similar to: Rd: pdf manual: package information not on first page

Displaying 20 results from an estimated 4000 matches similar to: "Rd: pdf manual: package information not on first page"

2009 Jul 06
3
Speed up code, profiling, optimization, lapply vs. loops
High everybody, currently I'm writinig a package that, for a given family of variance functions depending on a parameter theta, say, computes the extended quasi likelihood (eql) function for different values of theta. The computation involves a couple of calls of the 'glm' routine. What I'm doing now is to call 'lapply' for a list of theta values and a function, that
2009 Aug 19
1
Lattice: Drawing a single contour line with a negative value fails
Hi everybody, I want to add a single contourline to a levelplot. While everything works fine if the value at which the line should be drawn is positive, there is an error if the value is negative: library(lattice) my.panel <- function(..., at, contour=FALSE, labels=NULL) { panel.levelplot(..., at=at, contour=contour, labels=labels) panel.contourplot(..., contour=TRUE,
2010 Jun 21
2
list() assigning the same value to two items
Hi everybody, I'd like to have a list with two elements, where both elements have the same value: z <- list(a=1, b=1) If it happens, that I've to change the value, I've to assure that I change both. This is error prone. Hence, a better way to achieve this is to define: tmp <- 1 z <- list(a=tmp, b=tmp) Now, I'm wondering if it is possible to make this more compact: z
2012 Oct 31
1
aggregate.formula: formula from string
Dear all, I want to use aggregate.formula to conveniently summarize a data.frame. I have quiet some variables in the data.frame and thus I don't want to write all these names by hand, but instead create them on the fly. This approach has the advantage that if there will be even more columns in the data.frame I don't have to change the code. I've hence tried to construct a formula
2012 Jul 02
5
ggplot: dodge positions
Dear all, I want to get a series of boxplots (grouped by two factors) and I want to overlay the original observations and the following code does almost what I want: library(ggplot) ddf <- data.frame(x=factor(rep(LETTERS[1:4], each=30)), y = runif(120,0,10), grp = factor(rep(rep(1:3, 10), 4))) ggplot(ddf, aes(x, y, colour=grp)) + geom_boxplot() + geom_point() Yet the position of the points
2013 Nov 04
1
ggplot2: Add '+' operator for aes (uneval) objects
Dear all, Is there a reason, why there is no +-operator for aes (i.e. uneval) objects (as there is for themes and gg objects)? I had a couple of cases where such an operator would be useful, for instance to combine the result of aes and aes_string in functions. Any flaws with the following proposition: `+.uneval` <- function(e1, e2) { dup <- names(e1) %in% names(e2) if (any(dup)) {
2012 Dec 10
1
Sweep out control
Dear all, Assume that I have the following data structure: d <- expand.grid(subj=1:5, time=1:3, treatment=LETTERS[1:3]) d$value <- 10 ^ (as.numeric(d$treatment) + 1) + 10 * d$subj + d$time d$value2 <- 100000 + d$value where d$treatment == "C" stands for my control group. What I want to achieve now is to subtract the values corresponding to d$treatment == "C" from
2012 Jul 03
2
ggplot2: legend
Dear all, I produced the following graph with ggplot which is almost fine, yet I don't like that the legend for "Means" and "Observations" includes a line, though no line is used in the plot for those two (the line for "Overall Mean" on the other hand is wanted): library(ggplot2) ddf <- data.frame(x = factor(rep(LETTERS[1:2], 5)), y = rnorm(10)) p <-
2010 Dec 13
1
predict.lm[e] with formula passed as a variable
Dear all, In a function I paste a string and convert it to a formula which I pass to lm[e]. The idea is to write a function which takes the name of the response variable and the explanatory variable and the data frame as an argument and calculates an lm[e]. (see example below) This works fine, but if I want to make a prediction on this model, R complains that the object holding the formula
2011 Jan 05
1
Minimum of an ordered factor
Hi everybody, Is there a particular reason, why this code does not work as intended: z <- factor(LETTERS[1:3], ordered = TRUE) u <- 4:6 min(z[u > 4]) Error in Summary.factor(2:3, na.rm = FALSE) : min not meaningful for factors I agree that min is indeed not meaningful for not ordered factors, but it makes sense for ordered factors. Especially since z[3] <
2010 Aug 30
1
lattice: limits in reversed order with relation="same"
Hi everybody, I want an x-axis which has xlim=c(max, min) rather than xlim=c(min, max) in order to reflect the type of the process (cooling): library(lattice) myprepanel <- function(x,y,...) list(xlim=rev(range(x))) x <- rep(1:10, 100) z <- factor(sample(10, 1000, T)) y <- rnorm(1000, x, as.numeric(z)) xyplot(y~x|z, scales=list(x="free"), prepanel=myprepanel) This works
2011 Oct 21
1
droplevels: drops contrasts as well
Dear all, Today I figured out that there is a neat function called droplevels, which, well, drops unused levels in a data frame. I tried the function with some of my data sets and it turned out that not only the unused levels were dropped but also the contrasts I set via "C". I had a look into the code, and this behaviour arises from the fact that droplevels uses simply factor to drop
2010 Aug 23
2
Sum a list of tables
Hi all, In R it is possible to sum tables: > (a <- table(rep(1:3, sample(10,3)))) 1 2 3 2 5 7 > a+a 1 2 3 4 10 14 Now suppose that I have a list of tables, where each table counts the same things > k <- list(a,a,a) How can I sum all tables in k? > do.call(sum, k) [1] 42 does not work since it sums over each table. > do.call(`+`, list(a,a)) 1 2 3 4 10
2010 May 04
1
Lazy evaluation in function call
Hi everybody, how is it possible to refer to an argument passed to a function in the function call? What I like to do, is something like f <- function(x,y) x+y f(2, x) # should give 4 The problem is of course that x is only known inside the function. Of course I could specify something like f(z<-2,z) but I'm just curious whether it is possible to use a fancy combination of eval,
2010 Jul 12
1
Checking formulae: are lower order terms included
Dear all, I have a very rudimental function which takes a vector of terms and returns a list of all possible models which can be made using the given terms. For example for the set c("1", "x", "y", "x:y") I'd get: ~ 1 ~ x ~ y ~ x:y ~ 1 + x ~ 1 + y ~ 1 + x:y ~ x + y ~ x + x:y ~ y + x:y ~ 1 + x + y ~ 1 + x + x:y ~ 1 + y + x:y ~ x + y + x:y ~ 1 + x + y +
2010 Jul 20
1
Telling R CMD check where to find libraries
Hello everybody, Currently I'm developing a library, which uses some functions from another package (namely plotrix). Consequently, I listed this dependency in the DESCRIPTION file. When I try to run "R CMD check mypackage", the check fails, for the library plotrix cannot be found on the system. As far as I understood "R CMD check" uses --vanilla implicitly, thus, no
2010 Jun 11
1
CHM help does not find help docs in package stats
Hi all, currently I'm working on an R package bundling some frequently used functions. When I load my package and type ?one_of_my_functions I get the particular help file. If I try to get help on another function, which is part of package stats (prcomp say), I get "This program cannot display the webpage". A help on ?mean does, however, work as it opens a new window showing the
2012 Feb 13
1
Overwrite S3 methond from base package
Dear all, I am developing a package, which bundles my most frequently used functions. One of those is a modified version of droplevels from the base package (basically, it preserves any contrast function which was used to create the factor, contrast matrices are not kept, for they could be wrong if a level is dropped). In my NAMESPACE file I've the following directives, which should export
2011 Aug 02
1
lattice: index plot
Dear all, How can I make an index plot with lattice, that is plotting a vector simply against its particular index in the vector, i.e. something similar to y <- rnorm(10) plot(y) I don't want to specify the x's manually, as this could become cumbersome when having multiple panels. I tried something like library(lattice) mp <- function(x, y, ...) { x <- 1:length(y)
2011 Mar 08
1
Replacing values in a data.frame/matrix
Hi all, Suppose we have the following matrix m <- matrix(c(1,2,3,2,1,3,3,1,2), ncol = 3, byrow=T) where in each row each number occurs only once. I'd like to define a permutation, e.g. 1 -> 2, 2 -> 1, 3 -> 3 and apply it to the matrix. Thus, the following matrix should result: m.perm <- matrix(c(2,1,3,1,2,3,3,2,1), ncol = 3, byrow=T) i.e. each 1 should map to 2 and vice