similar to: Bug in base function sample ( ) (PR#13727)

Dear All, Has anyone tried to use this plug-in? Since I am running R-2.9.1 it will not even let me install it. Further, since I am running Windows I cannot use the R provided R-2.7.0 Linux installation file from the archive (tried to install it through cygwin and it was a mess). Suggestions? Ideas? Has anybody used this plug-in? Michael -- Michael Chajewski, M.A. Department of Psychology

Dear mailing list I have a data that have 20,000 rows and 20 columns. Io wonted to extract the 10th row only. Example the 10th, 20th, 30th 40th…..20000 th. can you please help me how do I do that.Than kyou. Example is below. Inpute: AG GG GG AG CC CC CC CC CT CC CT CT GG GG GG GG CC CC CC CC GG GG GG GG CC CC CC CC GG CG CG GG GG GG GG GG *CC CC CC CC* AA AG AG AA AA AA AA AA GG AG AG GG GG AG AG

Dear All I have a data.frame like that: structure(list(name = c("Gga_rs10722041", "Gga_rs10722249", "Gga_rs10722565", "Gga_rs10723082", "Gga_rs10723993", "Gga_rs10724555", "Gga_rs10726238", "Gga_rs10726461", "Gga_rs10726774", "Gga_rs10726967", "Gga_rs10727581", "Gga_rs10728004",

Hi, I am trying to split multiple columns. One column works just fine, but I want to do it for multiple columns??? Example > a ID V2 V3 V4 V5 V6 V7 V8 V9 V10 1 PBBA0644 -- GG AA -- AA -- AA GG GG 2 PBBA1010 -- GG AA -- AA -- AA GG GG 3 0127ATPR -- GG AA -- AA -- AA GG GG 4 0128EHAB -- GG AA -- AG -- AA AG GG 5 PBBA0829 -- GG AA -- AA -- AA GG AG

Dear list, I am trying to evaluate how many elements in a vector equal a certain value. The vectors are the columns of a data.frame, read in using read.table(): > dim(data) [1] 2600 742 > data[1:5,1:5] SNP001 SNP002 SNP003 SNP004 SNP005 1 GG AA TT TT GG 2 GG AA TC TT GG 3 GG AC CC TT GG 4 AG AA TT TT GG 5

I HAVE A VERY BIG DATA OF 67 COLMS AND 25000 ROWS AND WOULD LIKE TO TRANSPOSE IT THE R HELP WAS NOT ENOUGH INFORMATION BECOUSE I AM NOT A PROGRAMMER AND FIRST TIME R USER. SO CAN YOU GIVE SOME HINTS OF CODING, AA TT GG GG CC AA TT GG GG CC AA TT GG GG CC AA TT GG GG CC AA TT GG GG CC TO AA AA AA AA AA TT TT TT TT TT GG GG GG GG GG GG GG GG GG GG CC CC CC CC CC [[alternative HTML

The documentation for assignment says: In all the assignment operator expressions, 'x' can be a name or an expression defining a part of an object to be replaced (e.g., 'z[[1]]'). A syntactic name does not need to be quoted, though it can be (preferably by backticks). But the implementation allows assignment to a character string (i.e. not a name), which it

Hi, I'm trying to set a rule to dial out through multiple Zap groups so that, say, g0 is the cheaper POTS lines group and must be used first. However, if g0 is busy or disconnected then try dialing out g1. My g0 group is made up of 4 analog lines connected to a 4-FXO card. I disconnected the RJ-11 wires from the FXO card to simulate a line disconnection. So theoretically all calls should

Dear R users, I am trying to fill in arrays (5 different according to distinct "id") from objects produced from arbitrary data set below. a <-

Dear Contributors I have a problem with the collection of data from the results of a test. I need to perform a comparative test over groups of data , recall the value of the pvalue and create a table. My problem is in the way to replicate the analysis over and over again over subsets of data according to a condition. I have this database, called y: gg t1 t2 d 40 1 1

I was going through the example below which is taken from the example section in the R documentation for accessing the function call stack. I am confused and I have 3 questions that I was hoping someone could answer. 1) why is y equal to zero even though the call was done with gg(3) 2) what does parents are 0,1,2,0,4,5,6,7 mean ? I understand what a parent frame is but how do the #'s relate

Hi, There are some generated Sparc assembly code like this: main: ! @main ! BB#0: save %sp, -112, %sp sethi 0, %l0 or %g0, 5, %l1 st %l0, [%fp+-4] st %l1, [%fp+-8] st %l1, [%fp+-12] sethi %hi(.L.str), %l1 ld [%fp+-8], %o1 add %l1, %lo(.L.str), %l1 or %g0, %l1, %o0 call printf nop ld [%fp+-12], %o2 ld [%fp+-8], %l2 sethi %hi(.L.strQ521), %l3 add

I have a more complicated function I am trying to write, but I run in to a problem when I want to add something to the plot from more than one data set while simultaneously controlling the appearance of the additional layer. # Toy data: foo <- data.frame ( x = 1:4, y = 4:1 , membership = c( "A", "A", "B", "B" ) ) bar <- data.frame ( x = 1:4 + 1 , y

Hi, I have a large dataset on which I would like to do the following: x<-data.frame(id=c(1,2,3), snp1=c("AA","GG", "AG"),snp2=c("GG","AG","GG"),snp3=c("GG","AG","AA")) > x id snp1 snp2 snp3 1 1 AA GG GG 2 2 GG AG AG 3 3 AG GG AA And then

I'm switching from OpenLDAP to the newly released Fedora Directory Server (formely known as the Netscape Directory Server) as a LDAP backend for my Samba domain. I'm now faced with a problem regarding how Fedora DS handles the userPassword field. Unlike OpenLDAP it encodes it in base64 so instead of reading userPassword: {SSHA}0lP+r3Z1NVan7Caf4CG9oSgnTbQRrv/p it reads: userPassword::

Dear all, In order to be sure I understand glmm correctly, I try to reproduce by hand a simple result. Here is a reproducible code. The questions are in _________________ Of course I have tried to find the solution using internet but I was not able to find a solution. I have also tried to follow glmer but it is very complicated code! Thanks for any help. Marc # Generate set of df with nb

I am trying to create plots within a for loop and output them to a pdf. Here is a working example using plot: gg <- data.frame(datadate=1:4, spread=5:8) pdf() for (i in 1:3) { plot(gg$datadate, gg$spread, main=i) } dev.off() I am trying to learn more about ggplot2 so I try a slight modification and it doesn't work. Anyone

Nick, Do you happen to know why the version reported in 'dwarfdump --eh-frame' for object files now differs when compiled with and without -g? The test used in FSF gcc's configure produces a diff of.. % diff -u conftest.o.g.stripped.dwarfdump conftest.o.g0.stripped.dwarfdump --- conftest.o.g.stripped.dwarfdump 2015-04-10 21:43:15.000000000 -0400 +++

I'm new to R (previously used SAS primarily) and I have a genetics data frame consisting of genotypes for each of 300+ subjects (ID1, ID2, ID3, ...) at 3000+ genetic locations (SNP1, SNP2, SNP3...). A small subset of the data is shown below: SNP_ID SNP1 SNP2 SNP3 SNP4 Maj_Allele C G C A Min_Allele T A T G ID1 CC GG CT AA ID2 CC GG CC AA ID3 CC GG nc AA

Hello, I have a question regarding competing risk regression using cmprsk package (function crr()). I am using R2.9.1. How can I do to assess the effect of qualitative predictor (gg) with more than two categories (a,b,c) categorie c is the reference category. See above results, gg is considered like a ordered predictor ! Thank you for your help Jan > # simulated data to test > set.seed(10)