) { require(lattice) return(xyplot(y~x, ...)) } My question today is this: If I want two graphs on one page, one way of achieving it is to print the objects into defined areas, as in gr1 <- xyplot(rnorm(111) ~ runif(111)) gr2 <-

On Tue, 16 Nov 2004, Vladimir Prus wrote: > and I could not find any discussions in the archives. > > Why the change was necessary? Writing: > > def gr0 : Register<"gr0">; > def gr1 : Register<"gr1">; > def gr2 : Register<"gr2">; > def gr3 : Register<"gr3">; > def gr4 :

Hello, As I am quitte an ignorant user of R, excuse me for any wrongfull usage of all the terms. My question relates to the statistics behind the survdiff function in the package survival. My textbook knowledge of the logrank test tells me that if I want to compare two survival curves, I have to take the sum of the factors: (O-E)^2/E of both groups, which will give me the Chisq. If I calculate

Dear expeRts, Why does na.blank=TRUE not replace the NA's in the following LaTeX table? x <- matrix(1:72, ncol=4, nrow=8) colnames(x) <- c("gr1.sgr1", "gr1.sgr2", "gr2.sgr1", "gr2.sgr2") rn <- apply(expand.grid(beta=c(0.25, 0.75), n=c(100, 500), d=c(10, 100))[, 3:1], 2, rmNames) x <- cbind(rn, x) # append columns containing the row labels

http://bugzilla.mindrot.org/show_bug.cgi?id=938 Summary: "AllowGroups" option and secondary user's groups limit Product: Portable OpenSSH Version: 3.9p1 Platform: ix86 OS/Version: Linux Status: NEW Severity: major Priority: P2 Component: PAM support AssignedTo: openssh-bugs at

Laurent: As I don't use dplyr, this won't help you, but I hope you and others may find it entertaining anyway. If I understand you correctly (and ignore this if I have not), there are a ton of ways to do this in base R, including using switch() along the lines you noted in your post. However, when the functions get sufficiently complicated or numerous, it may be useful to store them in a

Dear all, I wish to create a POSIXct variable from date and time variables using the ymd_hm function in package lubridate. In some cases data for time is missing, which causes a problem for ymd_hm. I wish to find a smooth way to handle this. # Some example data: x <- data.frame(date = c("2011-09-22", "2011-07-28"), time = c("15:00", NA)) x # paste date and

> On Nov 21, 2020, at 10:55 AM, Mario Annau <mario.annau at gmail.com> wrote: > > Hello, > > using the `unsplit()` function with tibbles currently leads to the > following error: > >> mtcars_tb <- as_tibble(mtcars, rownames = NULL) >> s <- split(mtcars_tb, mtcars_tb$gear) >> unsplit(s, mtcars_tb$gear) > Error: Must subset rows with a valid

(only of interest -- maybe! -- to those who followed this thread of a couple of weeks ago) Just for the heckuva it, I compared the timing of Deepayan's unsplit(x,f) solution to my as.vector(do.call(rbind, x)) approach to the query for a list of 3 vectors each of length 1000 (the original toy example was for a list of 3 vectors of length 5). Unsurprisingly, I think, because the unsplit()

Cool - thank you Peter! @Marc: This is really not a tidyverse vs base-R debate and I personally think that they should both work together for most parts. The common environment is still R. But just to give you the full picture I also filed a bug for tibbles (https://github.com/tidyverse/tibble/issues/829). With these two fixes I think that split/unsplit would work for tibbles and users (like me)

Dear RHelp-list, ?? Using dplyr and the group_by approach on a dataframe, I want to be able to apply a specific action according to the group name. The code bellow works, but I am not able to write it in a more esthetic way using dplyr. Can somebody help me to find a better solution ? Thank you Best regards Laurent df_test <- data.frame( x1=1:9, x2=1:9,

Hello everyone, I use the split function splitting with the f function on a 3 columns and more than 100 000 rows data frame. Once it's split I have a list of data frames still with 3 columns and n rows. I manipulate those list elements and get a list of data frames still with 3 columns but less rows. So when I unsplit it, I get an error as I use the same factor function I used to split ( f in

Hedderik van Rijn <hedderik@cmu.edu> writes: > If the second argument to unsplit is not a simple vector (but a "list > containing multiple lists"), the function seems to have some problems. > > Given a slight modification of the examples in help(split): > > > xg <- split(x,list(g1=g,g2=g)) > > unsplit(xg,list(g1=g,g2=g)) > [1] -0.7877109

R-devel, Below is a simple example calling split and unsplit on a numeric vector of length 2 where 'f' is c(1,NA). > unsplit(split(c(1,2), c(1,NA)), c(1,NA)) [1] 1 0 I noticed that the call to vector in unsplit gives us 0 as the 2nd element of the result. Is this the intended result, as opposed to NA? Thanks for your help, Jeff -- Jeff Enos Kane Capital Management jeff at

Perhaps this is the intended behavior, but I discovered that unsplit throws an error when it tries to set rownames of a variable that has no dimension. This occurs when unsplit is passed a list of data.frames that have only a single column. An example: df <- data.frame(letters[seq(25)]) fac <- rep(seq(5), 5) unsplit(split(df, fac), fac) For reference, I'm using R version 2.9.0