similar to: Named backreference in gsub()?

I'm having a Thursday morning mental block, any suggestions on the following would be most appreciated... I have (as an example) surgery = c("d48", "d67", "dnc37", "a75", "d10", "a78", "d31", "d55", "d1") before each number part the possibilities are c("a", "d",

Hi I have a problem with substitutions involving named backreferences. I have a vector American.dates: > American.dates [1] "5/15/1976" "2.15.1970" "1.9.2006" which I want to change into British.dates: > British.dates [1] "15/5/1976" "15/2/1970" "9/1/2006" I know I can do it like this:

Hello; I am a R newbie and would like to know correct and efficient method for doing string replacement. I have a large data set, where I want to replace character "M", "b", and "K" (currency in Million, Billion and K) to millions. That is 209.7B with (209.7 * 10e6) and 100.00K with (100.00 *1/100) and etc.. d <- c("120.0M", "11.01m",

> grep("f[0-9]+=", "f1=5,f22=3,", value = T) [1] "f1=5,f22=3," How do I make the line output c("f1", "f22") instead? (Actually, c(1,22) would be even better). Thank you. -- View this message in context: http://r.789695.n4.nabble.com/Quick-GREP-challenge-tp2339486p2339486.html Sent from the R help mailing list archive at Nabble.com.

I have a matching problem that I cant solve. mystring = "xxx{XX}yy{YYY}zzz{Z}" where "x","X","y","Y","z","Z" basiclly can be anything, letters, digits etc. I'm only interested in the content within each "{}". I am close but not really there yet. library(gsubfn) strapply(mystring,"\\{[^\\}]+",, perl=F)

Hi all, I swear this used to work: library(gsubfn) strapply("S(AC,P)TVDK(8)EELVQK(8), ".[(].{1,2}[)]|.")[[1]] But somewhere along the update path it stopped ... now giving me this Error in base::gsub(pattern, rs, x, ...) : invalid backreference 2 in regular expression Can't figure it out. What am I doing wrong? Thanks for any hints, Joh

Each day the daily balance in the following link http://www. snamretegas.it/italiano/business/gas/bilancio/pdf/bilancio.pdf is updated. I would like to set up an R procedure to be run daily in a server able to read the figures in a couple of lines only ("Industriale" and "Termoelettrico", towards the end of the balance) and put the data in a table. Is that possible? If

Dear R guru: If I got a variable aaa<- "up.6.11(16)" how can I extract 16 out of the bracket? I could use substr, e.g. substr(aaa, start=1, stop=2) [1] "up" But it needs start and stop, what if my start or stop is not fixed, I just want the number inside the bracket, how can I achieve this? Many thanks yan

Hi, this should be an easy one, but I can't figure it out. I have a vector of tests, with their units between brackets (if they have units). eg tests <- c("pH", "Assay (%)", "Impurity A(%)", "content (mg/ml)") Now I would like to hava a function where I use a test as input, and which returns the units like: f <- function (x) sub("\\)",

Hi Folks, I'm trying to extract just the backreferences from a regex. > temp = "abcd1234abcd1234" > regmatches(temp, gregexpr("(?:abcd)(1234)", temp)) [[1]] [1] "abcd1234" "abcd1234" What I would like is: [1] "1234" "1234" Note: I know I can just match 1234 here, but the actual example is complicated enough that I have to

Hi all, Does anyone have a version of strsplit that keeps the string that is split by. e.g. from x <- "A: 123 B: 456 C: 678" I'd like to get c("A:", "123 ", "B: ", "456 ", "C: ", 678) but strsplit(x, "[A-Z]+:") gives me c("", " 123 ", " 456 ", " 678") Any ideas? Thanks,

Greetings, I have a vector of values that are a word followed by a number, e.g., x = c("Apple12","HP42","Dell91"). The goal is to split this vector into two vectors such that the first vector contains just the words and the second contains just the numbers. I cannot use strsplit (or at least I do not know how) as there is no obvious separator. I can use sub to

Hello, assume I have an "unstructured" text line from a connection. Unfortunately, it is in string format: R> x [1] "\talpha0\t-0.638\t0.4043\t0.4043\t-2.215\t-0.5765\t-0.137\t501\t2000" How can I extract the data included in this string object "x" in order to get the elements for the parameter vector called "alpha0", i.e. -0.638 0.4043 0.0467

Hi all, I'm trying to write a function that will search and extract from a long character string, but with a twist: I want to use the characters before and the characters after what I want to extract as reference points. For example, say I'm working with data entries that looks like this: Drink=Coffee:Location=Office:Time=Morning:Market=Flat

I'm running R 2.10.0 under Mac OS X 10.5.8; however, I don't think this is a Mac-specific problem. I have a very large (158,908 possible sentences, ca. 58 MB) plain text document d which I am trying to tokenize: t <- strapply(d, "\\w+", perl = T). I am encountering the following error: Error in base::gsub(pattern, rs, x, ...) : Calloc could not allocate (-1398215180 of

Hi R, A quick question: How do we find the number of words in a string? Example: C="Have a nice day" And the number of words should be 4. any built in function or?... Thanks, Shubha Shubha Karanth | Amba Research Ph +91 80 3980 8031 | Mob +91 94 4886 4510 Bangalore * Colombo * London * New York * San José * Singapore * www.ambaresearch.com This e-mail may contain

Are there packages that allow improved String and URL processing? E.g. extract parts of a URLs such as sub-domains, top-level domain, protocols (e.g. https, http, ftp), file type based on endings, check if a URL is valid or not, etc... I am currently only using split and paste. Are there better and more efficient ways to handle strings e.g. finding sub-strings or to do pattern matching? What

Un texte encapsul? et encod? dans un jeu de caract?res inconnu a ?t? nettoy?... Nom : non disponible URL : <https://stat.ethz.ch/pipermail/r-help/attachments/20100208/52a6d080/attachment.pl>

I have a table statement that returns the following: [10.839,10.841] (10.841,10.843] (10.843,10.846] (10.846,10.848] (10.848,10.85] 0 0 0 0 1 (10.85,10.852] (10.852,10.854] (10.854,10.857] (10.857,10.859] (10.859,10.861] 0 0 0 0 0 What I want to do is get the upper bound

Dear list memebers, I am stuck with using regular expressions. Imagine I have a vector of character strings like: test <- c('filename_1_def.pdf', 'filename_2_abc.pdf') How could I use regexpressions to extract only the 'def'/'abc' parts of these strings? Some try from my side yielded no results: testresults <-