similar to: In the documentation of 'Ops.Date', please remove mention about "difftime", like in the documentation of 'DateTimeClasses' (PR#14072)

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Full_Name: Suharto Anggono Version: 2.8.1 OS: Windows Submission from: (NULL) (125.161.134.206) About PR#14067, now I understand why (Date + difftime) does not use '+.Date'. But, before I understand, it was surprising. The surprise is also reflected in the post "Problem with +(POSIXt, difftime) dispatching -- WAS: How to create sequence of constant time interval" in R-help

Can anyone please shed any light on why R DateTimeClasses give weird times for when daylight saving time information changes, and which aren't consistent with the OS? Example: Expected result: in New Zealand DST stopped (NZDT -> NZST) at 03:00 NZDT on 2010-04-04, as confirmed by the OS time zone info (OS X 10.8.2): zdump -v /etc/localtime /etc/localtime Sat Apr 3 13:59:59 2010 UTC

Hello, ?DateTimeClasses states that "one can add or subtract a number of seconds or a 'difftime' object from a date-time object, but not add two date-time objects." So, is the below expected behavior? > x <- Sys.time() > x [1] "2007-02-21 16:19:56 CST" > x + as.difftime("1","%H") [1] "2007-02-21 16:19:57 CST" Warning

Dear all, according to the Help-page of DateTimeClasses {base} I should be able to do time - z with time date-time objects z a numeric vector (in seconds) or an object of class "difftime". However, on R version 2.6.0 (Windows XP) I get > Sys.time() - as.difftime(c("0:3:20", "11:23:15")) Time differences in mins [1] 1191837998 1191837318

Hi, I am trying to take difference of two time objects. I want to fix the result's unit to minutes. How can I do that? Here is an example: > difftime(x, y) Time difference of 2.030720 hours > difftime(x, z) Time difference of 30.34672 mins where x = '2007-03-05 08:32:58' y = '2007-03-05 06:31:07' and z = '2007-03-05 08:02:37' How can I get answer

On Thu, Jun 10, 2010 at 3:39 PM, Gustaf Rydevik <gustaf.rydevik at gmail.com> wrote: > Hi all, > > The recent change in 2.11 that made as.numeric() return false on > difftime-objects broke some of my code that calculated age classes of > individuals using cut(). While this was no big thing to fix for me, it > might be wise > to provide a cut.difftime method to ?stop

On Thu, Jun 10, 2010 at 3:39 PM, Gustaf Rydevik <gustaf.rydevik at gmail.com> wrote: > Hi all, > > The recent change in 2.11 that made as.numeric() return false on > difftime-objects broke some of my code that calculated age classes of > individuals using cut(). While this was no big thing to fix for me, it > might be wise > to provide a cut.difftime method to ?stop

Full_Name: Suharto Anggono Version: 2.8.1 OS: Windows Submission from: (NULL) (125.165.81.48) There is already PR#13369. But, the problem is not just the warning. C:\Program Files\R\R-2.8.1\bin>R --vanilla R version 2.8.1 (2008-12-22) Copyright (C) 2008 The R Foundation for Statistical Computing ISBN 3-900051-07-0 R is free software and comes with ABSOLUTELY NO WARRANTY. You are welcome

I would like to know how many years (including partial years) are between two dates. So difftime("20/11/1962", "20/5/1964", units="years") would be about 1.5 But units of years are not available. cheers Worik [[alternative HTML version deleted]]

Anybody have an idea why I would get a non-integer value for the number of days here? > difftime('2004-08-05','2001-01-03',units='days') Time difference of 1309.958 days Would you just round off? Best, Jon

Colleagues, I just encountered some unexpected behavior of difftime in relationship to the change from daylight savings to standard time. My understanding is that DST and ST take effect at 2AM. However, the code below suggests that R (version 2.8.0 in OS X) implements the change at 2:16AM: Expected: > > difftime("2008-11-02 02:01:00", "2008-11-02 00:59:00")

I received a warning about incompatible methods that I don't understand. The workaround in this example is simple. What is the reason that these methods are seen as incompatible? Is there some dangerous consequence of my as.numeric() workaround? Can a fix to the code base, perhaps similar to my workaround, make this warning no longer necessary? I am using R 2.7.0 on Windows. version.string R

Full_Name: Barry Rowlingson Version: 1.6.0 OS: RH8 i386 Submission from: (NULL) (148.88.136.205) Strange things happen if I premultiply a difftime() object with a number. Example: > d1 <- difftime(Sys.time(),Sys.time()) > d2 <- 1 * difftime(Sys.time(),Sys.time()) > d3 <- difftime(Sys.time(),Sys.time()) * 1 > d1 Time difference of 0 secs - thats fine > d2 [1] 0

This looks unintentional: > d <- as.Date("2004-09-07") > dd <- as.Date("2004-10-04") > data.frame(d,dd,dd-d) Error in as.data.frame.default(x[[i]], optional = TRUE) : can't coerce difftime into a data.frame > F <- data.frame(d,dd) > F$foo <- dd-d > cbind(F,dd-d) Error in as.data.frame.default(x[[i]], optional = TRUE) :

It seems that there are several folks Out There with an itch to scratch with respect to difftimes. http://article.gmane.org/gmane.comp.lang.r.devel/19223/match=difftime http://article.gmane.org/gmane.comp.lang.r.devel/18441/match=difftime http://article.gmane.org/gmane.comp.lang.r.devel/10882/match=difftime http://article.gmane.org/gmane.comp.lang.r.devel/11675/match=difftime and I might be

Full_Name: Suharto Anggono Version: 2.8.1 OS: Windows Submission from: (NULL) (125.165.84.118) PR#14076 inspired me to write this. > t1 <- as.POSIXct("1970-01-01 00:00:00", tz="GMT") > t2 <- as.POSIXlt("1970-01-01 00:00:00", tz="GMT") > t1 - t2 Time difference of 7 hours Above, t1 and t2 represent the same time in the same specified

I am trying to write S4 methods with "difftime" in the signature but am being "informed" (? not a warning or error) that "difftime" is not a class. Nevertheless, dispatch takes place. Should I simply ignore that "information"? Here is a toy example: > setClass("foo", contains = "Date") > setMethod("+", c("foo",

Hello! I notice I can convert strings containing hour, minute or second specifications to a 'difftime': > as.difftime("12 h", "%H") Time difference of 12 hours > as.difftime("12 m", "%M") Time difference of 12 mins > as.difftime("12 s", "%S") Time difference of 12 secs But I can't do so with a week specification,

Hi, I have a variable "m" that contains the number of minutes that something lasted, e.g. m <- 139 I'd like to convert it to a difftime, so I can add it to the POSIXct start time. But as.difftime seems to want a character string, with at most two characters for the minutes. All other conversion functions seem to take strings as well. What am I missing? Thanks, Martin